Concept explainers
Practice Problem 9.2
Find the phase angle between
Does i1 lead or lag i2?
Answer: 210°, i1 leads i2.
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Fundamentals of Electric Circuits
- Prob. I and Vc For the following RMS phasor circuit, a coworker has determined values for 50 Ohms 50 Ohms i,- 225 2253.13° = 190.92 + 254.56 VRMS R1 + R2 Vc = 237.17/26.565° = 212.13+ 106.07 VRMS 100 2 -3Z98.13° =-0.4243 + J2.970 ARMS C -j60 Ohms For this problem provide at least 3 digits of precision for the answers. The results for the following calculations are to be answered in - a) Find the current I b) Determine the real (P) and reactive(Q) power DELIVERED by the source c) Determine the real (P) and reactive (Q) power ABSORBED by each impedance ( resistors R1 and R2, inductor and capacitor). The values for P and Q can be positive or negative. Remember S =P+jQ, so do not include the j with your answer for Q. Each of these answers will require two parts. For the phasor a magnitude and angle will be needed. For the powers, The real power P and the reactive power Q are required.arrow_forwardLet's say V = 10 sin( 2t) is a reference sinusoid. Then the phasor diagram of i=20 cos( 2t - 20°) is drawn as shown in Figure 2. ... I, 110° 70° -70° -110° I (a) (b) (c) (d) Figure 2 A a B) barrow_forwardTwo sinusoidal currents are given by the equations: il = 10 sin (ot + 1/3) and i2= 15 sin (oot-/4) ne phase difference between them is-degrees (b) 75 (a) 105 (c) 15 $ (d) 60arrow_forward
- 3) Given the circuit with an AC sinusoidal current source and an AC sinusoidal voltage source: ZR1 $60k0 <0 deg V₁" I₂" IR1 V1- Zc 85 kohms <-90 deg Ic VR2™ VL™ VIC ZR1 = 60 k < 0 degrees Zc = 85 k0 <-90 degrees ZR2 = 20 kn 0 degrees Z₁ = 50 kn < 90 degrees www ZR2 20k0 <0 deg Isa 1.2 mA <0 deg 12- + Esb All sinusoidal complex phasor currents and voltages are peak phasors. Isa 1.2 mA <0 degrees represents a current source peak phasor Esb = 80 V < -150 degrees represents a voltage source peak phasor The current source and voltage source have angular velocity w 2000 rad/s At the previously stated angular velocity, the schematic shows the element complex impedances as follows: ZL 50 kohms < 90 deg 80 V<-150 deg Use the Superposition theorem and circuit analysis to find all of the circuit peak complex phasor voltages and currents requested below:arrow_forward• V is an AC voltage source with 220 V amplitude, 50 Hz frequency and 0° phase i₁ is an AC current with 2 A amplitude, 50 Hz frequency and 10° phase lag with respect to V i2 is an AC current with 4 A amplitude, 50 Hz frequency and 40° phase lag with respect to V Determine: 1. The phasor form for • V= ● Provide your answers to this part to 0.d.p 2. The values of i₁ = i2 = ● R₁ = • L1 = ● 2 R2 = L2= Provide your answers to this part to 3.d.p. Ω H Ω H + V i Figure EL4-1 Downloadable image 12 R₂arrow_forward1. Solve for I rms. 0.785 and b = 3.37. a = i(wt) = 21.8 sin (wt – 1.312) – 50 + 75.0e¯®t/3.77 A for 0.785arrow_forwardAsiacell l. U L3% docs.google.com A non-sinusoidal voltage (e=20+15sin2000t+ 10sin6000t+5sin8000t) Volt is applied to the circuit shown. Find the total power? * iT -J9Q 4Ω, iL IR ет J4Ω (+)arrow_forward4. With respect to the following figure, explain why v。 does not follow v₁ until Và – Vỵ and follows only when v₁ ≥ VB - Vy in the positive half cycle? What happens in the negative half-cycle? Explain. Assume a sinusoidal current of losin(ot) from v₁, what is the voltage drop across R when vo follows vi and Vo does not follow v₁. www + R D VI vo VB-Vy VI Voarrow_forwardA non-sinusoidal voltage (e=20+15sin1000t+ 10sin3000t+5sin4000t) Volt is applied to the circuit shown. Find the * ?total power iT 42 42 iL ic ет, -J92 J4Q 44.04 W 44.03 W 88.06 W 86.08 Warrow_forwardProblem 10 – Transformation [6] A delta and star configuration shown in Figure 7. Transform the delta connection are to a star and determine the values impedances: (a) ZA (b) ZB (c) Zc of the following Z CAS zZAB wi B Impedance in polar notation. 2 BC Figure 7 ZAB = 27.3L0° Q ZBc = 27.3L-30° Q ZCA = 27.3L 30° Qarrow_forwardQUESTION 6 R www L m + + + 12 cos 3t V Vo 4 sin 2t A 10 V If we would like to use Superposition to solve for vo in the circuit shown above, we must find the individual contribution of each independent source. SINUSOIDAL CURRENT SOURCE CONTRIBUTION: What is the amplitude of the voltage vo considering only the contribution of the sinusoidal current source? Assume that R = 16 Ohms, L = 11.9 Henry, and C = 0.03 Farad. Write your answer in Volts.arrow_forwardA non-sinusoidal current source (iT=2+1.5sin1000t+ 1cos30o0t- 0.5sin4000t) A is applied to the * ?circuit shown. Find the total power İL iT ic -J9N J4Q 39 W O 20 W O 55 W 28 W )!( هذا السؤال مطلوبarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning