A hydrometer test was conducted on the material passing sieve No. 200 and the results are listed in the table below, The results of sieve analysis on the soil showed that the percentage passing No. 4 was 90 % and that passing No. 200 was 20 %. Estimate the clay size fraction in the soil.
Q: A soil specimen weighs 30 grams oven dried. When mixed with 7.50 cc of water, the soil is at its…
A:
Q: Q.10 melindiical analysis on four different samples designated as A, B, Cand D were carried out in a…
A:
Q: A particle analysis test was conducted on a dry soil. The total mass used in test was (500 grams).…
A:
Q: 10. The results of a Standard Proctoretest is tabulated as follows: (SEE PICTURE) Determine the…
A:
Q: The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty…
A: Vulume of the mould V=13 ft3=943.89 cm3mass of water =mass of cane and wet soil Mw-mass of cane and…
Q: A field technician submits the results of a sand cone test for review. Prior to the test, the…
A:
Q: From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow…
A:
Q: find the following: a. What is the value of the percent passing for sieve with 2 mm. opening in…
A: Total weight of soil sample=500gm Weight remain in pan=500-wt retained in all mesh D10- size of mesh…
Q: A sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…
A:
Q: a sample of silty sand in a 150 mm diameter mold. The maximum dry unit weight is 19.6 kN/m3 and…
A: According to given data A modified proctor compaction test is performed on a sample of silty sand…
Q: What is the maximum weight of the soil sample? B. What is the minimum weight of the soil sample?…
A: GEO TECHNICAL ENGINEERING:
Q: Consider the grain size gradation curve for the soil shown in the image below and classify the soil…
A: Look at the % passing through sieve no 200=20<50%⇒COARSE GRAINED SOIL
Q: LL=25% PI=15% Cu=_____
A: From graph :D60=0.05mmD30=0.0026mmD10=0.0007mmFind uniformity coeff:Cu=D60D10=0.050.0007=71.4285Find…
Q: Data from the sieve analysis showed that 65% of the particles passed through 0.075 mm sieve. The…
A:
Q: Classify the following soils using the Unified soil classification system. Give the group symbols…
A: The USCS soil classification table is given below:
Q: A liquid limit test was performed on a soil sample. It was found out that the moisture content at 21…
A:
Q: b) During lab investigation the soil fall under "CL". Comment on its type and usefulness.
A: CL is Lean Clay {falls under Average NC clays of fine grained soil type} It is a clay of low to…
Q: 2. The following laboratory test results for Atterberg limits and particle-size distribution (sieve…
A: Given Soil sample and asked to classify according AASHTO system. Liquid limit=31 Plastic…
Q: A soil has a liquid limit of 61 and plastic limit of 30. A moisture content test yielded the…
A: Given: liquid limit Plastic limit Mass of soil before oven drying Mass of soil after oven drying…
Q: Q.12.32 Mechanical analysis on four different samples designated as A, B, Cand D were carried out in…
A:
Q: The same soil sample has a natural moisture content of 30% and was subject to the Atterberg Limits…
A:
Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…
A:
Q: The results of a standard Proctor test are given in the following table. Given: Mold volume : 1/30…
A:
Q: A clay sample coated with paraffin wax is weighing 700 gm including the weight of the wax. When the…
A:
Q: Note: Answer 5 questions only. Q1: A cylindrical soil specimen of 50 mm diameter and 100 mm long is…
A: Hi there!! since you have asked multiple questions, as per our honour codes we will solve the first…
Q: During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following…
A: Table : N MC in % 14 38.4 16 36.5 20 33.1 28 27 Graph :
Q: A sample of soil was retrieved and tested in the laboratory. Its water content was 29%, the bulk…
A: Given information: So, the void ratio =e = 0.816
Q: VA soil sample has a weight of 0.7 kg and the volume was found to be 3.5 x 10-4 m3 . After drying…
A:
Q: A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…
A: Mechanical Grain Size Analysis Sieve Number Percentage Passing Retained % 1 in 100 0 0.75 in…
Q: A 5-lb soil sample was taken from a fill. The volume of the hole from which the sample was taken was…
A:
Q: The following results were obtained by a mechanical sieve analysis. classify the soil using the…
A: Given :- Sieve analysis % passing by weight is as follows: No.4 = 100% No. 40 = 70% No.200 = 30%…
Q: Q.82 Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a…
A:
Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…
A:
Q: A liquid limit test was performed on a soil sample. It was found out that the moisture content at 17…
A: Liquid limit is water content where no. of blows is 25
Q: A soil sample has a unit weight of 1.9 g/cc and w=12%. If Gs of solids is 2.65, determine the…
A: INTRODUCTION: Unit Weight : It is the ratio of weight of material accompanied to the unit volume of…
Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…
A:
Q: Following are the results from the liquid and plastic limit test for a soil. No. of blows (N)…
A: Given Natural water content 26.5 % Liquid limit is calculated corresponding to no.of blows 25
Q: The values of liquid limit, plastic limit and shrinkage limit of a soil were reported as below : w =…
A:
Q: A 5-lb soil sample was taken from a fill. The volume the hole from which the sample was taken was…
A:
Q: Example 2.21:The liquid limit and plastic limit of a soil are 50 % and 25 %, respectively When the…
