Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
Question
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Chapter 7, Problem 7.39P

(A)

Interpretation Introduction

Interpretation:

to find the number of stages

Concept Introduction:

Initial Pressure P1=1atm

Initial temperature T1=(35+273.15)K

T1=308.15 K

Final pressure P2=50atm

Outlet temperature T2=(200+273.15)K

T2=473.15 K

Efficiency, η=0.65

Volumetric flow rate Vdot=0.5m3sec

CP=3.5×R

Assume air as ideal gas, V=R×T1P1

ndot=VdotV

(B)

Interpretation Introduction

Interpretation:

To calculate the mechanical power required per stage

Concept Introduction:

Initial Pressure P1=1atm

Initial temperature T1=(35+273.15)K

T1=308.15 K

Final pressure P2=50atm

Outlet temperature T2=(200+273.15)K

T2=473.15 K

Efficiency, η=0.65

Volumetric flow rate Vdot=0.5m3sec

CP=3.5×R

Ws(isentropic)=CpT1[(P2P1)RCp1]

(C)

Interpretation Introduction

Interpretation:

To calculate the heat duty for each intercooler

Concept Introduction:

Initial Pressure P1=1atm

Initial temperature T1=(35+273.15)K

T1=308.15 K

Final pressure P2=50atm

Outlet temperature T2=(200+273.15)K

T2=473.15 K

Efficiency, η=0.65

Volumetric flow rate Vdot=0.5m3sec

CP=3.5×R

By first law

Qr=Wr

(D)

Interpretation Introduction

Interpretation:

To find the mass flow rate of cooling water per intercooler

Concept Introduction:

Take Energy balance on each interchanger

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