Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 6, Problem 6.5P
To determine
The relative compaction in the field.
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b. Compute the plastic limit.
C. Compute the natural water content.
d. Compute the plasticity index.
e. Compute the liquidity index.
f. Compute the consistency index.
PROBLEM NO. 4
From the table shows a summary of a liquid limit and
plastic limit test.
LIQUID LIMIT TEST
Soil Wt. of wet Wt. of dry Water No. of
Sample Soil (kg) Soil (kg)
A.
Content Blows
9.5
6.7
28
B
7.95
5.54
20
8.21
5.69
18
D.
12.85
8.83
13
PLASTIC LIMIT TEST
Wt. of Dry
Soil(kg)
Soil
Wt, of Wet
Sample
Soil(kg)
9.05
7.35
2
8.66
7.01
Natural Water Content
Scil
Wt. of
Wt. of
Sample
Wet Soil
Dry Soi!
1
9.69
7.0
9.47
6.86
a. Compute the liquid limit.
b. Compute the plastic limit.
C. Compute the natural water content.
d. Compute the plasticity index.
e. Compute the liquidity index
GEOTECHNICAL ENGINEERING 1
Homework #3
The results of a standard Proctor test are given in the following table.
a. Determine the maximum dry unit weight of compaction and the optimum
moisture content. Given: mold volume =943.3 cm'.
b. Determine the void ratio and the degree of saturation at the optimum moisture
content. Given: G, = 2.68.
Trial no.
Weight of moist soil in the mold (kg)
Moisture content (%)
1.78
5.0
1.87
7.5
3
1.95
10.0
4
1.98
12.5
5
2.02
1.97
15
17.5
7
1.90
20.0
The results of a standard Proctor test are given below. Determine the maximum dry
unit weight of compaction and the optimum moisture content.
Volume of
Proctor mold
(ft³)
1/30
1/30
1/30
1/30
1/30
Weight of
wet soil
in the mold
(lb)
3.26
4.15
4.67
4.02
3.63
Moisture
content
(%)
8.4
10.2
12.3
14.6
16.8
Chapter 6 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- The results of a standard Proctor test are given in the following table. Given: Mold volume 1/30 ft' and Gs = 2.69. Determine the void ratio and the degree of saturation at the optimum moisture content. Weight of moist soil Moisture in the mold (lb) Trial no. content (%) 1 3.7 8.6 2 4.15 10.6 4.69 12.5 4 4.62 14.9 5 4.02 16.7 6. 3.63 18.3arrow_forward1. The results of a standard Proctor test are given in the following table. a. Determine the maximum dry unit weight of compaction and the optimum moisture content, given that the Proctor mold volume is 1/30 ft³. b. Determine the void ratio and the degree of saturation at the optimum moisture content given G₁= 2.68. Trial no. 1234567 Weight of moist soil in the mold (lb) 3.92 4.12 4.29 4.37 4.45 4.35 4.20 Moisture content (%) 5.0 7.5 10.0 12.5. 15 17.5 20.0arrow_forward(c) A sample of clay having a mass of 675 gm was coated with paraffin wax. The combined mass of the clay and the wax was found to be 682 gm. The volume was found by immersion in water as 345 ml. The sample was then broken to open. The water content and specific gravity of solids were found to be 15 % and 2.70 respectively. Calculate the bulk density of soil, its void ratio, and degree of saturation. Take specific gravity of wax as 0.89.arrow_forward
- 6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 2 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1.83 13.8 5 943.3 1.86 15.1 943.3 1.88 17.4 7 943.3 1.87 19.4 8 943.3 1.85 21.2arrow_forward6. Following is the result of 8 trials of à standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 943.3 1.68 9.9 2 943.3 1.71 10.6 943.3 1.77 12.1 4 943.3 1.83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2arrow_forwardA 627-g sample of sand was found to have the following amounts of material retained on each sieve/pan: 3/8 in. = 22 g, No. 4 = 45 g, No. 8 = 96 g, No. 16 = 122 g, No. 30 = 163 g. No. 50 86 g, No. 100 = 51 g, No. 200 = 30 g, pan = 11 g a. Calculate the fineness modulus of the sand. b. Is this sieve analysis valid for acceptance purposes? Explain why. c. Does the sand meet the particle size criteria of ASTM C 33. Fully justify your answer (list and check all relevant criteria from ASTM C33)arrow_forward
- A hydrometer test was conducted on the material passing sieve No, 200 and the results are listed in the table below, The results of sieve analysis on the soil showed that the percentage passing No. 4 was 90 % and that passing No. 200 was 20 %. Estimate the clay size fraction in the soil. Table : Results of hydrometer test diameter (mm) 0.0700 0.0400 0.0150 0.0020 % finer (combined) 19 finer 95 80 16 65 13 45 0.0010 30 6 Select one:arrow_forwardIn a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: O There is no clay in the sample ) the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample O 95.5% of the sample is Sand and Silt O Oarrow_forward2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture contentarrow_forward
- The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m3) of compaction and the optimum moisture content. Volume of Proctor mold (cm3) Mass of wet soil in the mold (kg) Moisture content (%) 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 1.6 1.71 1.77 1.83 1.86 1.88 1.87 1.85 9.9 10.6 12.1 13.8 15.1 17.4 19.4 21.2arrow_forwardThe resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold (cu.m) Wt. of wet soil in mold (kg) Moisture (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture contentarrow_forwardDerive the relation between void ratio (e), specific gravity of particles (G) and moisture content at full saturation (w). A certain sample of saturated soil in a container weighs 0.65 N. On drying in an oven in the container it weighs 0.60 N. The weight of container is 0.35 N. The grain specific gravity is 2.65. Determine the void ratio, water content, and bulk unit weight. Show Solutionsarrow_forward
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