Chemistry: Atoms First
Chemistry: Atoms First
3rd Edition
ISBN: 9781259638138
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 8, Problem 8.37QP

Nitrous oxide (N2O) is also called “laughing gas.” It can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H2O. (a) Write a balanced equation for this reaction, (b) How many grams of N2O are formed if 0.46 mole of NH4NO3 is used in the reaction?

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: Balanced equation of ammonium nitrate decomposition and the amount of N2O produced from 0.46 mole of NH4NO3 has to be determined.

Concept introduction:

Balanced chemical equation: The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass.

Massofstartingmaterials(Reactants)=MassofproductsN2+H2NH3

In the above reaction 2 nitrogen atoms are there in reactant side but 1 nitrogen in product side, likewise 2 hydrogen’s in reactant side but 3 hydrogen’s in product side so this is unbalanced equation by putting coefficients for each elements in both sides we can balance this reaction as follows:

N2+3H22NH3

To write: Balanced chemical equation of NH4NO3 decomposition

Answer to Problem 8.37QP

Balanced equation for ammonium nitrate decomposition is given below

NH4NO3N2O+H2O

Explanation of Solution

The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass this equation is known as balanced chemical equation.

Decomposition of ammonium nitrate:

Starting material: ammonium nitrate NH4NO3

Products: N2O and H2O

We can write this chemical reaction as follows:

NH4NO3N2O+H2O

Above one is an unbalanced equation because the number of hydrogen and oxygen in starting material and products are not equal. So this equation balanced by putting coefficients to corresponding elements as follows:

NH4NO3N2O+2H2O

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: Balanced equation of ammonium nitrate decomposition and the amount of N2O produced from 0.46 mole of NH4NO3 has to be determined.

Concept introduction:

Balanced chemical equation: The mass of products should be equal to mass of its starting materials this is governed by law of conservation of mass.

Massofstartingmaterials(Reactants)=MassofproductsN2+H2NH3

In the above reaction 2 nitrogen atoms are there in reactant side but 1 nitrogen in product side, likewise 2 hydrogen’s in reactant side but 3 hydrogen’s in product side so this is unbalanced equation by putting coefficients for each elements in both sides we can balance this reaction as follows:

N2+3H22NH3

To calculate: The amount of N2O produced from 0.46 mole of NH4NO3

Answer to Problem 8.37QP

The amount of N2O produced from 0.46 mole of NH4NO3 is 20.2457 g

Explanation of Solution

NH4NO3N2O+2H2O

The above balanced equation shows 1 mole of N2O produced from 1 mole NH4NO3

1moleofN2O1moleofNH4NO3

Molar mass of NH4NO3 calculation is given below:

MolarmassofNH4NO3=((2×massofN)+(4×massofH)+(3×massofO))grams=((2×14.0067)+(4×1.00794)+(3×15.9994))grams=(28.0134+4.03176+47.9982)grams=80.04336grams

Molar mass of N2O calculation is given below:

MolarmassofN2O=((2×massofN)+massofO)grams=((2×14.0067)+15.9994)grams=(28.0134+15.9994)grams=44.0128grams

Moles to gram conversion of NH4NO3

molesofNH4NO3×molecularmassofNHN4O3=weightofNH4NO3ingrams0.46×80.04336=36.8199grams

Production of N2Ocalculation is given below:

WeightofN2Oproducedingrams=MassofNH4NO3 in grams×MolarmassofN2OingramsMolarmassofNH4NO3ingrams 36.8199g×44.0128g80.04336g=20.2457g

The amount of N2O produced from 0.46 mole of NH4NO3 is 20.2457 g

Conclusion

Balanced equation of ammonium nitrate decomposition and the amount of N2O produced from 0.46 moles of NH4NO3 were determined.

