The smallest alkane , smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table. Concept Introduction: Physical properties of hydrocarbons: The compounds with high molecular weight have high boiling point. Insoluble in water, but in polar solvent it is stable. Density of hydrocarbons are less than of water. Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

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Answer 1

Question

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

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Answer 2

Question

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Expert Solution & Answer

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Answer 4

Question

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Expert Solution & Answer

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Answer 5

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Answer 6

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Answer 7

Chapter 7.3, Problem 8P

Interpretation Introduction

Interpretation:

The smallest alkane, smallest terminal alkene and smallest terminal alkyne which are liquids at room temperature should be identified from the given table.

Concept Introduction:

Physical properties of hydrocarbons:

The compounds with high molecular weight have high boiling point.

Insoluble in water, but in polar solvent it is stable.

Density of hydrocarbons are less than of water.

Polarity is an important factor in comparing the boiling points of two compounds. The more dipole moment, more will be the boiling point.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 7.1 - What is the molecular formula for a monocyclic...Ch. 7.1 - Prob. 2P Ch. 7.1 - Draw the structure and give the common and...Ch. 7.1 - Prob. 4P Ch. 7.1 - Name the following:Ch. 7.2 - Prob. 6P Ch. 7.2 - Name the following:Ch. 7.3 - Prob. 8P Ch. 7.3 - Why does cis-2-butene have a higher boiling point...Ch. 7.4 - What orbitals are used to form the carbon-carbon ...

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