I asked this question 5 hours ago still haven't gotten any answers for it, please show all work, want to make sure I make no mistakes on this type of question. 2)Determine the shear force V(x) and moment M(x) as functions of x by integrating for thesystem sketched below.yLWo*X

The load intensity is-The reaction at left support is .The moment equilibrium conditions at the…

Answered: 2)Determine the shear force V(x) and…

Engineering

Mechanical Engineering

2)Determine the shear force V(x) and moment M(x) as functions of x by integrating for the system sketched below. y Wo x

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

8:30 Test 3.pdf F1 F2 a CF3 A b a F4 D Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30°, 0= 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m e) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m 0 None of them 21 What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 KN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m ) None of them 31 What is the resultant moment of the five forces acting on the rod about point C? b) - 21.1 kN.m e) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m ) None of them a) 32.6 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m ) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m ) None…
A > X L Determine the function for internal resultant moment in terms of x given: L = L Wo = W M(x) = B x³ + Number For: Wo = 6 kN/m L = 3 m Find the variables a, b, c, and d for the equation in the form ax³+bx²+cx+d. Note: terms may be equal to zero M(x) = Number x² + Number Wo x + Number
Solved Examples 8KN Example 5 Replace the force and couple moment system acting on the beam in the figure below by an equivalent resultant force, and find where its line of action intersects the beam, measured from point O. 4KN 15 KN-m (0,5 m Solution:- Force Summation. Summing the force components, 1.5 m 1.5 m 15 m 15m F), = XF;; (F), = 8 kN(}) = 4.80 kNO
Draw the shear and moment diagrams for the figure shown Show your solutions 80KN 40KN ▼ 30 KN/m v 3m 3m 3m
Q2: Draw the load and the bending moment diagrams that correspond to the given shear force diagrams in the figures below.[ V (kN) Figure (1) V (kN) Figure (2) 114 11 94 14 x (m) x(m) 2. 1.4 18 -66 V(kN) Figure (3) V Figure (4) (kN) | 20 2 3 - 2nd-degree curve x(m) x (m) 1* degree 2nd degree -16 3 -13
Answer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Leta = 5.2 ft, w = 235 Ib/ft, Mp = 7000 lb-ft, and P = 11001b. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Mp Determine the bending moment acting at each of the following locations: (a) x = 5.2 ft (i.e., at point B) (b) x = 10.4 ft (i.e., at point C) (c) x = 15.6 – ft (i.e., just to the left of point D) (d) x = 15.6 + ft (i.e., just to the right of point D) (e) x = 20.8 ft (i.e., at point E) When entering your answers, use the bending moment sign convention.
Required information A rope connecting points A and B supports the force F shown in the figure. Write expressions using Cartesian vector representation for the following. Take L = 8 ft and F= 12 lb. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. y 30° es ÜAB : the unit vector in the direction from A to B. ûAB =
The cantilever beam depicted below is rigidly attached to a wall at point A, which coincides with the coordinate system's origin. Point B near the beam's free end has coordinates (1.3, 0.3, 2.4) m. The vector r₁ = 11+12ĵ+1km is perpendicular to the beam axis AB and oriented parallel to the width dimension of the cross-section, as shown. The vector 7₂ = 29.1î+1.23 — 14.72 m is perpendicular to the beam axis AB and r₁. The force P applied to point B of the beam has the direction angles 0 = 144°, 0y = 72°,0₂ = 60°. fa Questions: a Assuming |P| = 1000 N Compute the force moment about ri and 72. b Previous experiments on similar beams made of the same material have shown that the beam will rupture and be torn from the wall when the absolute value of the moment of P about r₁ is 4000 Nm, or when the absolute value of the moment of P about r2 is 6000 Nm. Determine the magnitude of P that will cause this beam to fail.
A distributed load and a force is applied to a beam, where a = 2 m, b = 7 m, c= 3 m, w = 2 N/m, F = 5 N, and 0 = 45°. W F Determine the internal normal force (N), shear force (V), and moment (M) at point P, located at distance x = 4 m from the fixed support. (Note: Remember the sign conventions.) N = number (rtol=0.01, atol=1e-05) N V = number (rtol=0.01, atol=1e-05) М- number (rtol=0.01, atol=1e-05) N'm
Find the desired ones by randomly typing two A and B vectors in the form below. A = (5) i + (7) j + (10) k B = (2) i + (3) j + (5) k The cross product A x B =? Scalar product A x B =? Intensity A x B =?
Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M = 14 kN-m Ay = 3.54 KN Dy = 32.46 kN Units: KN Ay M 4m O 31.52 kN-m O 20.0 kN-m O 33.6 kN-m 23.2 kN-m O 26.1 kN-m B Ay 4 m 15 kN C A, 4 m A,-15 7 kN/m D 3 m 21 A₁-15 E X