Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- G3 62 GI G 4 GGU W AUG GCC AUG CUC ACG GAG CUC UUC UAC CGG R (the strand) Y CUC GAG AAG The original template for this process is: O DNA O MRNA O TRNA O FRNA & 5 6 7\ 9. t O o oarrow_forwardAssume that you are a RNA polymerase. Which strand is the template strand? -5 ↓ 3’-TCTTCGTGAGATGATATAAGAGTTATCCAGGTACCGGTAAACTGG-5’ 5’-AGAAGCACTCTACTATATTCTCAATAGGTCCATGGCCATTTGACC-3’arrow_forwardThe beginning of the hexose kinase gene's sequence can be found below, the +1 nucleotide is underlined and bolded. It also contains an origin of replication (ORI) which is found at position 30. 1 20 ORI 40 60 5'.TTCGAGCTCTCGTCGTCGAGATACGCGATGATATTACTGGTAATATGGGGATGCACTATC...3' 3'.AAGCTCGAGAGCAGCAGCTCTATGCGCTACTATAATGACCATTATACCCCTACGTGATAG...5' promoter 2a. Assume that replication has been initiated at that ORI. Provide the sequence of the primer that is complementary to the DNA in each of the following positions. d Site A - binding to the top strand of the DNA at position 20 – 30 5' 3' Site B - binding to the top strand of the DNA at position 31 -41 5' 3' 2b. Replication is occurring normally in these cells; would you expect to find a primer in both positions? Why or why not?arrow_forward
- A lagging strand is sketched below. The Okazaki fragment DNA is red, and the RNA primers aredashed orange lines. Which Okazaki fragment was made first? When ligase joins fragments Aand B, will it act at arrow 1, arrow 2, or both?arrow_forward5’ GGACCTATCAAAATCCTTATGCGCTAGGATAGCTAACGCATCCAC3’ This is the template strand. The +1 transcription start site is bold. Transcribe template DNA to mRNA. Make sure you write mRNA in the 5’ to 3’ direction. This is tricky – don’t assume the polymerase knows right from left. It can only synthesize new DNA in 5’>3’ direction.arrow_forwardpcc300ATAAADATATAOOTTAA 1. Use the genetic code table and the information in the diagram below to determine the amino acids that would make up the portion of the polypeptide shown. Include information for a key as well. DNA template 3' G CATA ACAGAGGATT-5' al bnsua AMAm pniwollot erfT E transcription s yd bnsita ebitgeqylog s sidmeaze of beae RNA strandUU UAOUOUU A-emoaodin 5'-CGUA AUUGUC UCCUUA- 3' J J JL erit o elinW (s) translation bluow terdt aspnso sigootiwsone polypeptide viemetis ns ebivo19 (d) ent ot etslanT Key:arrow_forward
- Provide the sequences of the template and coding strands of a DNA double helix that was used toproduce this RNA: 5’-GUUACCGACUAU. Be sure to label the 5’ and 3’ ends.arrow_forward1. Given the piece of MRNA: 5'-CCUGCAGUAUGAAACGCCUGGUAGAAGGUGGGAAGUGGUGCGCC-3' 1. Predict the DNA strand sequence from which it was transcribe 2. List the complementary non-coding DNA Sequence 3. List the Amino acid Sequence of the protein coded for. Use the Genetic Code 2. Below is a short segment of a DNA molecule. Translate the DNA codon into MRNA. 5'- TACCATGAGAATTGTGG TCACCTTTTT-3' 3'- ATGGTACTCTTAACACCAGTGGAAAA A-5' MRNA Sequence Amino Acid Sequencearrow_forwardGenetics Attached is a segment of DNA (doublestranded). Answer the following questions about the segment of DNA: How many open reading frames (ORF) are in this sequence? How many amino acids are encoded in all open reading frames in this segment/sequence? Which strand is the template strand for the longest open reading frame?arrow_forward
- 15)arrow_forwardThe following DNA strand is a template strand (also called non-coding strand) of an E. coli gene. Arrow indicates the direction of transcription. The asterisk indicates t transcription initiation site GCAGTGACCGGATATAACGAAGAGGAATGCCGTACAAA 5' GCAGTGA 3' -10 Which of the following sequences accurately represents the RNA derived from this gene? C5' UCCUUAC 3' C3' UCCUUAC 5' C5' CGUCACU 3' +10 3' AGGAATG 5'arrow_forwardvvnicn the following statements are correct about the repair of a DNA duplex containing the sequence below that is grown INE coli (select all that apply)? Strand A Strand B GATCTAGCCGGCATCCGAT CTAGATCGGACGTAGGCTA Methyl ✔A. MutH cleaves Strand A O B. DNA repair will result in the bold A in strand B being replaced with a C O C. DNA repair will result in the bold G in strand A being replaced with a T ✔ D. Defect will not be properly repaired in dam(-) E coli O E. The mammalian repair system would also correct the mismatch shown based on the methylation status of the DNAarrow_forward
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