General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN: 9781305580343
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher: Cengage Learning
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Chapter 8, Problem 8.118QP
Interpretation Introduction

Interpretation:

The kinetic energy of an electron emitted from Helium ion has to be calculated.

Concept introduction:

The kinetic energy of an electron emitted is calculated using given formula

Bohr formula is when the nf=,ni=1andZ=2

 ΔE=-RH[2222212]=-RH[-4]=4RH

Expert Solution & Answer
Check Mark

Answer to Problem 8.118QP

The kinetic energy of an electron emitted from Helium ion ionized is 4.5×10-18J

Explanation of Solution

Bohr formula is

 ΔE=-RH[2222212]=-RH[-4]=4RH

4×2.179×10-18J1He+ion

I.E=4×2.179×10-18J1He+ion×6.022×1023He+ions1He+ions=5.24_87×106J1molHe+

I.E.=5.25×103kJ/molHe+

The electron is removed from H atom

The law of conservation of energy,

 Ephoton=Ekinetic+I.E

The energy of the 15 nm photon is calculated

 Ephoton==hcλ=(6.626×10-34J.sphoton)(2.998×108m/s)15.0×10-9m=0.45_2×10-17Jphoton

 8.716×10-18J

   Ekinetic=Ephoton-I.E=1.32_4×10-17J-8.716×10-18J=0.45_2×10-17J=4.5×10-18J

Conclusion

The kinetic energy of an electron emitted from Helium ion ionized as found to be  4.5×10-18J

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Chapter 8 Solutions

General Chemistry - Standalone book (MindTap Course List)

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