The compound 1,2-dichloroethane (C 2 H 4 Cl 2 ) is nonpolar, while cis -dichloroethylene (C 2 H 2 Cl 2 ) has a dipole moment: The reason for the difference is that groups connected by a single bond can rotate with respect to each other, but no rotation occurs when a double bond connects the groups. On the basis of bonding considerations, explain why rotation occurs in 1,2-dichloroethane but not in cis- dichloroethylene.
The compound 1,2-dichloroethane (C 2 H 4 Cl 2 ) is nonpolar, while cis -dichloroethylene (C 2 H 2 Cl 2 ) has a dipole moment: The reason for the difference is that groups connected by a single bond can rotate with respect to each other, but no rotation occurs when a double bond connects the groups. On the basis of bonding considerations, explain why rotation occurs in 1,2-dichloroethane but not in cis- dichloroethylene.
The compound 1,2-dichloroethane
(C
2
H
4
Cl
2
)
is nonpolar, while cis-dichloroethylene
(C
2
H
2
Cl
2
)
has a dipole moment: The reason for the difference is that groups connected by a single bond can rotate with respect to each other, but no rotation occurs when a double bond connects the groups. On the basis of bonding considerations, explain why rotation occurs in 1,2-dichloroethane but not in cis- dichloroethylene.
Benzene is an organic chemical compound with the molecular formula C6Hỏ. In the benzene molecule, carbon atoms form a ring with alternating single and double bonds connecting them. Thus, each individual carbon
atom forms one o bond with another carbon atom and one σ and one π bond with another carbon atom. Each carbon atom also forms one o bond with a hydrogen atom.
H
H
Identify which types of orbitals overlap to form the bonds between the atoms in a benzene molecule.
Drag the appropriate labels to their respective targets.
View Available Hint(s)
р-р
sp² - sp²
sp³ – sp³
sp-sp
sp² - s
Bonds formed
Carbon-carbon o bond
Carbon-carbon bond
H-C
Carbon-hydrogen o bond
H
C-C
000
C=C
Type of orbitals involved
C-H
H
Reset Help
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell