Chapter 9.7, Problem 13PSB

a

To determine

To find: The coordinates of a given point.

Answer to Problem 13PSB

The coordinates of a given point is (1, 1)

Explanation of Solution

Given information :

Triangle $45°-45°-90°$

Coordinates of O as (0, 0) and A (1, 0)

Formula used :

Triangle $45°-45°-90°$ , two sides are equal

Calculation :

Since, In Triangle $45°-45°-90°$ , two sides are equal

Thus, OC = CD = 1 unit

Therefore,

The coordinates of a given point D is (1, 1)

b

To determine

To find: The slope of given line

Answer to Problem 13PSB

The slope of OD is 1

Explanation of Solution

Given information :

Triangle $45°-45°-90°$

Coordinates of O as (0, 0) and C (1, 0)

Formula used :

Triangle $45°-45°-90°$ , two sides are equal

Calculation :

Since, In Triangle $45°-45°-90°$ , two sides are equal

Thus, OC = CD = 1 unit

Therefore,

The slope of OD = $\frac{\text{CD}}{\text{OC}}=\frac{1}{1}=1$

c

To determine

To find: The tangent of 45 $°$

Answer to Problem 13PSB

The tangent of 45 $°$ is 1

Explanation of Solution

Given information :

Triangle $45°-45°-90°$

Coordinates of O as (0, 0) and C (1, 0)

Formula used :

Triangle $45°-45°-90°$ , two sides are equal

Calculation :

Since, In Triangle $45°-45°-90°$ , two sides are equal

Thus, OC = CD = 1 unit

Therefore,

The tangent of 45 $°$ = $\frac{\text{CD}}{\text{OC}}=\frac{1}{1}=1$