Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
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Chapter 8, Problem 28QAP
To determine
The reason why the giant planets except Uranus
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What fraction of the energy emitted from the sun is absorbed by the Earth? Treat the sun like a light bulb 93 million miles away. Also, assume the Earth only absorbs the energy associated with an area of approximately 50 million square miles. (This is roughly the area of a disc with the same radius as the Earth.)
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Chapter 8 Solutions
Understanding Our Universe
Ch. 8.1 - Prob. 8.1CYUCh. 8.2 - Prob. 8.2CYUCh. 8.3 - Prob. 8.3CYUCh. 8.4 - Prob. 8.4CYUCh. 8.5 - Prob. 8.5CYUCh. 8 - Prob. 1QAPCh. 8 - Prob. 2QAPCh. 8 - Prob. 3QAPCh. 8 - Prob. 4QAPCh. 8 - Prob. 5QAP
Ch. 8 - Prob. 6QAPCh. 8 - Prob. 7QAPCh. 8 - Prob. 8QAPCh. 8 - Prob. 9QAPCh. 8 - Prob. 10QAPCh. 8 - Prob. 11QAPCh. 8 - Prob. 12QAPCh. 8 - Prob. 13QAPCh. 8 - Prob. 14QAPCh. 8 - Prob. 15QAPCh. 8 - Prob. 16QAPCh. 8 - Prob. 17QAPCh. 8 - Prob. 18QAPCh. 8 - Prob. 19QAPCh. 8 - Prob. 20QAPCh. 8 - Prob. 21QAPCh. 8 - Prob. 22QAPCh. 8 - Prob. 23QAPCh. 8 - Prob. 24QAPCh. 8 - Prob. 25QAPCh. 8 - Prob. 26QAPCh. 8 - Prob. 27QAPCh. 8 - Prob. 28QAPCh. 8 - Prob. 29QAPCh. 8 - Prob. 30QAPCh. 8 - Prob. 31QAPCh. 8 - Prob. 32QAPCh. 8 - Prob. 33QAPCh. 8 - Prob. 34QAPCh. 8 - Prob. 35QAPCh. 8 - Prob. 36QAPCh. 8 - Prob. 37QAPCh. 8 - Prob. 38QAPCh. 8 - Prob. 39QAPCh. 8 - Prob. 40QAPCh. 8 - Prob. 41QAPCh. 8 - Prob. 42QAPCh. 8 - Prob. 43QAPCh. 8 - Prob. 44QAPCh. 8 - Prob. 45QAP
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- The light a planet receives from the Sun (per square meter of planet surface) decreases with the square of the distance from the Sun. So a planet that is twice as far from the Sun as Earth receives (1/2)2=0.25 times (25%) as much light and a planet that is three times as far from the Sun receives (1/3)2=0.11 times (11%) as much light. How much light is received by the moons of Jupiter and Saturn (compared to Earth), worlds which orbit 5.2 and 9.5 times farther from the Sun than Earth?arrow_forwardMultiple choice. The total Sun's energy output for every second can power Earth in modern time hundreds of years several hundreds of thousands years about 50-100 years millions of years billions of yearsarrow_forwardKepler’s First Law: Elliptical Planetary Orbits: The solar system major planet in the most elliptical solar orbit is little Mercury, which is the closest planet to the Sun. At Perihelion, Mercury’s distance from the Sun (Rp) is 0.31 AU. At Aphelion, Mercury’s distance from the Sun (Ra) is 0.47 AU. The intensity of Sunlight (I) that a planet receives from the Sun is inversely proportional to the square of that planet’s distance from the Sun (R). in other words, I = Constant / R2. Calculate how much more intense the Sunlight received by Mercury is at perihelion (p) than at aphelion (a): Rp2 = Ra2 = Ip / Ia = Ra2 / Rp2 =arrow_forward
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