Laboratory Manual For Human Anatomy & Physiology
4th Edition
ISBN: 9781260159363
Author: Martin, Terry R., Prentice-craver, Cynthia
Publisher: McGraw-Hill Publishing Co.
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Chapter 62, Problem 3.5A
Color blindness is an example of X-linked inheritance. Hemophilia is another example of X-linked inheritance, also from a recessive allele (h). The dominant allele (H) determines whether the person possesses normal blood clotting. A person with hemophilia has a permanent tendency for hemorrhaging due to a deficiency of one of the clotting factors (VIII—antihemophilic factor). Determine the offspring from a cross of a mother who is a carrier (heterozygous) for the disease and a father with normal blood coagulation.
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Hemophilia A is caused by a recessive X-linked allele that encodes a defective form of a clotting protein. If a affected father and a mother who is known to not be a carrier have children, what percentage of female offspring will have hemophilia?
In humans, the genes for red-green color blindness (R = normal, r = color blind) and hemophilia A (H = normal, h = hemophilia) are both X-linked and only 3 map units apart.
Suppose a woman has four sons, and two are color blind but have normal blood clotting and two have hemophilia but normal color vision. What is the probable genotype of the woman?
HR/hr
Hr/hr
hr/hR
Hr/hR
HR/Hr
Construct pedigree charts using the inheritance of hemophilia in figure 92 (page 113). This is X-linked inheritance so you are required to label XX for females and XY for males. The gene responsible for the trait is represented by the superscript which should be specified in the legend.
Chapter 62 Solutions
Laboratory Manual For Human Anatomy & Physiology
Ch. 62 - The term _________ is used for a person possessing...Ch. 62 - The term _________ is used for the appearance of...Ch. 62 - The _________ is a genetic tool to simulate all...Ch. 62 - Prob. 4PLCh. 62 - Which of the following represents a dominant human...Ch. 62 - An attached earlobe is considered a recessive...Ch. 62 - A diploid chromosome number of 46 and a haploid...Ch. 62 - The possession of freckles is considered a...Ch. 62 - Single penny tossed 20 times and counting heads...Ch. 62 - Determine the results from a cross of a mother who...
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- An allele responsible for Marfan syndrome Section 13.4 is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the allele if one parent does not carry it and the other is heterozygous?arrow_forwardFamilial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?arrow_forwardThe gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?arrow_forward
- An individual with 46, XX genotype is diagnosed with Duchenne-type Muscular Dystrophy, a recessive X-linked disorder. Genetic tests confirm that this individual is a heterozygote for this disorder. Briefly, but specifically, explain how it’s possible that they are showing symptoms of this disorder.arrow_forwardA mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?arrow_forwardIn humans, the ABO blood type is under the control of autosomal multiple alleles. Color blindness is a recessive X-linked trait. If two parents who are both type A and have normal vision produce a son who is color blind and is type O, what is the probability that their next child will be a female who has normal vision and is type O?arrow_forward
- Hemophilia is another example of an X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia?arrow_forwardHemophilia is another example of a X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia? As in the previous question, you must also give the gender of the child in your genotype and phenotype descriptions here.arrow_forwardIn humans, the genes for red-green color blindness (R=normal, r=color-blind) and hemophilia A (H=normal, h=hemophilia) are both X-linked and only 3 map units apart. Suppose a woman has four sons, and two are colorblind and have hemophilia and two are normal. What is the probable genotype of the woman? Group of answer choices HR/hr Hr/hr hr/hr Hr/hRarrow_forward
- X-linked Recessive Inheritance A gene is described as X-linked when it occurs on the X chromosome and not the Y. Our convention is to indicate X-linkage by attaching the appropriate gene symbol as a superscript on the letter X. Commonly, the wild-type (+) allele is indicated with only a "+" to avoid having to type a superscript on a superscript. For example, a female that is heterozygous and carrying a recessive mutant allele is indicated as X+Xm. Note the convenience of the shorthand + for m+ in this situation. A mutant male has the genotype XmY. When working with X-linked inheritance, always include the X and Y chromosomes in the descriptions of genotypes, and include the sex (male or female) in the descriptions of the phenotypes (e.g., mutant male, wild-type female, etc.). Here are the genotypes and associated phenotypes for X-linked recessive inheritance: X+X+ Wild-type female X+Xm Wild-type female xmxm Mutant female X+Y xmy Wild-type male Mutant malearrow_forwardautosomal recessive allele (not sex-linked). Omplete the following monohybrid crosses for different types neritance pattefh autosomal dominant, sex linked recessive, and dominant inheritance. Inheritance of autosomal recessive traits Female parent phenolype: Example: Albinism Albinism (lack of pigment in hair, eyes and skin) is inherited as an Male parent phenatype: Using the codes: PP Pp (normal) (albino) la) Enter the parent phenotypes and complete the Punnett square for a cross between two carrier genotypes. A Give the ratios for the phenotypes from this cross. Pp (carrier) eggs sperm Phenotype ratios: Inheritance of autosomal dominant traits Example: Woolly hair Woolly hair is inherited as an autosomal dominant allele. Each affected individual will have at least one affected parent. Using the codes: WW (woolly hair) Female parent phenotype: Male parent phenotype: Ww (woolly hair, heterozygous) W w (normal hair) (a) Enter the parent phenotypes and complete the Punnett square for a…arrow_forwardO. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S Farrow_forward
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