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Q: If the 10-9 plate was counted to have 155 colonies on it, would the CFU/mL be 1.55*1011? If not,…
A: CFU Colony forming unit it a method to calculate the number of microorganisms in a culture media.
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Q: What special precautions must be taken when using the oil immersion (100x) objective?
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Q: How many bacteria would be in 1ml of the sample if you counted 134 colonies on the 1:1,000 dilution?
A:
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Q: You dilute 1 mL of bacterial culture with 99 mL of water. What is the resulting dilution factor?
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How to count the number of colonies forming units per milliliter (CFUs per ml) of the sample?
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- Based on the image below, select the correct statement. Complex II QH₂ Q- 10 2 HO 2 HO Fe-S (2.8 FADH₂ FAD- Succinate Fumarate https://canvas.uts.edu.au/assessment questions/356986/files/1562694/download? 2e verifier-eUTT3hYal2YYTWlywV8TIFA3USmzCsM52jECmvTo O Succinate is reduced to fumarate O Succinate is oxidised to FAD O The Fe-S center shuffles electrons from FAD to ubiquinone (Q) O The Fe-S center shuffles electrons from FADH2 to ubiquinone (Q) The Fe-S center shuffles electrons from FADH2 to ubiquinonol (QH2) W 88 16°CKCI for injection contains 40 mEq in 20 mL. An order requires 15 mEq, how many mL are needed?regular set Clo drepps la) The lv is In fusing 125 drups Imin with ar How long will It taire to Infuse 25oml?
- Given that the normal range for serum protein is about 7 g/100ml and albumin is about 4 g/100ml, what clinical conclusions can you draw from the following samples A-C? If samples are not normal, what protein fraction is increased/decreased and with what disease is this protein pattern likely to be associated? Sample A: total protein = 14 g/100mlalbumin= 8 g/100 ml Sample B:total protein = 5.8 g/100ml albumin = 4 g/100 ml Sample C:total protein = 3.5 g/100mlalbumin = 2g/100 mlEcoRI 4359 Aatll - Zral 4284 Bei 4209 BsrBl 4205 Clal - BspDI 23 Hindill 29 EcoRV 185 Bmtl - Nhel 229 Sspl 4168 Earl 4155 Acul 4048 Xmnl 3961 Hincll 3905 Scal 3844 BamH 375 Sgrl 409 Banll 471 Banll 485 Вы 3787 Bsl 3759 Bgl 528 Sphl 562 EcoNI 622 Sal - Acct - Hincll 651 Pvul 3733 Pstl 3607 Bartl 3602 Pshl 712 Asel 3537 Eagl 909 Bell 949 Bsal 3433 BarDI 3420 Nrul 972 PBR322 4,361 bp BstAPI 1045 Ahdi 3361 BspMI - Bfual 1063 PAMI 1315 Bsml 1353 PAMI 1364 Acul 3000 Ori Styl 1369 Aval - BsoBl 1425 PpuMI 1438 Msel 1444 Bigl 1447 Ppu 1480 AlwNI 2884 Bell 2777 kI 2682 rop Drdi 2575 Bsgl 1650 BspEI 1664 Pcil - Afl 2473 rBl 2404 Earl 2351 Bspol - Sapl 2350 Ndel 2295 BstAPI 2291 Bsaß 1668 Xmat 2029 Pvull 2064 BsmBI 2122 Dndl 2162 BstZ171 - Acct 2244 Bsal 2225 TthI- PI 2217 Figure 1 If your gene of interest was inserted at the Sphl restriction site of the plasmid illustrated in Figure 1, describe the screening process to select the positive recombinants.The order is to give 45 mEq. The dosage available is 30 mEq in 15 mL. How many mL do you give?
- What is the cause for false negative for protein in blood test?In order to improve contract during X-ray diagnostics of soft tissues, contrast agents are used. For example, the stomach and intestines are filled with barium sulphate ВаSO4. Compare mass attenuation coefficients for soft tissues and for barium sulphate.What is the dose in mSv for: (a) a 0.1 Gy x-ray?
- What is the cause for false positive for protein in blood test?The growth of hybridoma cells, producing a monoclonal antibody, was monitored for 4 and a half days, and the results obtained are listed in the following table: time (days) nº cel/mL x 106 ln nº cel 0 0,45 -0,79851 0,2 0,52 -0,65393 0,5 0,65 -0,43078 1 0,81 -0,21072 1,5 1,22 0,198851 2 1,77 0,57098 2,5 2,13 0,756122 3 3,55 1,266948 3,5 4,02 1,391282 4 3,77 1,327075 4,5 2,2 0,788457 What is the maximum specific rate (µmax) of growth of these cells per day? what is the doubling time of these cells (in days)?