Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 6, Problem 6.8P
(a)
To determine
The maximum dry density of compaction and the optimum moisture content.
(b)
To determine
The field dry density and range of acceptable moisture content.
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The detailed results of a standard Proctor test on a soil
classified as CL-ML and group name silty clay with sand are
shown in the table below. Determine the maximum dry unit
.weight and optimum water content
.Diameter of mould = 4 in
Height of mould = 4.584 in
.Volume of mould 1/30 ft3
.Weight of mould, M = 4.45 lb
Unit weight data
Water content data
Mass of can and
Weight of wet soil
and mold (Ibs)
Mass of can
(grams)
Mass of can and
wet soil (grams)
dry soil (grams)
M
M..
M.
M.
111.48
155.08
7.32
114.92
46.50
163.12
190.43
193.13
7.57
46.43
7.68
7.74
178.64
46.20
178.24
46.50
7.65
188.77
171.58
46.10
a. 100 cm3 saturated sample of quartz sand is weighed, gravity drained, weighed, oven dried, and weighed again. The saturated, gravity-drained, and oven-dried weights are 130g, 110 g, and 105 g, respectively. Using these data, calculate the following quantities.
i. Dry bulk density
ii. Porosity
iii. Degree of saturation after gravity drainage
iv. Specific yield
b. Given that the soil sample in part (a) above has porosity of 35%.
i. Determine the void ratio of this soil.
ii. If 50% of the void space is filled with water, with the remaining 50% filled with air, determine the volumetric water content, θ.
iii. and the degree of saturation, S.
1. The results of a standard Proctor test are given in the following table.
a. Determine the maximum dry unit weight of compaction and the optimum moisture content,
given that the Proctor mold volume is 1/30 ft³.
b. Determine the void ratio and the degree of saturation at the optimum moisture content
given G₁= 2.68.
Trial no.
1234567
Weight of moist soil in the mold (lb)
3.92
4.12
4.29
4.37
4.45
4.35
4.20
Moisture content (%)
5.0
7.5
10.0
12.5.
15
17.5
20.0
Chapter 6 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- A compaction test was conducted in the laboratory and the following information was obtained: • The weight of the compacted soil specimen (including the mold) was determined to be 3815 • The volume of the mold = 1/30 ft³ (944 cm³) • The weight of the mold = 2050 g • The water content in the soil was determined to be 9.1% Find the dry unit weight of the soil (in units of kN/m³).arrow_forwardHomework #3 The results of a standard Proctor test are given in the following table. a. Determine the maximum dry unit weight of compaction and the optimum moisture content. Given: mold volume =943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.68. Trial no. Weight of moist soil in the mold (kg) Moisture content (%) 1.78 5.0 1.87 7.5 3 1.95 10.0 4 1.98 12.5 5 2.02 1.97 15 17.5 7 1.90 20.0arrow_forwardThe results of a standard Proctor test are given in the following table. Given: Mold volume 1/30 ft' and Gs = 2.69. Determine the void ratio and the degree of saturation at the optimum moisture content. Weight of moist soil Moisture in the mold (lb) Trial no. content (%) 1 3.7 8.6 2 4.15 10.6 4.69 12.5 4 4.62 14.9 5 4.02 16.7 6. 3.63 18.3arrow_forward
- A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor tests at optimum moisture content are given in the Table below: Standard Proctor test Modified Proctor test Mass of wet soil in the mold (g) 1800 2000 Volume of Proctor mold (cm2) 900 1000 Optimum moisture content (%) 12 10 At the field, a sample of 600 cm3 of this soil weighted 1200 g. The weight of water in this sample was 200 g. Find the following: 1- Degree of compaction (Relative compaction) (R%) at Standard Proctor test. 2- Degree of compaction (Relative compaction) (R%) at Modified Proctor test.arrow_forwardThe results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m3) of compaction and the optimum moisture content. Volume of Proctor mold (cm3) Mass of wet soil in the mold (kg) Moisture content (%) 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 1.6 1.71 1.77 1.83 1.86 1.88 1.87 1.85 9.9 10.6 12.1 13.8 15.1 17.4 19.4 21.2arrow_forwardA sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor tests at optimum moisture content are given in the Table below: Standard Proctor test Modified Proctor test Mass of wet soil in the mold (g) 1800 2000 Volume of Proctor mold (cm?) 900 1000 Optimum moisture content (%) 12 10 At the field, a sample of 600 cm3 of this soil weighted 1200 g. The weight of water in this sample was 200 g. Find the following: 1- Degree of compaction (Relative compaction) (R%) at Standard Proctor test. 2- Degree of compaction (Relative compaction) (R%) at Modified Proctor test.arrow_forward
- H.W The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit weight and optimum water content. Diameter of mould = 4 in. Height of mould = 4.584 in. Volume of mould = 1/30 ft3. Weight of mould. M = 4.45 lb. Unit weight data Water content data Weight of wet soil and mold (Ibs) Mass of can and dry soil (grams) Mass of can and Mass of can wet soil (grams) (grams) M. M. м. 7.32 114.92 111.48 155.08 46.50 7.57 163.12 46.43 7.68 190.43 178.64 46.20 46.50 7.74 193.13 178.24 7.65 188.77 171.58 46.10arrow_forwardA liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the plasticity index of this clay? (Use Interpolation) Group of answer choices 15.74% 18.99% 18.85% 17.63% Please answer this asap for upvote. thanksarrow_forward(c) A sample of clay having a mass of 675 gm was coated with paraffin wax. The combined mass of the clay and the wax was found to be 682 gm. The volume was found by immersion in water as 345 ml. The sample was then broken to open. The water content and specific gravity of solids were found to be 15 % and 2.70 respectively. Calculate the bulk density of soil, its void ratio, and degree of saturation. Take specific gravity of wax as 0.89.arrow_forward
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