(Latin square) A Latin square is an n-by-n array filled with n different Latin letters, each occurring exactly once in each row and once in each column. Write a program that prompts the user to enter the number n and the array of characters, as shown in the sample output, and checks if the input array is a Latin square. The characters are the first n characters starting from A.
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- (FYI: Pseudocode is required (Not any programming language) Design a pseudocode program that loads an array with the following 7 values. Add one more word (of your own choosing) for a total of 8 words. biffcomelyfezmottleperukebedraggledquisling Be sure to use lowercase, as shown above. This will make the processing easier. Ask the user to enter a word Search through this array until you find a match with the word the user entered. Once you find a match, output "Yes, that word is in the dictionary". If you get to the end of the array and do NOT find a match, output "No, that word is not in the dictionary". The program should work with any set of words in the arrays. If I were to change the words in the arrays, it should still work. If you need help, look at the search example in your textbook.arrow_forwardWrite the function that prints a 23 numbered array sent into it with the main function.(Please generate the 23 numbers randomly)arrow_forwardDo the following in the most efficient way possible in C Language: 1. Take an Array of 10 integer values (automatically should be converted to ascending order). 2. Insert Values - Value should be inserted automatically as per the ascending order. If array is {1,7,28,45,67,81} and the user inserts 31; the program should automatically insert at the 3rd index and array size should increase by 1. 3. Delete Values by Range - the user will be asked to two indexes (<sizeofArray) and all values in between those indexed should be deleted. E.g. If array is {1, 7, 28, 45, 67,81} and user enters the indexes 2,4. Then the values 28, 45, 67 should be deleted.arrow_forward
- Do the following in the most efficient way possible in C Language: 1. Take an Array of 10 integer values (automatically should be converted to ascending order). 2. Insert Values - Value should be inserted automatically as per the ascending order. If array is {1,7,28,45,67,81} and the user inserts 31; the program should automatically insert at the 3rd index and array size should increase by 1. 3. Delete Values by Range - the user will be asked to two indexes (<sizeofArray) and all values in between those indexed should be deleted. E.g. If array is {1, 7, 28, 45, 67,81} and user enters the indexes 2,4. Then the values 28, 45, 67 should be deleted. Note: If at any time, the array becomes unsorted, then; some values need to be deleted at runtime to make the array sorted again. At any given time, the array shouldn't be unsorted. Please do not use Pointers and only use Array as a Data Structure.arrow_forwardCorrect my mistake in my C++ code please! Here is the question and my code is below as well. (Duplicate Elimination with array) Use a one-dimensional array to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the array only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Provide for the 'worst case' in which all 20 numbers are different. Use the smallest possible array to solve this problem. Code; #include <iostream> using namespace std; int main(){ int arr[100]={0};int temp,i;for( i=0;i<20;i++){ cout<<"Enter an Integer : "; cin>>temp; arr[temp]++;}for( i=0;i<100;i++) if(arr[i]==1) cout<<i<<" "; return 0;}arrow_forwardExercise 2. (Pascal's Triangle) Pascal's triangle Pn is a triangular array with n+1 rows, each listing the coefficients of the binomial expansion (x+ y)', where 0 _ "/workspace/project3 рython3 pавса1.ру 10 1 1 1 1 2 1 1 33 1 1 4 6 4 1 1 5 10 10 5 1 16 15 20 15 6 1 1 7 21 35 35 21 7 1 1 8 28 56 70 56 28 8 1 1 9 36 84 126 126 84 36 9 1 1 10 45 120 210 252 210 120 45 10 1 В равса1.ру import stdarray import stdio іпрort вys # Accept n (int) as command -line argument. ... # Setup a 2D ragged list a of integers. The list must have n + 1 rovs, vith the ith (0 <= i # <= n) row a[i] having i + 1 elements , each initialized to 1. For example, if n = 3, a should be # initialized to [[1], [1, 1], [1, 1, 1], [1, 1, 1, 1]]. a =... for i in range (...): ... # Fill the ragged list a using the formula for Pascal's triangle 1] [j - 1) + a[i - 1] [j] a [i][j] = a[i - 1] [j - 1] + a[i - 1] [j] #3 # vhere o <- i <- n and 1 <= j < i. for i in range (...): for j in range (...): ... # Write a to standard…arrow_forward
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- Write pseudo code for given statemente. The amount variable is set to 0, and then each is called on the array. Each of the values in the array is passed to the block. Each time the block is called, amount is updated:arrow_forwardWrite the following function that tests whether the array has four consecutive numbers with the same value. bool isConsecutiveFour(const int values[], int size) Write a test program that prompts the user to enter a series of integers and displays if the series contains four consecutive numbers with the same value. Your program should first prompt the user to enter the input size—i.e., the number of values in the series. Assume the maximum number of values is 80. Here are sample runs: Enter the number of values: 8 Enter the values: 3 4 5 5 5 5 4 5 The list has consecutive fours Enter the number of values: 9 Enter the values: 3 4 5 5 6 5 5 4 5 The list has no consecutive foursarrow_forwardCorrect my mistake in my C++ code please! Here is the questin and my code is below as well. (Duplicate Elimination with array) Use a one-dimensional array to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the array only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Provide for the 'worst case' in which all 20 numbers are different. Use the smallest possible array to solve this problem. Code; #include <iostream> using namespace std; int main(){ int arr[100]={0};int temp,i;for( i=0;i<20;i++){ cout<<"Enter an Integer : "; cin>>temp; arr[temp]++;}for( i=0;i<100;i++) if(arr[i]==1) cout<<i<<" "; return 0;}arrow_forward
- C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr