a
To find: The co-ordinate of “ B ”.
a

Answer to Problem 12PSB
The co-ordinate of “ B ” is (1,√3) .
Explanation of Solution
Given information :
30°−60°−90°
Coordinates of O as (0, 0) and A as (1, 0)
Formula used :
In 30°−60°−90° triangle, sides are in ratio 1: √3 :2
Calculation :
In triangle, OAB
tan60o=ABOA√3=AB1AB=√3
Therefore, the y co-ordinate of B is √3
Hence, the coordinate of B is (1,√3)
b
To find: The slope of line “ OB ”.
b

Answer to Problem 12PSB
The slope of a given line is √3
Explanation of Solution
Given information :
30°−60°−90° triangle
Coordinates of O as (0, 0) and A as (1, 0)
Formula used :
In 30°−60°−90° triangle, sides are in ratio 1: √3 :2
Calculation :
In triangle, OAB
It is 30°−60°−90° triangle and OA = 1 unit
∴ AB = √3 and
Required ratio = ABOA=√31=√3
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