(a) Balanced equation for ammonium nitrate decomposition is given below

NH4NO3N2O+H2O

(b) The amount of N2O produced from 0.46 mole of NH4NO3 is 20.2457 g

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Chapter 8 Solutions

Chemistry: Atoms First

Ch. 8.1 - Using the chemical species A2, B, and AB, write a...Ch. 8.1 - Prob. 3PPCCh. 8.1 - Prob. 8.1.1SRCh. 8.1 - Prob. 8.1.2SRCh. 8.1 - Prob. 8.1.3SRCh. 8.1 - Prob. 8.1.4SRCh. 8.1 - Prob. 8.1.5SRCh. 8.2 - Combustion of a 5.50-g sample of benzene produces...Ch. 8.2 - The combustion of a 28.1-g sample of ascorbic acid...Ch. 8.2 - Prob. 4PPBCh. 8.2 - Prob. 4PPCCh. 8.2 - Prob. 8.2.1SRCh. 8.2 - Prob. 8.2.2SRCh. 8.2 - Prob. 8.2.3SRCh. 8.3 - Prob. 8.5WECh. 8.3 - Nitrogen and hydrogen react to form ammonia...Ch. 8.3 - Prob. 5PPBCh. 8.3 - Prob. 5PPCCh. 8.3 - Prob. 8.6WECh. 8.3 - Calculate the mass of water produced by the...Ch. 8.3 - Prob. 6PPBCh. 8.3 - The models here represent the reaction of nitrogen...Ch. 8.3 - Prob. 8.3.1SRCh. 8.3 - What mass of lithium nitride is produced when 75.0...Ch. 8.3 - Prob. 8.3.3SRCh. 8.3 - Determine the stoichiometric amount (in grams) of...Ch. 8.4 - Alka-Seltzer tablets contain aspirin, sodium...Ch. 8.4 - Ammonia is produced by the reaction of nitrogen...Ch. 8.4 - Prob. 7PPBCh. 8.4 - The diagrams show a reaction mixture before and...Ch. 8.4 - Aspirin, acetylsalicylic acid (C9H8O4), is the...Ch. 8.4 - Diethyl ether is produced from ethanol according...Ch. 8.4 - What mass of ether will be produced if 207 g of...Ch. 8.4 - The diagrams show a mixture of reactants and the...Ch. 8.4 - How many moles of NH3 can be produced by the...Ch. 8.4 - Prob. 8.4.2SRCh. 8.4 - What is the percent yield for a process in which...Ch. 8.4 - Prob. 8.4.4SRCh. 8.4 - Reactants A (red) and B (blue) combine to form a...Ch. 8 - Calculate the mass of water produced in the...Ch. 8 - Calcium phosphide (Ca3P2) and water react to form...Ch. 8 - Prob. 8.3KSPCh. 8 - Prob. 8.4KSPCh. 8 - Prob. 8.1QPCh. 8 - Prob. 8.2QPCh. 8 - Why must a chemical equation he balanced? What law...Ch. 8 - Write an unbalanced equation to represent each of...Ch. 8 - Prob. 8.5QPCh. 8 - Prob. 8.6QPCh. 8 - For each of the following unbalanced chemical...Ch. 8 - Prob. 8.8QPCh. 8 - Balance the following equations using the method...Ch. 8 - Which of the following equations best represents...Ch. 8 - Prob. 8.11QPCh. 8 - Determine whether each of the following equations...Ch. 8 - Prob. 8.13QPCh. 8 - Prob. 8.14QPCh. 8 - Prob. 8.15QPCh. 8 - Prob. 8.16QPCh. 8 - Prob. 8.17QPCh. 8 - Prob. 8.18QPCh. 8 - Prob. 8.19QPCh. 8 - Prob. 8.20QPCh. 8 - Prob. 8.21QPCh. 8 - Prob. 8.22QPCh. 8 - Prob. 8.23QPCh. 8 - On what law is stoichiometry based? Why is it...Ch. 8 - Prob. 8.25QPCh. 8 - Prob. 8.26QPCh. 8 - Prob. 8.27QPCh. 8 - Prob. 8.28QPCh. 8 - Prob. 8.29QPCh. 8 - Prob. 8.30QPCh. 8 - Prob. 8.31QPCh. 8 - Prob. 8.32QPCh. 8 - Prob. 8.33QPCh. 8 - When copper(II) sulfate pentahydrate (CuSO4 5H2O)...Ch. 8 - For many years, the extraction of gold from other...Ch. 8 - Prob. 8.36QPCh. 8 - Nitrous oxide (N2O) is also called laughing gas....Ch. 8 - Prob. 8.38QPCh. 8 - Prob. 8.39QPCh. 8 - Prob. 8.1VCCh. 8 - Prob. 8.2VCCh. 8 - Prob. 8.3VCCh. 8 - Prob. 8.4VCCh. 8 - Prob. 8.40QPCh. 8 - Prob. 8.41QPCh. 8 - Why is the theoretical yield of a reaction...Ch. 8 - Why is the actual yield of a reaction almost...Ch. 8 - Prob. 8.44QPCh. 8 - Prob. 8.45QPCh. 8 - Reactants A (red) and B (blue) combine in the...Ch. 8 - Prob. 8.47QPCh. 8 - Prob. 8.48QPCh. 8 - Prob. 8.49QPCh. 8 - Propane (C3H8) is a minor component of natural gas...Ch. 8 - Prob. 8.51QPCh. 8 - Prob. 8.52QPCh. 8 - Prob. 8.53QPCh. 8 - Prob. 8.54QPCh. 8 - Prob. 8.55QPCh. 8 - Prob. 8.56QPCh. 8 - Disulfur dichloride (S2Cl2) is used in the...Ch. 8 - Prob. 8.58QPCh. 8 - Prob. 8.59QPCh. 8 - Prob. 8.60QPCh. 8 - Prob. 8.61QPCh. 8 - Prob. 8.62QPCh. 8 - Prob. 8.63QPCh. 8 - Prob. 8.64QPCh. 8 - Prob. 8.65QPCh. 8 - Industrially, nitric acid is produced by the...Ch. 8 - Prob. 8.67QPCh. 8 - Prob. 8.68QPCh. 8 - Prob. 8.69QPCh. 8 - Prob. 8.70QPCh. 8 - Prob. 8.71QPCh. 8 - Prob. 8.72QPCh. 8 - Prob. 8.73QPCh. 8 - Prob. 8.74QPCh. 8 - Prob. 8.75QPCh. 8 - Prob. 8.76QPCh. 8 - Prob. 8.77QPCh. 8 - Prob. 8.78QPCh. 8 - Prob. 8.79QPCh. 8 - The combustion of a 5.50-g sample of oxalic acid...Ch. 8 - Prob. 8.81QPCh. 8 - Prob. 8.82QPCh. 8 - Prob. 8.83QPCh. 8 - Prob. 8.84QPCh. 8 - Prob. 8.85QPCh. 8 - Prob. 8.86QPCh. 8 - Potash is any potassium mineral that is used for...Ch. 8 - A 21.496-g sample of magnesium is burned in air to...Ch. 8 - Prob. 8.89QPCh. 8 - Prob. 8.90QPCh. 8 - Prob. 8.91QPCh. 8 - Prob. 8.92QPCh. 8 - Prob. 8.93QPCh. 8 - Prob. 8.94QPCh. 8 - Prob. 8.95QPCh. 8 - Prob. 8.96QPCh. 8 - Prob. 8.97QPCh. 8 - Prob. 8.98QPCh. 8 - A compound X contains 63.3 percent manganese (Mn)...
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