Here’s a Ramachandran plot. Give the dihedral angles--phi and psi--that are characteristic of a left handed helix.
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Here’s a Ramachandran plot. Give the dihedral angles--phi and psi--that are characteristic of a left handed helix.
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- TAC-ATA-ACG-CGA-CAA-CTA-AAA-ACT Write the amino acid sequence of the protein that would be formed by translating this plece of DNA. You can use the three letter abbreviations for the amino acid in each box, do not use the name of the full amino acids, Use the abbrevlation of the amino adid exactly as Itswritten in the table (including the appropriate capltalizations For example it your answer for amino acid 1 is"Methionine" you would write MET in the box (not Met or met) Second Later UUU UUUC Phe UCU UAU Ser UAC UAA UAG Tyr UGU Cys U Leu UCA ucG UGC Stop uGA Beop UUG Step UGG Trp G Cuu C cuC CUA CUG CU Leu Coc CCA CG CAU Pro cGu CAC CAA CAG His CGC Arg CGA CGG 1st 3rd letter AUU A AUG AUA AUG ACU le AAU AAC AGU ACC Asn Ser U leBer ACC ACA Mct ACG The AAA AAG ACA Lys AGG Arg acu Val GCC GCA GCG GAU GAC GAA GAG GOU GGC GGA GGG Arp G GUC GUA GUG Ala Gly Glu Seovence of the protein, 1st amino acid. 2nd arnino acid: 3rd amino acid: 4th amino acid Sth amino acid: 6th amino acid: 7th amino…wol for Frayon Elolog - Meet - cha-gX-m sc Jupiter Ed G Which orgerell= A sample of DNA is collected from an organism. It is analyzed and determined that 20% of the DNA is made up of the base adenine. Based on this information, which of the following correctly lists the amounts of the three. remaining bases for this sample? 10% cytosine, 30% thymine, 40% guanine O 20% cytosine, 20% thymine, 20% guanine 30% cytosine, 30% thymine, 20% guanine 30% cytosine, 20% thymine, 30% guanine p. 5 of 31Genetic Code-Reference Second Letter First Letter C Third Letter UAU] UACS **UAA Stop UGU] Cys UGC U UUU Phe UUC UCU Туг UCC U Ser UUA) Leu UUG **UGA Stop UGG Trp UCA UCG **UAG Stop CUU CCU CAU) CGU His CACJ CAA) CUC CCC CGC Leu Pro Arg CUA ССА CGA A Gln CUG CCG CAGJ CGG AAU] AGUSer U AUU ACU AACAsn AAA Lys AUC Ile ACC AGC C Thr AGA] Arg AUA ACА AAGJLYS GAU] GACASP *AUG Met/Start ACG AGG U GUU GCU GGU Asp GUC GCC GGC Val Ala Gly GAA) Glu GAGJ GUA GCA GGA GUG GCG GGG
- 134 LABORATORY Size of the Cell U22T RAJUBAV RO OJA Shape of the Nucleus 916 91032 Degree of Chromatin Condensation Presence or Absence of Nucleoli Cytoplasmic Staining Blood Cells Presence of Cytoplasmic Granules Cytologic/Histologie 18: or cellule Bone Marrow Cells of the develo eveloping cells noil Identi 0105' G-A-T-A-с-А-А-с-А-т-G-6-A-с-А-т-G-А-с-т3 What would be the first 3 bases in the 5' end of the complementary strand? Indicate the base sequence and the direction of synthesis of a 3-nucleotide RNA primer. Indicate the base sequence and the direction of synthesis of a 5-nucleotide Okazaki fragment (include a 3 nucleotide RNA primer, a total of 8 bases in the sequence). Assuming the presence of the complementary strand, what is the percentage composition of the polymer with respect to the A-T base pair and G-C base pair?āiglho älimill JS - alimi 9 Which of the following is found in a molecule of DNA? 1 ribose phosphate groups deoxyribose nitrogneous bases Show
