Physical Universe
16th Edition
ISBN: 9780077862619
Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur
Publisher: Mcgraw-hill Education,
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Chapter 9, Problem 28E
To determine
Reason why electron microscope have greater useful magnification than an optical microscope.
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7. Resolving ‘power’ of an electron microscope versus optical (photon) microscope: If a resolution of 1.0 x 10-11m (0.010nm) is required to ‘see’ an atom, (a) If electrons are used (e-microscope), what minimum kinetic energy of the electrons is required? Use deBroglie’s Hypothesis and KE = p2/2me and non-relativistic velocities:\
(b) If photons are used, what minimum KE (Eγ) is required to obtain 10-11m resolution?
An electron microscope is designed to resolve objects as small as 0.14 nm. What energy electrons must be used in this instrument?
The resolving power of a microscope depends on the wavelength used. If you wanted to "see" an atom, a
resolution of approximately 1.00 x 10-11 m would be required. If electrons are used (in an electron
microscope), what minimum kinetic energy is required for the electrons?
Chapter 9 Solutions
Physical Universe
Ch. 9 - Prob. 1MCCh. 9 - Prob. 2MCCh. 9 - Prob. 3MCCh. 9 - Prob. 4MCCh. 9 - Prob. 5MCCh. 9 - Prob. 6MCCh. 9 - Prob. 7MCCh. 9 - Prob. 8MCCh. 9 - Prob. 9MCCh. 9 - Prob. 10MC
Ch. 9 - Prob. 11MCCh. 9 - Prob. 12MCCh. 9 - Prob. 13MCCh. 9 - Prob. 14MCCh. 9 - Prob. 15MCCh. 9 - Prob. 16MCCh. 9 - Prob. 17MCCh. 9 - Prob. 18MCCh. 9 - Prob. 19MCCh. 9 - Prob. 20MCCh. 9 - Prob. 21MCCh. 9 - Prob. 22MCCh. 9 - Prob. 23MCCh. 9 - Prob. 24MCCh. 9 - Prob. 25MCCh. 9 - Prob. 26MCCh. 9 - Prob. 27MCCh. 9 - Prob. 28MCCh. 9 - Prob. 29MCCh. 9 - Prob. 30MCCh. 9 - Prob. 31MCCh. 9 - Prob. 32MCCh. 9 - Prob. 33MCCh. 9 - Prob. 34MCCh. 9 - Prob. 35MCCh. 9 - Prob. 36MCCh. 9 - Prob. 37MCCh. 9 - Prob. 38MCCh. 9 - Prob. 39MCCh. 9 - Prob. 40MCCh. 9 - Prob. 41MCCh. 9 - Prob. 42MCCh. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - Prob. 11ECh. 9 - Prob. 12ECh. 9 - Prob. 13ECh. 9 - Prob. 14ECh. 9 - Prob. 15ECh. 9 - Prob. 16ECh. 9 - Prob. 17ECh. 9 - Prob. 18ECh. 9 - Prob. 19ECh. 9 - Prob. 20ECh. 9 - Prob. 21ECh. 9 - Prob. 22ECh. 9 - Prob. 23ECh. 9 - Prob. 24ECh. 9 - Prob. 25ECh. 9 - Prob. 26ECh. 9 - Prob. 27ECh. 9 - Prob. 28ECh. 9 - Prob. 29ECh. 9 - Prob. 30ECh. 9 - Prob. 31ECh. 9 - Prob. 32ECh. 9 - Prob. 33ECh. 9 - Prob. 34ECh. 9 - Prob. 35ECh. 9 - Prob. 36ECh. 9 - Prob. 37ECh. 9 - Prob. 38ECh. 9 - Prob. 39ECh. 9 - Prob. 40ECh. 9 - Prob. 41ECh. 9 - Prob. 42ECh. 9 - Prob. 43ECh. 9 - Prob. 44ECh. 9 - Prob. 45ECh. 9 - Prob. 46ECh. 9 - Prob. 47ECh. 9 - Prob. 48ECh. 9 - Prob. 49ECh. 9 - Prob. 50ECh. 9 - Prob. 51ECh. 9 - Prob. 52ECh. 9 - Prob. 53ECh. 9 - Prob. 54ECh. 9 - Prob. 55ECh. 9 - Prob. 56ECh. 9 - Prob. 57ECh. 9 - Prob. 58ECh. 9 - Prob. 59ECh. 9 - Prob. 60ECh. 9 - Prob. 61ECh. 9 - Prob. 62ECh. 9 - Under what circumstances do electrons exhibit...
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- An electron microscope passes 1.00-pm-wavelength electrons through a circular aperture 2.00 μm in diameter.What is the angle between two just-resolvable point sources for this microscope?arrow_forwardAn electron microscope passes 1.00-pm-wavelength electrons through a circular aperture 2.00 µm in diameter. What is the angle between two just-resolvable point sources for this microscope?arrow_forward2. We have a fiber optics link that uses a semiconductor pin photodiode which has the following characteristics: Wavelength of operation is 1.31 µm, reflectivity of the entrance face (anti- reflection coating) is 0.1, width of the depletion layer is 300 µm and the absorption coefficient of the semiconductor material is 25 cm". a. If a steady state average optical power of 0.2 mwatt is applied to this semiconductor pin photodiode, find the average photocurrent generated. Take h = 6.6×10* Joule.sec and q =1.6×10 Amp.sec. b. Find the responsivity of this semiconductor pin photodiode in mAmp/watt . If you measure 1010 µ Amp at the output of this semiconductor pin photodiode, what is the applied average optical power in mwatts?arrow_forward
- 8: Two flat mirrors are connected to each other such that they make an angle of ψ. A laser enters the system and first reflects off the bottom mirror, then the top mirror. When the beam exits it makes an angle of θ = 126 degrees with respect to the initial beam (see figure). θ = 126 degrees (a) Write an expression for the angle, ψ, between the mirrors. (b) Calculate this angle, ψ, in degrees.arrow_forwardThe spacing between atomic planes in a crystal is 0.130 nm. a) If 15.0 keV x rays are diffracted by this crystal, what is the angle of first-order diffraction? b) If 15.0 keV x rays are diffracted by this crystal, what is the angle of second-order diffraction?arrow_forward3. Diatomic line. Consider a line of atoms ABAB.....AB, with A-B bond length of a/2. The form factors are fa and f for atoms A, B, respectively. The incident beam of x- rays is perpendicular to the line of atoms. (a) Show that the interference condition is nλ = a cose, where is the angle between the diffraction beam and the line of atoms. (b) Show that the intensity of the diffracted beam is proportional to A f₁-f² for n odd, and to \ƒÃ +ƒÂ for n even. (c) Explain what happens if fA=fB.arrow_forward
- The resolving power of a microscope depends on the wavelength used. If you wanted to “see” an atom, a wavelength of approximately 1.00 × 10-11 m would be required. (a) If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons? (b) What If? If photons are used, what minimum photon energy is needed to obtain the required resolution?arrow_forwardThe resolving power of a microscope depends on the wavelength used. If you wanted to "see" an atom, a wavelength of approximately 1.00 x 10-11 m would be required.If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons?arrow_forwardX rays with a wavelength of 0.085 nm diffract from a crystal in which the spacing between atomic planes is 0.18 nm. How many diffraction orders are observed?arrow_forward
- 3. For crystal diffraction experiments, wavelengths on the order of 0.23 nm are often appropriate. Find the energy in electron volts for a particle with this wavelength if the particle is (a) a photon; (b) an electron; (c) an alpha particle (m = 6.64 × 10- 27 kg)arrow_forwardX rays with a wavelength of 0.0700 nm diffract from a crystal. Two adjacent angles of x-ray diffraction are 45.6° and 21.0°. What is the distance in nm between the atomic planes responsible for the diffraction?arrow_forwardTo resolve an object in an electron microscope, the wavelength of an electrons must be close to the diameter of the object. What kinetic energy must they have in order to resolve a protein molecule that is 8.40 nm in diameter. Take the mass of an electron to be 9.11 x 10-31 kg.arrow_forward
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