In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T 1 =450 0 C, P 1 =8000 KPa, m . = 80 k g / s , P 2 =30 KPa, η = 0.8 . Concept introduction: For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

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Answer 1

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Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

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Answer 2

Question

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

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Answer 3

Question

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

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Answer 4

Question

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

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Answer 5

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

Answer 6

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

Answer 7

Chapter 7, Problem 7.16P

Interpretation Introduction

Interpretation:

In an adiabatic steam turbine, find out power output of the turbine, enthalpy and entropy of the exhaust steam for T₁=450⁰C, P₁=8000 KPa, m.=80 kg/s, P₂=30 KPa, η=0.8 .

Concept introduction:

For adiabatic steam turbine, Rankine cycle is used to describe its principle. This cycle is an idealized thermodynamic cycle for which pressure constant and it converts part of heat into mechanical work.. Hence, an isentropic process of turbine is called idealized process. There is no heat transfer occur in the turbine, which indicates that work output is the desired output from a turbine.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 7 - Prob. 7.1P Ch. 7 - Prob. 7.2P Ch. 7 - Prob. 7.3P Ch. 7 - Prob. 7.4P Ch. 7 - Prob. 7.5P Ch. 7 - Prob. 7.6P Ch. 7 - Prob. 7.7P Ch. 7 - Prob. 7.8P Ch. 7 - Prob. 7.9P Ch. 7 - Prob. 7.10P

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Chapter 7 Solutions