Chapter 9.10, Problem 6PSB

a

To determine

To find: The value of xin the given expression i.e. $\sin {25}^0=\frac{x}{40}$

Answer to Problem 6PSB

The value of $x=17$

Explanation of Solution

Given information:The following value has been given

  $\sin {25}^0=\frac{x}{40}$

Formula used:No formula used. Values have been found from trigonometric tables in the book

Calculation:We find the value of $\sin {25}^0$ in order to find the value of x . hence, from the trigonometric tables, we get

  $\sin {25}^0=0.4226$

Now, we substitute this value in our main equation. We get

  $0.4226=\frac{x}{40}\to x=17$

Hence, we can say that

  $x=17$

b

To determine

To find: The value of xin the given expression i.e. $\cos {73}^0=\frac{35}{x}$

Answer to Problem 6PSB

The value of $x=120$

Explanation of Solution

Given information:The following value has been given

  $\cos {73}^0=\frac{35}{x}$

Formula used:No formula used. Values have been found from trigonometric tables in the book

Calculation:We find the value of $\cos {73}^0$ in order to find the value of x . hence, from the trigonometric tables, we get

  $\cos {73}^0=0.2924$

Now, we substitute this value in our main equation. We get

  $0.2924=\frac{35}{x}\to x=120$

Hence, we can say that

  $x=120$

c

To determine

To find: The value of xin the given expression i.e. $\sin x^0=\frac{29}{30}$

Answer to Problem 6PSB

The value of $x={75}^0$

Explanation of Solution

Given information:The following value has been given

  $\sin x^0=\frac{29}{30}$

Formula used:No formula used. Values have been found from trigonometric tables in the book

Calculation:We find the value of ${\sin }^{-1}\frac{29}{30}$ in order to find the value of x . hence, from the trigonometric tables, we get

  ${\sin }^{-1}\frac{29}{30}={75}^0$

Hence, we can say that

  $x={75}^0$