Applied Fluid Mechanics (7th Edition)
7th Edition
ISBN: 9780132558921
Author: Robert L. Mott, Joseph A. Untener
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 6, Problem 6.40PP
Water flows at 1.20 m/s in a circular section with a 150 mm inside diameter. Calculate the velocity of flow in a 300-mm-diameter section connected to it.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
الثانية
Babakt
Momentum equation for Boundary Layer
S
SS
-Txfriction dray
Momentum equation for Boundary Layer
What laws are important for resolving
issues
2 How to draw.
3 What's Point about this.
R
αι
g
The system given on the left, consists of three pulleys and
the depicted vertical ropes.
Given:
ri
J₁, m1
R = 2r;
απ
r2, J2, m₂
m1; m2; M3
J1 J2 J3
J3, m3
a) Determine the radii 2 and 3.
B: Solid rotating shaft used in the boat with high speed shown in Figure. The amount of power transmitted at the
greatest torque is 224 kW with 130 r.p.m. Used DE-Goodman theory to determine the shaft diameter. Take the
shaft material is annealed AISI 1030, the endurance limit of 18.86 kpsi and a factor of safety 1. Which criterion
is more conservative?
Note: all dimensions in mm.
1
AA
Motor
300
Thrust
Bearing
Sprocket
100
9750
เอ
Chapter 6 Solutions
Applied Fluid Mechanics (7th Edition)
Ch. 6 - Convert a volume flow rate of 3.0 gal/min to...Ch. 6 - Convert 459 gal/min to rrP/s.Ch. 6 - Convert 3720 gal/min to mJ/sCh. 6 - Convert 34.3 gal/min to mJ/sCh. 6 - Convert a volume flow rate of 125 L/min to m3/s.Ch. 6 - Convert 4500 L/min to m5/s.Ch. 6 - Convert 15 000 L/minto m3/s.Ch. 6 - Convert 459 gal/min to L/mninCh. 6 - Convert 3720 gal/min to L/minCh. 6 - Convert 23.5cm2/stom3/s.
Ch. 6 - '6.11 Convert 0.296cm5/stom3/s.Ch. 6 - Convert 0.105 cm3/s to L/minCh. 6 - Convert 3.53103m3/s to L/min.Ch. 6 - Convert 5.26106m3stoL/min.Ch. 6 - Prob. 6.15PPCh. 6 - Convert 20 gal/min to ft'/s.Ch. 6 - Convert 2500 gal/min to ft5/s.Ch. 6 - Convert 2.50 gal/min to ft3/s.Ch. 6 - Convert 125 ft3/s to gal/minCh. 6 - Convert 0.060 ft3/s to gal/min.Ch. 6 - Convert 0.03 ft5/s to gal/minCh. 6 - Convert ft5/s sto gal/minCh. 6 - Table 6.21 lists the range of typical volume flow...Ch. 6 - Table 6.2 lists the range of typical volume flow...Ch. 6 - A certain deep-well pump for a residence is rated...Ch. 6 - A small pump delivers 0.85 gal/h of liquid...Ch. 6 - A small metering pump delivers 11.4 gal of a water...Ch. 6 - A small metering pump delivers 19.5 mL/min of...Ch. 6 - Water at 10 C is flowing at 0.075 m3/s Calculate...Ch. 6 - Oil for a hydraulic system (sg =0.90 ) is flowing...Ch. 6 - A liquid refrigerant (sg = 1.08) is flowing at a...Ch. 6 - After the refrigerant from Problem 6.31 flashes...Ch. 6 - A fan delivers 640ft3/min (CFM) of air. If the...Ch. 6 - A large blower for a furnace delivers 47000ft3/min...Ch. 6 - A furnace requires 1200 Ib/h of air for efficient...Ch. 6 - If a pump removes 1.65 gal/min of water from a...Ch. 6 - Calculate the diameter of a pipe that would carry...Ch. 6 - If the velocity of a liquid is 1.65 ft/s in a...Ch. 6 - When 2000 L/min of water flows through a circular...Ch. 6 - Water flows at 1.20 m/s in a circular section with...Ch. 6 - Figure 6.16 shows a fabricated assembly made from...Ch. 6 - A standard Schedule 40 steel pipe is to be...Ch. 6 - If water at 180 F is flowing with a velocity of...Ch. 6 - A standard steel tube, 1.5 25-mm OD 3 1,5-mm wall...Ch. 6 - The recommended velocity of flow in the discharge...Ch. 6 - Repeat Problem 6.45, except specify suitable sizes...Ch. 6 - Table 6.2 shows the typical volume flow rate for...Ch. 6 - Repeat Problem 6.47 but use Schedule 80 DM pipeCh. 6 - Compute the resulting velocity of flow if 400...Ch. 6 - Repeat Problem 6.49 for a DN 50 Schedule 30 pipe.Ch. 6 - Compute the resulting velocity of flow if 400...Ch. 6 - Repeat Problem 6.51 for a 4-in Schedule 30 pipe.Ch. 6 - From the list of standard hydraulic steel tubing...Ch. 6 - A standard 6-in Schedule 40 steel pipe is carrying...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 O to specify...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 to specify...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 O to specify...Ch. 6 - A venturi meter is a device that uses a...Ch. 6 - A flow nozzle, shown in Fig. 6.18 is used to...Ch. 6 - Gasoline (sg = 0.67) is flowing at 0.11 m3/s in...Ch. 6 - Water at 10 C is flowing from point A to point B...Ch. 6 - Calculate the volume flow rate of water at 5 C...Ch. 6 - Calculate the pressure required in the larger...Ch. 6 - Kerosene with a specific weight of 50.0 lb/ft3 is...Ch. 6 - For the system shown in Fig. 6.23 ; calculate (a)...Ch. 6 - For the system shown in Fig. 6.24ss, calculate (a)...Ch. 6 - For the tank shown in Fig. 6.25lO, calculate the...Ch. 6 - Calculate the pressure of the air in the sealed...Ch. 6 - For the siphon in Fig. 6.26, calculate (a) the...Ch. 6 - For the siphon in Fig. 6.26 , calculate the...Ch. 6 - For the siphon in Fig. 6.26 , assume that the...Ch. 6 - For the siphon shown in Fig. 6.27, calculate (a)...Ch. 6 - For the special fabricated reducer shown in Fig....Ch. 6 - In the fabricated enlargement shown in Fig. 6.29,...Ch. 6 - Figure 6.30 shows a manometer being used to...Ch. 6 - For the venturi meter shown in Fig. 6.30,...Ch. 6 - Oil with a specific weight of 8.64 kN/m3 flows...Ch. 6 - The venturi meter shown in Fig. 6.32 iP carries...Ch. 6 - Oil with a specific gravity of 0.90 is flowing...Ch. 6 - Oil with a specific gravity of 0.90 is flowing...Ch. 6 - Gasoline (sg = 0.67) is flowing at 4.0 ft3/s in...Ch. 6 - Oil with a specific weight of 55.0lb/ft3 flows...Ch. 6 - Draw a plot of elevation head, pressure head,...Ch. 6 - Prob. 6.84PPCh. 6 - Figure 6.36 shows a system in which water flows...Ch. 6 - Figure 6.37 shows a venturi meter with a U-tube...Ch. 6 - For the tank shown in Fig. 6.38, compute the...Ch. 6 - What depth of fluid above the outlet nozzle is...Ch. 6 - Derive Torricelli's theorem for the velocity of...Ch. 6 - Solve Problem 6.88 using the direct application of...Ch. 6 - To what height will the jet of fluid rise for the...Ch. 6 - To what height will the jet of water rise for the...Ch. 6 - What pressure is required above the water in Fig....Ch. 6 - What pressure is required above the water in Fig....Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Prob. 6.103PPCh. 6 - Repeat Problem 6.101 if the tank is sealed and a...Ch. 6 - Repeat Problem 6.96 if the tank is sealed and a...Ch. 6 - Repeat Problem 6.100 if the tank is sealed and a...Ch. 6 - A village currently carries water by hand from a...Ch. 6 - A "spa tub" is to be designed to replace bath tubs...Ch. 6 - A simple soft drink system relies on pressurized...Ch. 6 - A concept team for a toy company is considering a...Ch. 6 - 6.111 Bernoulli's principle applies to Venturi...Ch. 6 - Prob. 6.112PPCh. 6 - You are to develop a mixing valve for use in a...Ch. 6 - Prob. 6.114PPCh. 6 - You would like to empty the in-ground pool in the...Ch. 6 - Prob. 6.116PPCh. 6 - Create a spreadsheet for computing the values of...Ch. 6 - Prob. 2APCh. 6 - Prob. 3APCh. 6 - Create a spreadsheet for computing, using Eq....Ch. 6 - Prob. 5APCh. 6 - Create a spreadsheet for computing the velocity of...