A:
Q: the results of the sieve analysis done on a soil are shown below: determine its classification…
A: To determine the classification of the given soil based on USCS. Given, Sieve No. Sieve Opening…
Q: A specimen of moist soil weighing 122 g has a total specific gravity of 1.82. The unit weight of…
A:
Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…
A:
Q: 9% of a soil is retained on No. 4 sieve, and 11% passes the No. 200 sieve. It is also known that…
A:
Q: A liquid limit test was performed on a soil sample. It was found out that the moisture content at 14…
A:
Q: The following data were obtained from the atterberg limits test for a soil: Liquid limit = 41.0%…
A: a.) The expression for plasticity index of the soil is given as IP=Liquid limit-plastic…
Q: The table below shows the laboratory results of the sieve analysis of Soil A and B. What is the…
A:
Q: Question 11 The results of the particle-size analysis of a soil are as follows: • Percent passing…
A:
Q: A sample of inorganic soil has 100% passing the No. 4 sieve and 75% passing the No. 200 sieve.…
A: Given data, % passing No. 4 sieve (4.75 mm) = 100 No. 200 sieve (0.075 mm) = 75 Liquid Limit LL =…
Q: Question 5 The results of the particle-size analysis of a soil are as follows: • Percent passing the…
A:
Step by step
Solved in 2 steps
- 3- Following are the results of a laboratory consolidation test on a sample of undisturbed clay obtained from the field. Final height of specimen (in) Pressure, o' (lb/ft') 1 0.9917 1,000 2,000 4,000 0.9843 0.956 0.9142 8,000 0.8685 16,000 0.8228 32.000 The height of the specimen at the beginning of the test was 1.0 inch, and the diameter was 2.5 inches. The moist specimen weighed 0.31 lb and the water content was determined to be 19%. Estimate the compression index and the preconsolidation pressure from the e-log o' curve. (Plot in Excel) Given: Gs = 2.7.A liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the plasticity index of this clay? (Use Interpolation) Group of answer choices 15.74% 18.99% 18.85% 17.63% Please answer this asap for upvote. thanksIn falling head permeability test the initial head was 350 mm and the final head was 60 mm. The cross-sectional area of the burette was 200 mm2. The sample was 50 mm in diameter and 105 mm long. If the test took 8 hours and 30 minutes, what was the coefficient of permeability of the soil in m/s?
- Permeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio (e) 0.65 1.02 Temperature °℃ 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10-¹ At 40° C, n = 6.54 × 10-¹ g sec/cm² and p $0.997 g/cm³ = = 0.992 g/cm³Permeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio Temperature °C (e) 0.65 1.02 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10¹ At 40° C, n = 6.54 × 10 g sec/cm² and p 8 0.997 g/cm³ = 0.992 g/cm³3- A series of standard Proctor compaction tests were performed on soil and the obtained results are presented in Figure below. The volume of the standard mould was 1 x 10³ m³ and Gs = 2.65. 1.82 1.80 1.78 1.76 What is the degree of saturation of the sample compacted to the maximum dry density? Estimate the volume of air (in m3) in the sample compacted to 15% water content. The void ratio of this soil in its loosest state is 1.74 1.72 1.70 1.68 1.66 0.623. Estimate the relative density of the soil sample compacted to 11% water content? 10 11 12 13 14 15 16 17 18 19 20 21 22 Water content (%) Dry density (g cm-3)
- A liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquid limit of this clay? (Use Interpolation) Group of answer choices 39.85% 39.99% 36.74% 38.63% Please answer this asap for upvote. ThanksQuestion 2 The result presented in Table Q2a were obtained from a consolidated drained (CD) triaxial test on a normally consolidated clay sample of 75mm height x 38mm diameter tested at a confining pressure of 50 kPa. Table Q2a. CD triaxial test result Axial strain (%) 1 2 5 10 15 Applied force (kN) 0.01 0.03 0.05 0.08 0.10 Page 3 of 6 (a) Draw the Mohr circle for each stress state in the sample and the total stress path (TSP) throughout the test and determine the slope of the TSP to the horizontal.The following results were obtained from a liquid limit test on a soil using a liquid limit device. The in-situ water content of this clay is 38% and the plastic limit is 20%. (Note: show the semi-log graph for the determination of the LL) Determine the following: (a) Liquid Limit of the soil, (b) Plasticity Index of the soil, and (c) Liquidity Index of the soil (d) shrinkage limit using the plasticity chart
- Refer to the soil in Problem 4.5. Using the Casagrande plasticity chart, graphically estimate the shrinkage limit of the soil as shown in Figure 4.22. 4.5 The following data were obtained by conducting liquid limit and plastic limit tests on a soil collected from the site. Liquid limit tests: Plastic limit test: PL = 19.3% a. Draw the flow curve and determine the liquid limit. b. Using the Casagrande plasticity chart (Figure 4.21), determine the soil type.Following results are obtained for a liquid limit test using a fall cone device. Estimate the liquid limit of the soil and the flow index.A consolidated-undrained tri-axial test was conducted on a normally conslidated clay sample and the results are follows: Chamber confining pressure= 119kpa Deviator Stress at failure=90 kpa Pore water pressure= 58kpa These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 156 kpa. Use stored value. Answer to 5 decimal places.