The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated. Concept Introduction: Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism. Elimination reaction of an alkyl halide results in the formation of an alkene . Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1° . Also E1 reaction takes place only on tertiary alkyl halides . If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product. If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer. If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

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Answer 1

Question

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

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Students have asked these similar questions

What is the major elimination product obtained from an E2 reaction of each of the following alkyl halides with hydroxide ion?

Which alkyl bromide(s) can form the alkene under E2 elimination conditions.

Draw the structure (including stereochemistry) of an alkyl chloride that forms each alkene as the exclusive E2 elimination product.

Answer 2

Question

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

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Answer 3

Question

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

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Answer 4

Question

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

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Answer 5

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

Answer 6

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

Answer 7

Chapter 8, Problem 48P

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

Answer 8

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

Answer 9

(a)

Interpretation Introduction

Interpretation:

The stereoisomer that would be formed in greatest yield in E2 reaction from the given alkyl halide has to be indicated.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both base and substituents in the reaction) mechanism.

Elimination reaction of an alkyl halide results in the formation of an alkene.

Zaitsev’s rule: In elimination reaction, when one hydrogen atom is removed from β- carbon in such a way that more substitute alkene is formed.

Relative relativities of alkyl halide in an E2 reaction are 3°> 2°> 1°. Also E1 reaction takes place only on tertiary alkyl halides.

If the product obtained after E2 reaction has both E and Z stereoisomers, then E-isomer is the major product.

If the two largest groups in a molecule are in same side of the double bond, then it is called as Z-isomer.

If the two largest groups in a molecule are in opposite side of the double bond, then it is called as E-isomer.

Answer 10

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Answer 11

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Answer 13

Ch. 8.1 - Prob. 2P Ch. 8.1 - Does increasing the energy barrier for an SN2...Ch. 8.1 - Arrange the following alkyl bromides in order from...Ch. 8.2 - Prob. 7P Ch. 8.2 - Which reaction in each of the following pairs...Ch. 8.2 - Prob. 9P Ch. 8.2 - Prob. 11P Ch. 8.3 - Draw the substitution products that will be formed...Ch. 8.4 - Arrange the following alkyl halides in order from...Ch. 8.5 - Prob. 14P

Solution Summary: The author explains that Elimination Reaction is just reverse reaction of addition where substituent from the given molecule is removed via E1 or E2 mechanism.

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Chapter 8 Solutions