PLEASE explain how to do this question step by tspe i am very confused! thank you! You have three independent mutant alleles in the Drosophila gene no legs (nlg): nlg1, nlg2, and nlg3. You assay the phenotype of Drosophila, which is an insect, that are heterozygous for the three allele (heterozygous for a wild-type and a mutant allele), and that are homozygous for the three alleles. Allele nlg1 nlg2 nlg3 heterozygous Wild-type Four pairs of legs Wild-type homozygous Stumpy legs Five pairs of legs No legs nlg1 is a ___X___ allele, nlg2 is a ___Y___ allele, and nlg3 is a ___Z___ allele. X Y Z A Gain of function Null Hypomorphic B Hypomorphic Gain of function Null C Null Gain of function Hypomorphic D Null Hypomorphic Gain of function E Hypomorphic Null Gain of function Referencing the table above, select the correct answer: 1 : A 2 : B 3 : C 4 : D 5 : E Correct answer is B

PLEASE explain how to do this question step by tspe i am very confused! thank you! You have three independent mutant alleles in the Drosophila gene no legs (nlg): nlg1, nlg2, and nlg3. You assay the phenotype of Drosophila, which is an insect, that are heterozygous for the three allele (heterozygous for a wild-type and a mutant allele), and that are homozygous for the three alleles. Allele nlg1 nlg2 nlg3 heterozygous Wild-type Four pairs of legs Wild-type homozygous Stumpy legs Five pairs of legs No legs nlg1 is a _X_ allele, nlg2 is a _Y_ allele, and nlg3 is a _Z_ allele. X Y Z A Gain of function Null Hypomorphic B Hypomorphic Gain of function Null C Null Gain of function Hypomorphic D Null Hypomorphic Gain of function E Hypomorphic Null Gain of function Referencing the table above, select the correct answer: 1 : A 2 : B 3 : C 4 : D 5 : E Correct answer is B

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 3CS: A couple was referred for genetic counseling because they wanted to know the chances of having a...

See similar textbooks

Referencing the table above, select the correct answer:

1 : A

2 : B

3 : C

4 : D

5 : E

Correct answer is B

Definition Definition Observable physical traits or characteristics of an organism, which are determined by its genetic makeup (genotype) as well as environmental factors. These traits can include anything from eye color or height to behavior or disease susceptibility. Understanding an organism's phenotype is important in fields such as genetics, medicine, and ecology.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduction

VIEW

Step 2: Evaluate sort of each allele by comparing the phenotype of the heterozygous and homozygous flies

VIEW

Step 3: Explanation of incorrect options

VIEW

Solution

VIEW

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.

