The compressor efficiency for the following inlet and outlet conditions should be determined. T 1 = 300 K, P 1 = 2 bar, T 2 = 464K, P 2 = 6 Bar and C p /R = 7/2 Concept Introduction: The change in enthalpy and heat capacity at constant pressure are related to each other as follows: ΔH = [ Cp . ( T 2 − T 1 ) ] → Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows: ΔH S = [ Cp .T1 [ ( P2 P 1 ) R C p − 1 ] ] → The compressor efficiency is ratio of isotropic and actual enthalpy change as follows: η = Δ Η S Δ Η

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Answer 1

Question

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

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Answer 2

Question

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Expert Solution & Answer

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Answer 4

Question

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Expert Solution & Answer

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Answer 5

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Answer 6

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Answer 7

Chapter 7, Problem 7.41P

Interpretation Introduction

Interpretation:

The compressor efficiency for the following inlet and outlet conditions should be determined.

T₁ = 300 K, P₁ = 2 bar, T₂ = 464K, P₂ = 6 Bar and C_p/R = 7/2

Concept Introduction:

The change in enthalpy and heat capacity at constant pressure are related to each other as follows:

ΔH = [Cp.(T2−T1)]→

Ideal gas having constant heat capacities. The actual enthalpy change is calculated as follows:

ΔHS=[Cp.T1[( P2 P1 ) R Cp−1]]→

The compressor efficiency is ratio of isotropic and actual enthalpy change as follows:

η = ΔΗSΔΗ

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

Ch. 7 - Prob. 7.1P Ch. 7 - Prob. 7.2P Ch. 7 - Prob. 7.3P Ch. 7 - Prob. 7.4P Ch. 7 - Prob. 7.5P Ch. 7 - Prob. 7.6P Ch. 7 - Prob. 7.7P Ch. 7 - Prob. 7.8P Ch. 7 - Prob. 7.9P Ch. 7 - Prob. 7.10P

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Chapter 7 Solutions