Interpretation:
From the given amount of reactants, the maximum amount of product that can be obtained by a
Concept Introduction:
In a chemical reaction, when the reactants gives product, the amount of product formed from the given amount of reactant can be said in terms of yield.
Theoretical yield of a chemical reaction is the maximum amount of the product that can be obtained from the given amount of reactants provided there is no loss or inefficiencies occur. The actual yield of the chemical reaction is the experimental yield that is obtained. Actual yield of the product is always lesser than the theoretical yield. For this, there are two reasons. They are,
- In mechanical process, some of the product is lost. Mechanical process involves the transfer of materials from a container to another container.
- Unwanted side reactions occur in the actual chemical reaction due to impurities present. These are not considered in theoretical yield.
Actual yield is the amount of product that is got from a chemical reaction. The actual yield has to be measured and not calculated.
Percent yield is the term that is used to tell about the product loss. It is the ratio of the actual amount of product that is obtained in a chemical reaction to the theoretical yield multiplied by 100 to give percent. Mathematical equation for percent yield is given as,
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Chapter 6 Solutions
General, Organic, and Biological Chemistry
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- PERCENT YIELD CALCULATIONS PRACTICE PROBLEMS 1.) A reaction with a calculated yield of 93.23 g produced 7.89 g of product. What is the percent yield for this reaction? 2.) 5.96 g of ammonia (17.031 g/mol) react completely according to the reaction 2 NH3(g) → CN2OH4(s) + H2O(I). What is the theoretical yield of urea (CN2OH460.056) for this reaction? 3.) 9.87 g of ammonia (17.031) react completely according to the reaction 2 NH3(g) → CN2OH4(s) + H2O(I). If 13.74 g of urea (CN2OH460.056) are produced, what is the percent yield for this reaction?arrow_forwardQuestion 69. Nice Consider the following equation 2 Mg (s) + O2 (g) → 2MgO (s) The number of moles of oxygen gas needed to react with 4.0 moles of Mg is ______ Group of answer choices 4.0 mole. 3.0 mole. 2.0 mole. 1.0 mole.arrow_forwardNa2CrO4: ________ g/mole Show work please!arrow_forward
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