Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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- You have the following DNA coding sequence of a wild-type allele: 5’-ATG TTC CAG CTA GAT GAT ATG CTG GTA ATT GGG GAA CGC GCG CGG TAA-3’ For each of the following mutations: A. State whether the mutation is missense, nonsense, frameshift, or silent. B. Write the codon change that occurs for the missense, nonsense, and silent mutations (ex. GAA -- GAT). C. For frameshift mutations, write out the entire mutant sequence with each codon clearly indicated (if the frameshift creates a new stop codon, end the sequence at the new stop). Using the wild type DNA sequence above as a guide : Write the amino acid sequence of the mutants. Mutant 1: transition at nucleotide 23 Mutant 2: T --> G transversion at nucleotide 29 Mutant 3: an insertion of “A” after nucleotide 14 Mutant 4: transition at nucleotide 7 Mutant 5: An insertion of GG after nucleotide 40 Mutant 6: transition at nucleotide 15 Mutant 7: a deletion of nucleotide 25arrow_forwardYou are a researcher studying a gene you think is responsible for super human strength. You call the gene HULK1. Below is the ORF of this gene from a normal strength individual (with nucleotide position indicated above). Use this sequence to answer the following questions. 1 10 20 30 39 5'- ATG TCA AAG GAC ATT CGC TGT GGG CTC AGA CTA TCA TAA -3' You design primers (6nt each) to amplify this entire sequence. Which primer set below did you use? O a. 5-TTATGA-3' and 5'-TGACAT-3' Ob.5'-TGACAT-3 and 5'-TCATAA-3' Oc 5'-ATGTCA-3' and 5'-TCATAA-3' Od. 5'-ATGTCA-3' and 5'-TTATGA-3' Oe. 5'-ATGTCA-3' and 5'-TGACAT-3'arrow_forward1st choices: promoter, 3’ UTR, exon 1, 5’UTR 2nd: Met, Lys, Arg, Leu, lle 3rd: GCC, AUC, UGA, GAAarrow_forward
- A. Diagram a short single strand of DNA 5’ -AA-GG- 3’. Show the chemical structure of the phosphoribosyl backbone and the attachment point for nucleotides added as “A” or “G”. B. Diagram the product of digestion was a restriction enzyme to cut this sequence between the A and G.arrow_forwardBoth question correlate with each otherarrow_forwardPlease in detail, what the picture attached representsarrow_forward
- Below is a portion of an exon from a gene that encodes protein X in the genome of the plant Arabidopsis. Wildtype DNA3’ TTC AAT GCT CCG AAT ACC 5’ template strand5’ AAG TTA CGA GGC TTA TGG 3’ non-template strand A new strain (Strain B) of Arabidopsis is identified with the same region of the gene coding for protein X: 3’ TTC AAT GCT CCC AAT ACC 5’ template strand5’ AAG TTA CGA GGG TTA TGG 3’ non-template strand Compare the two DNA sequences and look for any differences. Based on what you find a. There is no mutation in Strain B compared to Strain A. b. After the point of the mutation, all the amino acids encoded by the Strain B template will be different than the Strain A protein X. c. Protein X made from the Strain B template will be much shorter than protein X made from the Strain A template d. Protein X from Strain B will have one amino acid difference that would not affect protein function. e. There is a mutation but there will not be any difference in the…arrow_forwardE The arrow in the diagram below indicates the direction of transcription. BTTL c. A ATGCCGCA AUGCCCCAAUCUG TACGGCGTTAGAC OA OB с Q Search Which letter indicates the 5' end of the DNA template strand? R F TTCACGCACTCATSTOFACCACGTA T G Direction of synthesis- CG STACATGAGIAC LOC Y H Krit & 7 FO U 99+ * 8 D ATEGTGCAT CVBNM MO DE 79 Alt F:-10 KL E 0 P ^ @ ¹ F12 Ctrl 10:37 AM 4/8/2023 10arrow_forward
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