Chemistry
4th Edition
ISBN: 9780078021527
Author: Julia Burdge
Publisher: McGraw-Hill Education
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Chapter 9, Problem 49QP
The formation of
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. Assume that the third-period element phosphorus forms a diatomic molecule, P2, in an analogous way as nitrogen does to form N2. (a) Write the electronic configuration for P2. Use [Ne2] to represent the electron configuration for the first two periods. (b) Calculate its bond order. (c) What are its magnetic properties (diamagnetic or paramagnetic)?
The average bond energy (enthalpy) for a C=C double bond is 614 kJ/molkJ/mol and that of a C−C single bond is 348 kJ/molkJ/mol. If it takes
4.42×10−19
J/molecule
to break the C=C double bond. What is the longest wavelength λ of light that will provide photons of sufficient energy to break the π bond and cause the isomerization?
Express your answer numerically in nanometers.
“Inert” xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF6 are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the enthalpy of formation is - 402 kJ/mol.
Chapter 9 Solutions
Chemistry
Ch. 9.1 - Practice Problem ATTEMPT
Determine the shapes of...Ch. 9.1 - Prob. 1PPBCh. 9.1 - Prob. 1PPCCh. 9.1 - 9.1.1 What are the electron-domain geometry and...Ch. 9.1 - What are the electron-domain geometry and...Ch. 9.1 - Prob. 3CPCh. 9.1 - Prob. 4CPCh. 9.1 - Prob. 5CPCh. 9.2 - Practice Problem ATTEMPT
Ethanolamine has a...Ch. 9.2 - Practice Problem BUILD
The bond angle in is...
Ch. 9.2 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.2 - 9.2.1 Identify the polar molecules in the...Ch. 9.2 - Identify the nonpolar molecules in the following...Ch. 9.3 - Practice ProblemATTEMPT Use valence bond theory to...Ch. 9.3 - Practice ProblemBUILD For which molecule(s) can we...Ch. 9.3 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.3 - Which of the following atoms, in its ground state,...Ch. 9.3 - According to valence bond theory, how many bonds...Ch. 9.4 - Practice Problem ATTEMPT Use hybrid orbital theory...Ch. 9.4 - Practice ProblemBUILD Use hybrid orbital theory to...Ch. 9.4 - Prob. 1PPCCh. 9.4 - How many orbitals does a set of s p 2 hybrid...Ch. 9.4 - How many p atomic orbitals are required to...Ch. 9.5 - Practice Problem ATTEMPT
The active ingredient in...Ch. 9.5 - Practice ProblemBUILD Determine the total number...Ch. 9.5 - Practice ProblemCONCEPTUALIZE In terms of valence...Ch. 9.5 - Which of the following molecules contain one or...Ch. 9.5 - 9.5.2 From left to right, give the hybridization...Ch. 9.5 - Which of the following pairs of atomic orbitals on...Ch. 9.5 - 9.5.4 Which of the following pairs of atomic...Ch. 9.6 - Practice ProblemATTEMPT Use valence bond theory...Ch. 9.6 - Prob. 1PPBCh. 9.6 - Prob. 1PPCCh. 9.6 - Prob. 1CPCh. 9.6 - Prob. 2CPCh. 9.6 - Prob. 3CPCh. 9.6 - Prob. 4CPCh. 9.7 - Prob. 1PPACh. 9.7 - Prob. 1PPBCh. 9.7 - Prob. 1PPCCh. 9.7 - Prob. 1CPCh. 9.7 - Prob. 2CPCh. 9.7 - Prob. 3CPCh. 9.7 - Prob. 4CPCh. 9.8 - Practice ProblemATTEMPT Use a combination of...Ch. 9.8 - Practice ProblemBUILD Use a combination of valence...Ch. 9.8 - Prob. 1PPCCh. 9 - Prob. 1KSPCh. 9 - Which of the following species does not have...Ch. 9 - 9.3
Which of the following species is polar?
Ch. 9 - Which of the following species is nonpolar (a) IC1...Ch. 9 - How is the geometry of a molecule defined, and why...Ch. 9 - 9.2 Sketch the shape of a linear triatomic...Ch. 9 - How many atoms are directly bonded to the central...Ch. 9 - Discuss the basic features of the VSEPR model....Ch. 9 - In the trigonal bipyramidal arrangement, why does...Ch. 9 - 9.6 Explain why the molecule is not square...Ch. 9 - Predict the geometries of the following species...Ch. 9 - Predict the geometries of the following species: (...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following ions using...Ch. 9 - 9.12 Predict the geometries of the following ions:...Ch. 9 - Describe the geometry around each of the three...Ch. 9 - 9.14 Which of the following species are...Ch. 9 - Prob. 15QPCh. 9 - The bonds in beryllium hydride ( BeH 2 ) molecules...Ch. 9 - Determine whether (a) BrF 5 and (b) BCl 3 are...Ch. 9 - Determine whether (a) OCS and (b) XeF 4 are polar.Ch. 9 - Prob. 19QPCh. 9 - Prob. 20QPCh. 9 - Prob. 21QPCh. 9 - Use valence bond theory to explain the bonding in...Ch. 9 - Prob. 23QPCh. 9 - Prob. 24QPCh. 9 - 9.25 What is the hybridization of atomic orbitals?...Ch. 9 - Prob. 26QPCh. 9 - 9.27 What is the angle between the following two...Ch. 9 - Prob. 28QPCh. 9 - Prob. 29QPCh. 9 - Prob. 30QPCh. 9 - Prob. 31QPCh. 9 - Prob. 32QPCh. 9 - Prob. 33QPCh. 9 - Prob. 34QPCh. 9 - Which of the following pairs of atomic orbitals of...Ch. 9 - Prob. 36QPCh. 9 - 9.37 Specify which hybrid orbitals are used by...Ch. 9 - The allene molecule ( H 2 C=C=CH 2 ) is linear...Ch. 9 - Prob. 39QPCh. 9 - Prob. 40QPCh. 9 - How many pi bonds and sigma bonds are there in the...Ch. 9 - Prob. 42QPCh. 9 - Benzo(a)pyrene is a potent carcinogen found in...Ch. 9 - What is molecular orbital theory? How does it...Ch. 9 - 9.45 Define the following terms: bonding molecular...Ch. 9 - Sketch the shapes of the following molecular...Ch. 9 - Explain the significance of bond order. Can bond...Ch. 9 - Explain in molecular orbital terms the changes in...Ch. 9 - 9.49 The formation of from two atoms is an...Ch. 9 - 9.50 Draw a molecular orbital energy level diagram...Ch. 9 - Prob. 51QPCh. 9 - Prob. 52QPCh. 9 - Which of these species has a longer bond, B 2 or B...Ch. 9 - Prob. 54QPCh. 9 - 9.55 Compare the Lewis and molecular orbital...Ch. 9 - Prob. 56QPCh. 9 - Prob. 57QPCh. 9 - Prob. 58QPCh. 9 - A single bond is almost always a sigma bond, and a...Ch. 9 - Prob. 60QPCh. 9 - In Chapter 8, we saw that the resonance concept is...Ch. 9 - Prob. 62QPCh. 9 - Prob. 63QPCh. 9 - Prob. 64QPCh. 9 - Nitryl fluoride ( FNO 2 ) is very reactive...Ch. 9 - Prob. 66QPCh. 9 - Prob. 67QPCh. 9 - Which of the following species is not likely to...Ch. 9 - Prob. 69APCh. 9 - Although both carbon and silicon are in Group 4A,...Ch. 9 - Predict the geometry of sulfur dichloride ( SCl 2...Ch. 9 - Antimony pentafluoride ( sbF 5 ) reacts with XeF 4...Ch. 9 - Prob. 73APCh. 9 - Prob. 74APCh. 9 - Predict the bond angles for the following...Ch. 9 - Briefly compare the VSEPR and hybridization...Ch. 9 - 9.77 Draw Lewis structures and give the other...Ch. 9 - Prob. 78APCh. 9 - Determine whether (a) PCl 5 and (b) H 2 CO (C...Ch. 9 - Prob. 80APCh. 9 - 9.81 Which of the following molecules are linear:...Ch. 9 - Prob. 82APCh. 9 - 9.83 The molecule can exist in either of the...Ch. 9 - Cyclopropane ( C 3 H 6 ) has the shape of a...Ch. 9 - Determine whether (a) CH 2 Cl 2 and (b) XeF 4 are...Ch. 9 - 9.86 Does the following molecule have a dipole...Ch. 9 - For which molecular geometries (linear, bent,...Ch. 9 - Prob. 88APCh. 9 - 9.89 Carbon suboxide is a colorless...Ch. 9 - The following molecules ( AX 4 Y 2 ) all have an...Ch. 9 - Prob. 91APCh. 9 - Write the ground-state electron configuration for...Ch. 9 - 9.93 What is the hybridization of C and of N in...Ch. 9 - The stable allotropic form of phosphorus is P 4 ,...Ch. 9 - Prob. 95APCh. 9 - Use molecular orbital theory to explain the...Ch. 9 - Carbon dioxide has a linear geometry and is...Ch. 9 - Draw three Lewis structures for compounds with the...Ch. 9 - Prob. 99APCh. 9 - Prob. 100APCh. 9 - Prob. 101APCh. 9 - Draw the Lewis structure of ketene ( C 2 H 2 O )...Ch. 9 - Prob. 103APCh. 9 - Which of the following ions possess a dipole...Ch. 9 - Prob. 105APCh. 9 - Prob. 106APCh. 9 - The compound TCDD, or...Ch. 9 - Progesterone is a hormone responsible for female...Ch. 9 - 9.109 Carbon monoxide is a poisonous compound due...Ch. 9 - Prob. 110APCh. 9 - Prob. 111APCh. 9 - Prob. 112APCh. 9 - 9.113 The compound 1,2-dichloroethane is...Ch. 9 - Consider an N 2 molecule in its first excited...Ch. 9 - Prob. 115APCh. 9 - Prob. 1SEPPCh. 9 - Prob. 2SEPPCh. 9 - These questions are not based on a descriptive...Ch. 9 - These questions are not based on a descriptive...