- Mutated DNA Sequence #3 T A C A C C T T A G C G A C G A C T … What’s the mRNA sequence? (Circle the change) What will be the amino acid sequence? Will there likely be effects? What type of mutation is this? ________________________________ Mutated DNA Sequence #4 T A C A C C T T G G C G A C T A C T … What’s the mRNA sequence? (Circle the change) What will be the amino acid sequence? Will there likely be effects? What type of mutation is this? ______________________________11.5 A A Aa-AE-E-¹5- U - abe X₂ X² A-ay-A- Font Ulla Unigriffin DNA: mRNA: amino acids: traits: DNA: traits: mRNA: amino acids: · DNA: mRNA: to search #N O E Et CE- Paragraph $ 15 Ser 1. CAT AGG GAG | CAA GGG TGA CTT TTT | AAT AAT GAC GGG | A E ALT | CAA TTG TTA CGG | AAA AGA CCC | GCC ATA ACA TTT | % STP | CAC CGT CGA | GTA GTA | AGA GGG CAT | TTG TAA GGA GGG GGG TGT | 16 AaBbCcDc AaBbCcl AaBbCcL Aa BbCcDc 1 Normal 1 Body Text 1 List Para... 1 No Spac... W] Tyr 17 Val & 7 Gly E CO OM no num lk T Aa Bb Cc 1 Table Pa (p)) Styles 12 P11:29 Protein 6-10092015113530.pdf https:api.schoology.comv1attachment169963838... Name Class Date 2. How are enzymes involved in this process? 3. hаppens anzips"? 4. Why is it important that exact copies of DNA be made? 5. Suppose that a sequence of one DNA strand is T-A-C-A-A-C-G-T-G. What is the corresponding sequence on the other strand? E Concept Mapping The construction of and theory behind concept mapping are discussed on pages vil-ix in the front of this Study Guide. Read those pages carefully. Then consider the concepts presented in Section 7-1 and how you would organize them into a concept i page 74. Notice that the concept map has been started for you. Add the key Now look at the concept map for Chapter 7 on concepts you are important Secti When you have finished the chapter, you will have a completed concept map. 69 1 of 1
- Transposons in bacterial genomes can carry genes,including those conferring ________ resistanceposition position (5' end) position (3' end) UUU Phe - F UUC Phe UAU Tyr Y. UAC Tyr UAA Stop UGU Cys UGC Cys UGA Stop UGG Trp UCU Ser UCC Ser U UUA Leu UUG Leu UCA Ser UCG Ser UAG Stop W 輔 CAU His CGU Arg CGC Arg CGA Arg CGG Arg CUU Leu CCU Pro CUC Leu CCC Pro P. CCA Pro CÁC His CỦA Leu CAA Gln CUG Leu CCG Pro CAG GIn AUU lle ACU Thr AAU Asn AGU Ser AUC lle ACC Thr -T ACA Thr AAC Asn_ AGC Ser AGA Arg AGG Arg A AUA lle AAA Lys EK AAG Lys AUG Met ACG Thr GUU Val GGU Gly GGC Gly GGA Gly GGG Gly GAU Asp D GAC Asp GCU Ala GUC Val -V GUA Val GCC Ala GCA Ala GCG Ala G - A GAA Glu FE GAG Glu GUG Val Nonpolar Polar Basic Acidic Stop codon Table 4.1 Biology: How Life Works, Third Edition © 2019 W. H. Freeman and Company Consider the DNA sequence–3'-CACTGGTAGCGA–5', • What is the sequence of the messenger RNA sequence that is transcribed from this DNA sequence? (Indicate the 5' and 3' ends of the RNA molecule.) • Consult the genetic code that is shown above. What is the amino acid sequence of the…5' UGG CAA UCC UAC GAU 3' - 1. Here is the MRNA sequence from a section of a gene (it is the middle of the sequence, so it has no AUG). What is the template sequence of this gene? - 2. Are any of these codons in the MRNA non-degenerate? If so, indicate which one. e 3. 4 a) Translate this mRNA section. Give the 3 letter codes for the amino acids. b) Indicate on the peptide which is the C terminus and which is the N terminus. e 4. Is it possible for a single base pair substitution to cause a truncation in this peptide? If so, e explain how. e 5. Write out the sequence of the anticodon in the tRNA that would bind to the fourth codon in the e MRNA. e 6. Write out a possible miRNA that could regulate the expression of this gene
