BIOLOGY:THE ESSENTIALS (LL) W/CONNECT
3rd Edition
ISBN: 9781260670929
Author: Hoefnagels
Publisher: MCG CUSTOM
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Chapter 6.6, Problem 1MC
Summary Introduction
To explain:
The way in which each molecule of glucose theoretically yields 36 ATPs (adenosine triphosphate).
Introduction:
For all living organisms, glucose remains a vital source of energy.
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If 100% of the free energy from the metabolism of glucose is used for the conversion of ADP to ATP, how manymolecules of ATP can be produced from each gram of glucose (mm = 180.16)?
In biological systems, enzymes are used to accelerate the rates of certain bio-
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to glucose (a sugar that cells use for energy). Experiments show that 1 pg mol of
glucoamylase in a 4% starch solution results in a production rate of glucose of 0.6
ug mol/(mL)(min). Determine the production rate of glucose for this system in the
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Ibmol
Answer: 0.0639
ft day
True
False
Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical
amount of ATP your patient can generate under aerobic respiration with this amount of glucose. (Note: Glucose
MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)).
2.8 x 10^24 ATPs
02.9 x 10^21 ATPs
028 x 10-21 ATP5
029 x 10 24 ATPS
Lacks information, cannot be determined
Chapter 6 Solutions
BIOLOGY:THE ESSENTIALS (LL) W/CONNECT
Ch. 6.1 - Prob. 1MCCh. 6.1 - Prob. 2MCCh. 6.1 - Prob. 3MCCh. 6.2 - Prob. 1MCCh. 6.2 - Prob. 2MCCh. 6.3 - Prob. 1MCCh. 6.3 - Prob. 2MCCh. 6.4 - Prob. 1MCCh. 6.4 - Prob. 2MCCh. 6.5 - Prob. 1MC
Ch. 6.5 - How does the Krebs cycle generate CO2, ATP, NADH,...Ch. 6.5 - Prob. 3MCCh. 6.5 - Prob. 4MCCh. 6.6 - Prob. 1MCCh. 6.6 - How does the actual ATP yield compare to the...Ch. 6.7 - Prob. 1MCCh. 6.7 - Prob. 2MCCh. 6.8 - Prob. 1MCCh. 6.8 - Prob. 2MCCh. 6 - Which of the following best describes aerobic...Ch. 6 - Prob. 2MCQCh. 6 - Prob. 3MCQCh. 6 - Prob. 4MCQCh. 6 - Prob. 5MCQCh. 6 - Prob. 6MCQCh. 6 - The CO2 produced in respiration comes mainly from...Ch. 6 - Prob. 8MCQCh. 6 - Prob. 9MCQCh. 6 - Prob. 1WIOCh. 6 - Prob. 2WIOCh. 6 - Prob. 3WIOCh. 6 - Prob. 4WIOCh. 6 - Prob. 5WIOCh. 6 - Prob. 6WIOCh. 6 - Prob. 7WIOCh. 6 - Prob. 8WIOCh. 6 - Prob. 9WIOCh. 6 - Prob. 10WIOCh. 6 - Prob. 1SLCh. 6 - Add the locations of each stage of respiration to...Ch. 6 - Prob. 2PITCh. 6 - Prob. 3PITCh. 6 - Prob. 4PIT
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Similar questions
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- The standard free energy change, ΔGº‘ , for the phosphorylation of glucose to glucose-6-phosphate (glucose + Pi yields glucose-6-P) is +3.3 kcal/mol. The standard free energy change, ΔGº‘ , for the hydrolysis of ATP (ATP yields ADP + Pi) is -7.4 kcal/mol. What is the cellular free energy change, ΔG, if the concentration of glucose is 0.005 M, the concentration of ATP is 0.005M, the concentration of glucose-6-phosphate is 0.001M and the concentration of ADP is 0.001M? Cellular temperature = 37 C Gas constant = 0.00198 kilocalories/mol K Temperature = C + Kelvin (C + 273.15) the answer is supposed to be -6.1 kcal/mol but I am not sure how to get there - please show all stepsarrow_forwardTwenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under fermentative metabolism with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). O2.8 x 10^21 ATPs 01.5 x 10 20 ATPs 01.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined Nexte Previousarrow_forwardA yeast disaccharidase can hydrolyze sucrose and maltose according to the following table: Use Lineweaver-Burk representation to calculate the respective KMs and maximum speeds for each substrate under the conditions of the experiment. Saccharose(mM) Glucose released (µmol10 min) Maltose (mM) Glucose released (µmol10 min) 5 40 5 48 10 60 10 80 20 80 20 120 50 100 50 172 100 109 100 200arrow_forward
- The following reaction would most likely be catalyzed by an enzyme of which class? sucrose + H2O → glucose + fructosearrow_forwardA mutation has occurred that results in phosphofructokinase not being able to bind ATP in its allosteric site. What impact will this mutation have on the production of ATP in the cell? Select one: a. If no ATP can bind to the allosteric site, then phosphofructokinase will not be able to add the phosphate to fructose-6-phosphate to make fructose-1,6-bisphosphate and glycolysis will not work. So no pyruvate, not cellular respiration. b. If ATP cannot bind to the allosteric site, phosphofructokinase will not be activated to make more ATP by substrate-level phosphorylation. c. No impact on the production but will not be able to effectively shut off over production of ATP with feedback inhibition.arrow_forwardEnzymes Calculate the AG between glucose and ATP catalyzed by hexokinase: glucose + ATP glucose-6-phosphate + ADP Is the reaction spontaneous?| Given data: Glucose-6-phosphate + H2O glucose + P; AG' = -3138 cal/mole ATP+H,O =ADP + P. AG' = -7700 cal/molearrow_forward
- Consider the reaction: Galactose 1-phosphate + UDP-glucose → UDP-galactose + glucose 1-phosphate Which pairing correctly matches the enzyme class and Enzyme Commission number for the enzyme that catalyzes this reaction? translocase; 2 translocase; 7 transferase; 2 transferase; 7 isomerase; 5arrow_forwardThe first reaction in glycolysis is the phosphorylation of glucose: Pi + glucose → glucose-6-phosphate + H2O This is a thermodynamically unfavorable process, with ∆G°′ = +13.8 kJ/mol. (a) In a liver cell at 37 °C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each. What would be the equilibrium concentration of glucose-6-phosphate, according to the above data? (b) This very low concentration of the desired product would be unfavorable for glycolysis. In fact, the reaction is coupled to ATP hydrolysis to give the overall reaction ATP + glucose → glucose-6-phosphate + ADP + H+ What is ∆G°′ for the coupled reaction? (c) If, in addition to the constraints on glucose concentration listed previously, we have in the liver cell ATP concentration = 3 mM and ADP concentration = 1 mM, what is the theoretical concentration of glucose6-phosphate at equilibrium at pH = 7.4 and 37 °C? The answer…arrow_forwardConsider the graphic representation shown below for the free energy change for the overall reaction of Fructose-6-phosphate and ATP to form the products Fructose-1,6-biphosphate and ADP in the presence (blue line) or absence (red line) of enzyme. Match each of the arrows (labeled A, B, C, or D) indicated in the graph with an apropriate description by dragging the letters into their corresponding box. C D reactants Fructose-6-phosphate + ATP A products Fructose-1,6-biphosphate + ADP Progress of the Reaction Reset Help D BAc В C Energy of activation for the forward reaction in the absence of enzyme Energy of activation for the forward reaction Energy of activation for the reverse reaction in absence AG for the reaction the presence of enzyme of enzyme Energyarrow_forward
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