Solved Examples Example 5 Replace the force and couple moment system acting on the beam in the figure below by an equivalent resultant force, and find where its line of action intersects the beam, measured from point O. 15 KN m asm Solution:- Force Summation. Summing the force components, 15m+15m 15m 15m

I need quick solution, attempt only if you can solve it fast. Answer is around 166.7lb (don't know where on the beam does the resultant acts) Show work with FBD

1 ft 3 ft B 3 ft 3 ft (-9002 + 800f + 1000k) Ib.ft 6 ft 3 ft E (-300î – 400ĵ + 100k) Ibs The applied force at point E and the applied couple moment at point D are shown in the figure. Complete/calculate the following: (Where applicable, express the results as the (x, y, z) components of a Cartesian vector) 1. Draw the free-body diagram (FBD), showing the appropriate reaction forces and/or moments at the supports. (You must show the reactions in their component form i.e. show RAx, MRAX etc. on the FBD). Note: The support at point A is not able to resist a moment about the 'X' axis but is able to resist a force in this direction. 2. ME, which is the moment vector at point A due to the force acting at point E 3. Me, which is the moment vector at point A due to the tension force acting at point B. Write the vector in terms of the unknown tension magnitude 'T' 4. Set up the equations of equilibrium (You must show all relevant equilibrium equations one below the other. 5. Calculate the…

Using the image below replace the distributed loading with an equivalent resultant force, and specify its location on the beam measured from point A.   Let the length be: L1 = 9 ft.   Let the loads be: W1 = 70 lb/ft, W2 = 420 lb/ft.   Note you must determine the coefficients a and b based on the given intensities of the loads W1 and W2, respectively.