Laboratory Manual For Human Anatomy & Physiology
4th Edition
ISBN: 9781260159363
Author: Martin, Terry R., Prentice-craver, Cynthia
Publisher: McGraw-Hill Publishing Co.
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Chapter 62, Problem 3.1CT
Assume that the genes for hairline and earlobes are on different pairs of homologous chromosomes. Determine the genotypes and
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In currant moths, their Light color is sex-linked and recessive (d) to dark color (D).
Question: What are the genotype and the phenotype of the parents if a certain cross yields ½ dark and ½ light colored females and all dark males?
Take note that female moths are heterogametic.
Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY.
(A) For a standard monohybrid cross (Ss ´ Ss), what proportion of the offspring will have the genotype ss? (Express the proportion as a simple fraction)
(B) For the following cross (SsXX ´ SsXY), what proportion of the offspring will have the genotype Ss? (Express the proportion as a simple fraction)
(C) What proportion will have the genotype XX? (Express the proportion as a simple fraction)
(D) What proportion will have the genotype SsXX? (Express the proportion as a simple fraction)SHOW YOUR WORK
Two plants in a cross were each heterozygous for two gene pairs (AB /ab) whose loci are linked and
30 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.)
Assuming that crossing over occurs during the formation of both male and female gametes and
that the A and B alleles are dominant, determine the phenotypic ratio of their offspring.
Part E: What proportion of the offspring of two
plants (both (AB/ab ) will be A - B- if the genes are 30
mu apart?
Part F: What proportion of the offspring of two
plants (both (AB/ab)) will be A - bb if the genes are 30
mu apart?
Part G: What proportion of the offspring of two
plants (both (AB/ab)) will be aaB- If the genes are 30
mu apart?
Part H: What proportion of the offspring of two
plants (both (AB/ab)) will be aabb if the genes are 30
mu apart?
Chapter 62 Solutions
Laboratory Manual For Human Anatomy & Physiology
Ch. 62 - The term _________ is used for a person possessing...Ch. 62 - The term _________ is used for the appearance of...Ch. 62 - The _________ is a genetic tool to simulate all...Ch. 62 - Prob. 4PLCh. 62 - Which of the following represents a dominant human...Ch. 62 - An attached earlobe is considered a recessive...Ch. 62 - A diploid chromosome number of 46 and a haploid...Ch. 62 - The possession of freckles is considered a...Ch. 62 - Single penny tossed 20 times and counting heads...Ch. 62 - Determine the results from a cross of a mother who...
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- Indicate whether to cross (i) mutant females with wild-type males, or (ii) mutant males with wild-type females, or (iii) both (i.e. reciprocal crosses), to produce an F1 generation that will enable you to determine if the traits are dominant or recessive, and if they are sex-linked (on the X chromosome). Draw mating diagrams and Punnett squares to support your answer. To determine whether the mutant genes are independent or linked, a testcross is more appropriate than using data from the F2 generation. Knowing which are the recessive genes, indicate which individuals you would mate in this testcross. Draw a mating diagram & use the forked line method to predict the outcome of this cross. Conduct the appropriate testcross using Drosophila Lab, record your results and indicate whether the three mutant genes are inherited independently or whether they are linked? Include a chi square analysis to support your conclusion.arrow_forwardDuring the process of Meiosis an individual's alleles for each trait are independently sorted to make unique gametes. A person is heterozygous for the Freckles phenotype (Ff) and also heterozygous for the PTC-tasting phenotype (Tt). This person's genotype for these two traits is represented as FfTt. A) How many unique gametes could be produced by this individual if you consider these two traits? B) List the different allele combinations that could result.arrow_forwardIn the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosisarrow_forward
- Gene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?arrow_forwardHuman females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X chromosome alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an allele on an X chromosome, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X chromosome allele, how many types of gametes can she produce with respect to that allele?arrow_forwardDraw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.arrow_forward
- Discuss the following concepts: (a) homologous chromosomes x ½ = 2) (b) diploidy (c) haploidy Answer the following questions with either True or False. Provide a justification for your choice. (a) Alleles occupy different loci on homologous chromosomes. (b) Although alleles govern the same kinds of characteristics, they do not necessarily contain identical information. (e) The special region on a duplicated chromosome that holds the sister chromatids together is a centrosome. What names are assigned to chromosomes on the basis of their centromere placement, and where is the centromere located in each case?arrow_forwardTwo plants in a cross were each heterozygous for two gene pairs (AB/ab) whose loci are linked and 10 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.) Assuming that crossing over occurs during the formation of both male and female gametes and that the A and B alleles are dominant, determine the phenotypic ratio of their offspring. Part D If the two genes are 15 mu apart and the plant is (Ab/aB), what proportion of gametes from a signal plant will be ab? Part E What proportion of the offspring of two plants ( both (Ab/aB)) will be A_B_ if the genes are 15 mu apart? Part F What proportion of the offspring of two plants ( both (Ab/aB)) will be A_bb if the genes are 15 mu apart? Part G What proportion of the offspring of two plants ( both (Ab/aB)) will be aaB_ if the genes are 15 mu apart? Part H What proportion of the offspring of two plants ( both (Ab/aB)) will be aabb if the genes are 15 mu apart? How would I solve these?arrow_forwardIn fruit flies, eye color is carried on the X chromosome. The allele for red eyes is dominant over its recessive allele, white eyes. -Cross a heterozygous female to a white-eyed male 1st Question to answer ---- How many genotypes are possible among the offspring? 2nd Question to answer ---- How many phenotypes are possible among the offspring? 3rd Question to answer ---- What is the probability of getting a red-eyed male? 4th Question to answer ---- What is the probability of getting a white-eyed male? 5th Question to answer ---- What is the probability of getting a red-eyed female? 6th Question to answer ---- What is the probability of getting a white-eyed female? 7th Question to answer ---- What is the probability of getting a red-eyed offspring? 8th Question to answer ---- What is the probability of getting a white-eyed offspring?arrow_forward
- Sex determination in birds is different from that in humans. The sex chromosomes in birds are called Z and W, because males have two of the same chromosome (ZZ), whereas females have two different chromosomes (ZW). There is a Z-linked allele in some birds that causes the death of the embryo when the normal dominant allele is not present. What would be the sex ratio in the living offspring of a cross between a male heterozygous for the lethal allele and a normal female? A) What are the genotypes of the parents? Male____ Female____ B) Which gametes would each form? Male____ Female____ C) Draw your Punnett square below and determine the sex ratios of living offspring.arrow_forwardIn a testcross for two genes, what types of gametes are produced with (a) complete linkage, (b) independent assortment, and (c) incomplete linkage?arrow_forwardAn individual that is homozygous AABBcc is crossed to an individual that is homozygous aabbCC producing F1 individuals with genotype AaBbCc. Assume that the A, B, and C loci are all on the same chromosome. One chromatid at the start of meiosis (before crossing over) has the alleles A, B, and c. What alleles are on its sister chromatid? What alleles are on the homolog? Group of answer choices A. Sister chromatid ABc, Homolog no way to tell B. Sister chromatid ABC, Homolog abc C. Sister chromatid ABc, Homolog abC D. Sister chromatid abC, Homolog ABcarrow_forward
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