Similar questions

Let us practice it again! Analyze the pedigree below to answer the questions that follow. Huntington's disease a disorder in which nerve cells waste away, or disintegrate, is passed down through families. certain parts of the brain Huntington's diseate llustration ereated in htps://pregenygenetion.com/ 1. What members of the family above are affected with the Huntington's disease? 2. Tnere are no carriers ior Huntungton's disease you either have it or you do not. Is Huntington's disease caused-by a dominant or recessive trait? 3. Identify the genotypes of the following individuals using the pedigree above. (homozygous dominant, homozygous recessive, heterozygous). I- 1 II -1: II -3: III - 4 : 4. How many children did individuals I-1 and I-2 have? 5. How many girls did II-1 and II-2 have? How many have Huntington's Disease? 6. How are individuals III-2 and II-4 related? I-2 and III-5?
Question:- 3. Wild type Drosophila has red eyes and gray body*. Autosomal recessive mutations sepia (se) and ebony (e) modify the eye and body color, respectively. What kind of a cross (or crosses) can you set up to determine whether the two genes are linked? You have several lines to choose from: a pure-breeding wild type line (where alleles for both, sepia and ebony are wild type), a double homozygous recessive line, a pure breeding sepia mutant line and a pure breeding ebony mutant line. You don’t have to use all of them. (a) Write down the cross (or crosses, if necessary) which will allow you to determine linkage; include genotypes of both crossed individuals (b) What kind of results (offspring) do you expect if the two genes are linked? (c) What kind of results (offspring) do you expect if the two genes are not linked? For (b) and (c), state the phenotypes, genotypes and numbers.
Hi! I would love to get some help on the box-and arrow model question! :) A male individual who is XYSRY has the following genotype for the AMH gene on chromosome 19: AMH1 AMH2. The AMH1 allele codes for a protein that is capable of binding to the receptor for AMH. The AMH2 allele codes for a protein that is unable to bind with the receptor for AMH. Based on your understanding of biology, what is the likely phenotype of this individual? Humans have 23 pairs of chromosomes of which 22 pairs are autosomal and the 23rd pair is sex-linked.In a human female, the sex chromosome pair is represented as XX, whereas, in a human male, it is represented as XY.AMH is an anti-Mullerin hormone produced by the Sertoli cells in males and helps in the development of the sex organs. Each pair of chromosomes has a pair of genes called alleles at the same loci representing a single character. Each gene of an allele represents the expression of the character.A gene can either show expression or…
Use keyboard only to enter your answer below. ALL WORKING MUST BE SHOWN Problem 1) mutation in a gene on chromosome 15 that codes for an enzyme. The disease is an inherited autosomal recessive condition which is Tay-Sachs disease is caused by loss of function found amongst Ashkenazi Jews of Central European origin. In this population, 3 in 5,200 children are born with the disease. What proportion of the population are carriers (heterozygotes) for this disease?
QUESTION:- In Drosophila, assume that the gene for scute bristles (s) is located at map position 0.0 and that the gene for ruby eyes (r) is at position 25.0. Both genes are located on the X chromosome and are recessive to their wild-type alleles. A cross is made between scute-bristled females and ruby-eyed males. Phenotypically wild-type F1 females were then mated to homozygous double mutant males, and 1000 offspring were produced. Give the phenotypes and frequencies expected..
You are to discover the chromosomal location (autosomal or X linked) and mode of inheritance for two new fly mutations coughrotato (cp) and happyhour, (bb) The homozygous couchpotato (cpcp) phenotype is (sedentary) an extreme lack of activity The homozygous happyhour (hhhh) can drink any other fly under the table so phenotype (drinker) PARENTS Cross Male double homozygous mutants cp hh with Female wild wild CP HH are to be crossed BUT FIRST you don't know if either gene is on the X chromosome Parental diploid genotypes could be: male çpcphbbh female CPCPHHHH if Both genes autosomal or Male XcpYhbhh female XCPXCPHHHH if cp on the X chromosome and bh autosomal or Male cpcpXhhY female CPCPXHHXHH if hh on the X chromosome and cp autosomal What are the female and male PARENTAL GAMETE GENOTYPES for the above parental crosses if: a) Both genes were autosomal ((REMEMBER BOTH GENDER HAVE ONE GAMETE GENO) b) cp gene on the X chromosome and hh autosomal (REMEMBER MALES WITH HAVE 2 GAMETE GENO) c)…
Topic: Gene Locus Height in gryphons is determined by a single locus. You cross a two 9' tall gryphons and get 1/4 10'; 1/2 9' and 1/4 8' tall gryphons. If you across two 7' tall gryphons you get 1/4 8', 1/2 7'; 1/4 6' tall gryphons. pls kindly help to explanation: why In gryphons, alleles of the height lous are semidominant and form an allelic series. A.
Dihybrid Cross Problem Set Problem 13: AaBb dihybrid cross involving epistasis. Two unlinked loci effect mouse hair color. AA or Aa mice are agouti. Mice with genotype aa are albino because all pigment production is blocked. regardless of the phenotype at the second locus. At the second locus, the B allele (agouti coat) is dominant to the b allele (black coat). What would be the result of a cross between two agouti mice of genotype AaBb? A. 4 agouti: 4 black: 8 albino B. 9 agouti: 3 black: 3 albino: 1 grey C. 9 agouti: 3 black: 4 albino D. 8 agouti: 4 black: 4 albino
Miniature wings, X in Drosophila melanogaster result from an X-linked allele that is recessive to the allele for long wings, 9 + X. Match the genotypes for each parent in the crosses. Male parent phenotye long miniature miniature 111 long long Female parent phenotype long long long miniature long m m X X Male offspring phenotypes 231 long, 250 miniature 610 long 410 long, 417 miniature 753 miniature 625 long m X Y Female offspring phenotypes 560 long 632 long 412 long, 415 miniature 761 long 630 long Answer Bank ++ X X Male parent genotype + X Y Female parent genotype + X X m 00
Answer ALL questions in the foolscap paper sheets. 1. In the fruit fly, Drosophila melanogaster, the gene for eye colour is sex linked. The allele for the red eve is dominant to the allele for white eye. In an experiment, a red-eyed female was crossed with a white-eyed male. Two fruit flies of the F1 generation were then crossed. The following F2 phenotypes were produced: red- eyed females red-eyed males white-eyed males 95 49 56 By using suitable symbols, draw a genetic cross diagram to explain the results.
Please answer fast Gene B codes for purple-colored flowers while the recessive form of the gene (b) results in pink-colored flowers. Another gene, A, when dominant, activates the transcription of gene B, resulting in purple or pink-colored flowers, while the recessive version of aa, results in white-colored flowers. A homozygous purple-colored flowering plant was crossed with a fully homozygous recessive white-colored flowering plant. The F1 flowering plants were self-crossed to generate the F2 generation. Determine the phenotypes and genotypes for each generation. Explain.
The purpose of this assignment is to understand the principles of Mendelian and human genetics and the structure of DNA and how genetic code is converted to protein. After completing the three Unit 6 Labs on Connect (above), apply critical thinking to answer the following:1. Fruit Flies and Genetics Research: Imagine you are working in a genetics lab with the fruit fly Drosophila melanogaster, a model organism for genetics research. You want to determine whether a trait you have discovered in fruit flies is dominant or recessive.• Explain how you would design an experiment to answer this question.• Predict what types of outcomes are possible. Which would indicate that the trait is dominant? Which would indicate that it is recessive?2. Model Genetic Organisms: Why are fruit flies considered a model genetic organism? Would humans fit this description?

SEE MORE QUESTIONS

Recommended textbooks for you

Human Heredity: Principles and Issues (MindTap Co…

Biology

ISBN:

9781305251052

Author:

Michael Cummings

Publisher:

Cengage Learning

Human Heredity: Principles and Issues (MindTap Co…

Biology

ISBN:

9781305251052

Author:

Michael Cummings

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS

GET THE APP

About FAQ Academic Integrity Sitemap Document Sitemap

Contact Bartleby Contact Research (Essays)High School Textbooks Literature Guides Concept Explainers by Subject Essay Help Mobile App

GET THE APP

Privacy

Your CA Privacy Rights

Your NV Privacy Rights

About Ads

Manage My Data

bartleby, a Learneo, Inc. business

Allele	nlg¹	nlg²	nlg³
heterozygous	Wild-type	Four pairs of legs	Wild-type
homozygous	Stumpy legs	Five pairs of legs	No legs

	X	Y	Z
A	Gain of function	Null	Hypomorphic
B	Hypomorphic	Gain of function	Null
C	Null	Gain of function	Hypomorphic
D	Null	Hypomorphic	Gain of function
E	Hypomorphic	Null	Gain of function