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- Best Lewis Formula and Molecular Geometry A student writes the Lewis electron-dot formula for the carbonate anion, CO32, as a Does this Lewis formula obey the octet rule? Explain. What are the formal charges on the atoms? Try describing the bonding for this formula in valence bond terms. Do you have any difficulty doing this? b Does this Lewis formula give a reasonable description of the electron structure, or is there a better one? If there is a better Lewis formula, write it down and explain why it is better. c The same student writes the following resonance description for CO2: Is there something wrong with this description? (What would you predict as the geometries of these formulas?) d Is one or the other formula a better description? Could a value for the dipole moment help you decide? e Can you write a Lewis formula that gives an even better description of CO2? Explain your answer.arrow_forwardIt is possible to write a simple Lewis structure for the SO42- ion, involving only single bonds, which follows the octet rule. However, Linus Pauling and others have suggested an alternative structure, involving double bonds, in which the sulfur atom is surrounded by six electron pairs. (a) Draw the two Lewis structures. (b) What geometries are predicted for the two structures? (c) What is the hybridization of sulfur in each case? (d) What are the formal charges of the atoms in the two structures?arrow_forwardThe bond energy of C2 is 599 kJ/mol, the bond distance is 110 pm. Take a rough estimate of the Coulomb repulsion in doubly ionized C2 (i.e., C22+). How far would the C-C bond have to stretch for the Coulomb repulsion to be less than the bond energy in neutral C2? Do you think that the C22+ molecule will still be stable?arrow_forward
- Can you please help me with this?arrow_forward"Inert" xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF, are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the heat of formation is -402 kJ/mol.arrow_forwardIodine trichloride, ICl₃, is a bright yellow solid and an oxidizing agent. Based on your Lewis structure for ICl₃, how many electron domains are on the central atom?arrow_forward
- Here's a wild molecule: disulfur dinitride (S2N2). It can be isolated as a crystalline solid, but it is unstable (explosive). Therefore, it must to be handled carefully in an inert atmosphere free of oxygen. X-ray diffraction measurements of the crystalline solid indicate the atoms are arranged in a square with the sulfur atoms on opposite corners and the nitrogen atoms on the remaining opposite corners. Consider the bonding in this unusual molecule. a. Determine the best Lewis structure representation for S2N2. Include the formal charges on each atom in the structure. b. Determine the valence bonding theory predictions for hybridization at each atom in S2N2. The bond angles in S2N2 have been measured by X-ray diffraction and are all approximately 90°. Does valence bond theory do a good job of predicting this observation? Consider the geometry and bonding of S2N2 computed using molecular orbital theory. The results are shown below. Identify the orbital character of the HOMO(-2),…arrow_forwardThe Lewis structure for SF6 is shown below. This sulfur S atom in this molecule has an expanded octet, and you are not expected to be familiar with the specific electron geometry and molecular geometry for expanded octets. Still, we can make some predictions with the knowledge that we have. Would you predict the electron geometry and molecular geometry for SF6 to be the same or to differ? Please briefly explain your answer.arrow_forwardWhich of the following statements concerning the N₂O molecule is/are true? The atoms are bonded in the order NNO. You may select more than one, or none, of the responses. The central N atom is sp² hybridized. The structure of N2O is best represented as a hybrid of three equivalent resonance structures, There are two σ and two bonds. The N2O molecule is linear. The central N atom has a formal charge of +1. The N-N-O angle is 60°, The two N atoms have the same oxidation state.arrow_forward
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