The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH 3 O - has to be drawn. Concept Introduction: Elimination reaction: Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily. E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

Question

Want to see the full answer?

Answer 1

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Don't used Ai solution

this is an organic chemistry question please answer accordindly!! please post the solution draw the figures and post, answer the question in a very simple and straight forward manner thanks!!!!! please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures or diagrams, please draw them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!! im reposting this kindly solve all parts and draw it not just word explanations!!

Please correct answer and don't used hand raiting

Answer 2

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 6

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

Answer 7

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 9.1 - Prob. 3P Ch. 9.1 - Does increasing the energy barrier for an SN2...Ch. 9.1 - Rank the following alkyl bromides from most...Ch. 9.1 - Prob. 8P Ch. 9.2 - Prob. 9P Ch. 9.2 - Prob. 10P Ch. 9.2 - Prob. 11P Ch. 9.2 - Prob. 12P Ch. 9.2 - Which substitution reaction lakes place more...Ch. 9.2 - Prob. 15P

Solution Summary: The author explains that 3-bromo-3-methyl-1-butene has - hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed

Want to see the full answer?

Chapter 9 Solutions