The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 7.1, Problem 16E

(a)

To determine

The description about the population distribution.

(a)

Expert Solution
Check Mark

Answer to Problem 16E

The population distribution is approximately a binomial distribution with p = 0.75.

Explanation of Solution

Given information:

Number of white beads = 1000

Number of red beads = 3000

Number of beads for SRS = 50

Mean of the Normal distribution = 0.75

Standard deviation = 0.06

To find the total population, add the number of white beads and red beads that is, 1000 beads and 3000 beads.

  1000+3000=4000

Find the proportion of red beads by dividing 3000 by 4000.

  30004000=0.75

The above population distribution is approximately a binomial distribution with p=0.75 .

Hence, the population distribution is approximately a binomial distribution with p = 0.75.

(b)

To determine

The description about the sampling distribution of p¯ and the difference between the population distribution and the sampling distribution.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given information:

Number of white beads = 1000

Number of red beads = 3000

Number of beads for SRS = 50

Mean of the Normal distribution = 0.75

Standard deviation = 0.06

The values of sample proportion p^ follow the Normal distribution whose mean is 0.75 and the standard deviation is 0.06.

This means that the sampling distribution of p^ is the Normal distribution with mean of 0.75 minutes and standard deviation of 0.06.

Also, in the given data the sampling distribution of x¯ describes the proportion of red beads in a sample size of 50.

The sampling distribution differs from the population distribution by its Normal distribution.

Chapter 7 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 7.1 - Prob. 3ECh. 7.1 - Prob. 4ECh. 7.1 - Prob. 5ECh. 7.1 - Prob. 6ECh. 7.1 - Prob. 7ECh. 7.1 - Prob. 8ECh. 7.1 - Prob. 9ECh. 7.1 - Prob. 10ECh. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.2 - Prob. 1.1CYUCh. 7.2 - Prob. 1.2CYUCh. 7.2 - Prob. 1.3CYUCh. 7.2 - Prob. 1.4CYUCh. 7.2 - Prob. 27ECh. 7.2 - Prob. 28ECh. 7.2 - Prob. 29ECh. 7.2 - Prob. 30ECh. 7.2 - Prob. 31ECh. 7.2 - Prob. 32ECh. 7.2 - Prob. 33ECh. 7.2 - Prob. 34ECh. 7.2 - Prob. 35ECh. 7.2 - Prob. 36ECh. 7.2 - Prob. 37ECh. 7.2 - Prob. 38ECh. 7.2 - Prob. 39ECh. 7.2 - Prob. 40ECh. 7.2 - Prob. 41ECh. 7.2 - Prob. 42ECh. 7.2 - Prob. 43ECh. 7.2 - Prob. 44ECh. 7.2 - Prob. 45ECh. 7.2 - Prob. 46ECh. 7.2 - Prob. 47ECh. 7.2 - Prob. 48ECh. 7.3 - Prob. 1.1CYUCh. 7.3 - Prob. 1.2CYUCh. 7.3 - Prob. 1.3CYUCh. 7.3 - Prob. 1.4CYUCh. 7.3 - Prob. 49ECh. 7.3 - Prob. 50ECh. 7.3 - Prob. 51ECh. 7.3 - Prob. 52ECh. 7.3 - Prob. 53ECh. 7.3 - Prob. 54ECh. 7.3 - Prob. 55ECh. 7.3 - Prob. 56ECh. 7.3 - Prob. 57ECh. 7.3 - Prob. 58ECh. 7.3 - Prob. 59ECh. 7.3 - Prob. 60ECh. 7.3 - Prob. 61ECh. 7.3 - Prob. 62ECh. 7.3 - Prob. 63ECh. 7.3 - Prob. 64ECh. 7.3 - Prob. 65ECh. 7.3 - Prob. 66ECh. 7.3 - Prob. 67ECh. 7.3 - Prob. 68ECh. 7.3 - Prob. 69ECh. 7.3 - Prob. 70ECh. 7.3 - Prob. 71ECh. 7.3 - Prob. 72ECh. 7 - Prob. 1CRECh. 7 - Prob. 2CRECh. 7 - Prob. 3CRECh. 7 - Prob. 4CRECh. 7 - Prob. 5CRECh. 7 - Prob. 6CRECh. 7 - Prob. 7CRECh. 7 - Prob. 1PTCh. 7 - Prob. 2PTCh. 7 - Prob. 3PTCh. 7 - Prob. 4PTCh. 7 - Prob. 5PTCh. 7 - Prob. 6PTCh. 7 - Prob. 7PTCh. 7 - Prob. 8PTCh. 7 - Prob. 9PTCh. 7 - Prob. 10PTCh. 7 - Prob. 11PTCh. 7 - Prob. 12PTCh. 7 - Prob. 13PTCh. 7 - Prob. 1PT2Ch. 7 - Prob. 2PT2Ch. 7 - Prob. 3PT2Ch. 7 - Prob. 4PT2Ch. 7 - Prob. 5PT2Ch. 7 - Prob. 6PT2Ch. 7 - Prob. 7PT2Ch. 7 - Prob. 8PT2Ch. 7 - Prob. 9PT2Ch. 7 - Prob. 10PT2Ch. 7 - Prob. 11PT2Ch. 7 - Prob. 12PT2Ch. 7 - Prob. 13PT2Ch. 7 - Prob. 14PT2Ch. 7 - Prob. 15PT2Ch. 7 - Prob. 16PT2Ch. 7 - Prob. 17PT2Ch. 7 - Prob. 18PT2Ch. 7 - Prob. 19PT2Ch. 7 - Prob. 20PT2Ch. 7 - Prob. 21PT2Ch. 7 - Prob. 22PT2Ch. 7 - Prob. 23PT2Ch. 7 - Prob. 24PT2Ch. 7 - Prob. 25PT2
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman
Statistics 4.1 Point Estimators; Author: Dr. Jack L. Jackson II;https://www.youtube.com/watch?v=2MrI0J8XCEE;License: Standard YouTube License, CC-BY
Statistics 101: Point Estimators; Author: Brandon Foltz;https://www.youtube.com/watch?v=4v41z3HwLaM;License: Standard YouTube License, CC-BY
Central limit theorem; Author: 365 Data Science;https://www.youtube.com/watch?v=b5xQmk9veZ4;License: Standard YouTube License, CC-BY
Point Estimate Definition & Example; Author: Prof. Essa;https://www.youtube.com/watch?v=OTVwtvQmSn0;License: Standard Youtube License
Point Estimation; Author: Vamsidhar Ambatipudi;https://www.youtube.com/watch?v=flqhlM2bZWc;License: Standard Youtube License