Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- a. Replicate this sense strand to create a double-stranded DNA helix. Write your answers in CAPS LOCK with NO SPACES between the nucleotides - e.g. ATGCCGAG..... TGAGGATGAAACTCACACCGGGGCGCAGTTTGGCACTTAGATTCTTGTACACGACCTAGTATAACACAGTT complementary strand: b. Using this DNA double helix, express the gene – i.e. determine the resulting polypeptide sequence by using the correct reading frame. Write your answers using the three letter abbreviation for each amino acid. polypeptide sequence: does the sense strand DNA sequence have 5’ and 3’ UTR sequences? 5'UTR = 3'UTR =arrow_forward1c) Give the anticodon of the tRNA that would be a "wobble match" for the codon 5'AGG3'.arrow_forward(d) Let's suppose that the exons encoding the binding site for the SARS-CoV-2 spike protein are widely spaced (the exons are far apart, the parts on the polypeptide are far apart-I made these up so if they coincide with your answers, it is by accident). As indicated below, exons 4.10 and 15 encode the parts of the protein (indicated by arrows) that interact with the spike protein. Exon 4 E10 E15 RNA (protein)_ N- Give TWO explanations as to how widely separated parts of a protein can interact with the spike protein. (I gave one in the class)arrow_forward
- Identify the type of point mutation on the following strands (transition or transversion): a. 5’ TACTGCA 3’ 5’ TATTGCA 3’ 3’ ATGACGT 5’ 3’ ATAACGT 5’ b. 5’ CGACGTTA 3’ 5’ CGAGGTTA 3’ 3’ GCTGCAAT 5’ 3’ GCTCCAAT 5’c. Which of these types is more common and why?arrow_forward2b) Once an RNA polymerase has initiated transcription, it will release the sigma factor or sigma subunit and bind other proteins known as elongation factors before it begins moving down the DNA template doing strand elongation. Briefly explain why this is necessary - why can't RNA polymerase + sigma factor do all of transcription?arrow_forwardTay-Sachs disease (TSD) is a fatal genetic disorder, that results in progressive destruction of the nervous system. Tay-Sachs is caused by a mutation in the gene that codes for an enzyme called hexosaminidase-A (Hex-A). Hex A CDNA from normal and a Tay-Sachs individual was sequenced using the same primer. This is the coding strand and starts in-frame at amino acid position #78. Results are shown below. Read the darkest band in each row. Normal Tay-Sachs (-) ATG C ATG C (+) a. Write each coding strand DNA sequence, normal and Tay-Sachs 5' to 3' b. Write the amino acid sequence that will be translated from each sequence, normal and Tay-Sachs C. Describe the type of mutation? Predict the effect of this mutation on the Hex A protein.arrow_forward
- 2b) What anticodon would a suppressor tRNA have to have to suppress a 5'UAA3' stop codon?arrow_forwardThe amino acid sequence of part of a protein has beendetermined:N . . . Gly Ala Pro Arg Lys . . . CA mutation has been induced in the gene encodingthis protein using the mutagen proflavin. The resultingutant protein can be purified and its amino acidsequence determined. The amino acid sequence of themutant protein is exactly the same as the amino acidsequence of the wild-type protein from the N terminus of the protein to the glycine in the preceding sequence. Starting with this glycine, the sequence ofamino acids is changed to the following:N . . . Gly His Gln Gly Lys . . . CUsing the amino acid sequences, one can determinethe sequence of 14 nucleotides from the wild-typegene encoding this protein. What is this sequence?arrow_forwardLook at Figure 17-22 and state which bands are missing in the cri du chat deletion.arrow_forward
- G-LO37 Identify the consequences of mutations in different regions of a gene. The image below represents two strands of DNA: the top one corresponds to a healthy individual, and the bottom one of a sibling potentially affected with a disease due to genetic mutations Mutation 1 A + с AUA ACA AUG Met ACG GUU GUC GUA GUG Val GCU GCC GCA GCG It will result in mRNA produced Mutation 2 It will result in no mRNA produced 500 AGG The protein produced will be normal 500 + GGG Ala The Select all that applies about Mutation 1 (position -6): AAGLys AGA Arg GGU GGC GGA GGG GAC Asp GAA Glu GAGJ Gly The protein produced will have a different amino acid 1235 ATT 1235 TTT 070 2070 ALL The mutation occurs in the promoter region, and this means that the mRNA cannot be produced 1535 The mRNA and protein will both be normal because the mutation occurs outside of the consensus region of the promoter G 1535 с Affectedarrow_forward8) Transposons have two methods of transposition. Briefly describe each one and indicate whether genome is the same size or has increased in size after a transposition event.arrow_forwardI've attached the table of transcription ans translation for a DNA and Bees work, Genes A and B are exons while C is an intron. Gene A has a silent mutation and Gene B has a nonsense mutation. Please answer the below for me The 3 genes code for different proteins: • Gene A = protein essential for stinger • Gene B = DNA replication enzyme • Gene C = fuzzy hair protein Do you think it matters which protein is mutated? Is one protein more important than another? How would you try to help the bees stay healthy using the information from the mutations?arrow_forward
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