Statistics Through Applications
Statistics Through Applications
2nd Edition
ISBN: 9781429219747
Author: Daren S. Starnes, David Moore, Dan Yates
Publisher: Macmillan Higher Education
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Question
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Chapter 7.2, Problem 7.38E

(a)

To determine

To Calculate: P(BandG) and explain that this makes sense.

(a)

Expert Solution
Check Mark

Answer to Problem 7.38E

  P(B andG)=0

Explanation of Solution

Given:

Event G = ball lands in a green slot.

Formula used:

  Probability=Favourable CasesTotalCases

Calculation:

  P(B andG)=038=0

It makes sense that because there is no slot in both black and green.

(b)

To determine

To Calculate: the P(BorG) using the general addition rule and about you noticed.

(b)

Expert Solution
Check Mark

Answer to Problem 7.38E

  P(BorG)=0.5263

Explanation of Solution

Given:

Event G = ball lands in a green slot.

Formula used:

  Probability=Favourable CasesTotalCases

Calculation:

  P(BorG)=P(B)+p(G)P(B andG)=1838+2380=2038=0.5263

It is observed that the probability of “B or G” is the sum of the probability of event of B and G.

(c)

To determine

To Calculate: P(EandG) and explain that this makes sense.

(c)

Expert Solution
Check Mark

Answer to Problem 7.38E

  P(EandG)=0.0526

Explanation of Solution

Given:

Event G = ball lands in a green slot.

Formula used:

  Probability=Favourable CasesTotalCases

Calculation:

  P(EandG)=238=0.0526

It makes sense that because both green slots are even.

(d)

To determine

To Calculate: P(EorG) using the general addition rule.

(d)

Expert Solution
Check Mark

Answer to Problem 7.38E

  P(EorG)=0.4737

Explanation of Solution

Given:

Event G = ball lands in a green slot.

Formula used:

  Probability=Favourable CasesTotalCases

Calculation:

  P(EorG)=P(E)+P(G)P(EandG)=1838+238218=0.4737

Therefore it is observed that the probability of “E or G” is the probability of event E.

Chapter 7 Solutions

Statistics Through Applications

Ch. 7.1 - Prob. 7.11ECh. 7.1 - Prob. 7.12ECh. 7.1 - Prob. 7.13ECh. 7.1 - Prob. 7.14ECh. 7.1 - Prob. 7.15ECh. 7.1 - Prob. 7.16ECh. 7.1 - Prob. 7.17ECh. 7.1 - Prob. 7.18ECh. 7.1 - Prob. 7.19ECh. 7.1 - Prob. 7.20ECh. 7.1 - Prob. 7.21ECh. 7.1 - Prob. 7.22ECh. 7.1 - Prob. 7.23ECh. 7.1 - Prob. 7.24ECh. 7.1 - Prob. 7.25ECh. 7.1 - Prob. 7.26ECh. 7.2 - Prob. 7.27ECh. 7.2 - Prob. 7.28ECh. 7.2 - Prob. 7.29ECh. 7.2 - Prob. 7.30ECh. 7.2 - Prob. 7.31ECh. 7.2 - Prob. 7.32ECh. 7.2 - Prob. 7.33ECh. 7.2 - Prob. 7.34ECh. 7.2 - Prob. 7.35ECh. 7.2 - Prob. 7.36ECh. 7.2 - Prob. 7.37ECh. 7.2 - Prob. 7.38ECh. 7.2 - Prob. 7.39ECh. 7.2 - Prob. 7.40ECh. 7.2 - Prob. 7.41ECh. 7.2 - Prob. 7.42ECh. 7.2 - Prob. 7.43ECh. 7.2 - Prob. 7.44ECh. 7.2 - Prob. 7.45ECh. 7.2 - Prob. 7.46ECh. 7.2 - Prob. 7.47ECh. 7.2 - Prob. 7.48ECh. 7.2 - Prob. 7.49ECh. 7.2 - Prob. 7.50ECh. 7.2 - Prob. 7.51ECh. 7.2 - Prob. 7.52ECh. 7.3 - Prob. 7.53ECh. 7.3 - Prob. 7.54ECh. 7.3 - Prob. 7.55ECh. 7.3 - Prob. 7.56ECh. 7.3 - Prob. 7.57ECh. 7.3 - Prob. 7.58ECh. 7.3 - Prob. 7.59ECh. 7.3 - Prob. 7.60ECh. 7.3 - Prob. 7.61ECh. 7.3 - Prob. 7.62ECh. 7.3 - Prob. 7.63ECh. 7.3 - Prob. 7.64ECh. 7.3 - Prob. 7.65ECh. 7.3 - Prob. 7.66ECh. 7.3 - Prob. 7.67ECh. 7.3 - Prob. 7.68ECh. 7.3 - Prob. 7.69ECh. 7.3 - Prob. 7.70ECh. 7.3 - Prob. 7.71ECh. 7.3 - Prob. 7.72ECh. 7.3 - Prob. 7.73ECh. 7.3 - Prob. 7.74ECh. 7.3 - Prob. 7.75ECh. 7.3 - Prob. 7.76ECh. 7.3 - Prob. 7.77ECh. 7.3 - Prob. 7.78ECh. 7 - Prob. 7.79RECh. 7 - Prob. 7.80RECh. 7 - Prob. 7.81RECh. 7 - Prob. 7.82RECh. 7 - Prob. 7.83RECh. 7 - Prob. 7.84RECh. 7 - Prob. 7.85RECh. 7 - Prob. 7.86RECh. 7 - Prob. 7.87RECh. 7 - Prob. 7.88RE
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