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q2: The plate material of a pressure vessel is AISI 1050 QT 205 °C. The plate is rolled to a diameter of 1.2 m. The two sides of the plate are connected via a riveted joint as shown below. If the rivet material is G10500 with HB=197 and all rivet sizes M31. Find the required rivet size when the pressure vessel is subjected to an internal pressure of 500 MPa. Take safety factor = 2. 1.2m A B' A Chope olm 10.5 0.23 hopearrow_forwardContinuity equation A y x dx D T معادلة الاستمرارية Ly X Q/Prove that ди хе + ♥+ ㅇ? he me ze ོ༞“༠ ?arrow_forwardQ Derive (continuity equation)? I want to derive clear mathematics.arrow_forward
- motor supplies 200 kW at 6 Hz to flange A of the shaft shown in Figure. Gear B transfers 125 W of power to operating machinery in the factory, and the remaining power in the shaft is mansferred by gear D. Shafts (1) and (2) are solid aluminum (G = 28 GPa) shafts that have the same diameter and an allowable shear stress of t= 40 MPa. Shaft (3) is a solid steel (G = 80 GPa) shaft with an allowable shear stress of t = 55 MPa. Determine: a) the minimum permissible diameter for aluminum shafts (1) and (2) b) the minimum permissible diameter for steel shaft (3). c) the rotation angle of gear D with respect to flange A if the shafts have the minimum permissible diameters as determined in (a) and (b).arrow_forwardFirst monthly exam Gas dynamics Third stage Q1/Water at 15° C flow through a 300 mm diameter riveted steel pipe, E-3 mm with a head loss of 6 m in 300 m length. Determine the flow rate in pipe. Use moody chart. Q2/ Assume a car's exhaust system can be approximated as 14 ft long and 0.125 ft-diameter cast-iron pipe ( = 0.00085 ft) with the equivalent of (6) regular 90° flanged elbows (KL = 0.3) and a muffler. The muffler acts as a resistor with a loss coefficient of KL= 8.5. Determine the pressure at the beginning of the exhaust system (pl) if the flowrate is 0.10 cfs, and the exhaust has the same properties as air.(p = 1.74 × 10-3 slug/ft³, u= 4.7 x 10-7 lb.s/ft²) Use moody chart (1) MIDAS Kel=0.3 Q3/Liquid ammonia at -20°C is flowing through a 30 m long section of a 5 mm diameter copper tube(e = 1.5 × 10-6 m) at a rate of 0.15 kg/s. Determine the pressure drop and the head losses. .μ= 2.36 × 10-4 kg/m.s)p = 665.1 kg/m³arrow_forward2/Y Y+1 2Cp Q1/ Show that Cda Az x P1 mactual Cdf Af R/T₁ 2pf(P1-P2-zxgxpf) Q2/ A simple jet carburetor has to supply 5 Kg of air per minute. The air is at a pressure of 1.013 bar and a temperature of 27 °C. Calculate the throat diameter of the choke for air flow velocity of 90 m/sec. Take velocity coefficient to be 0.8. Assume isentropic flow and the flow to be compressible. Quiz/ Determine the air-fuel ratio supplied at 5000 m altitude by a carburetor which is adjusted to give an air-fuel ratio of 14:1 at sea level where air temperature is 27 °C and pressure is 1.013 bar. The temperature of air decreases with altitude as given by the expression The air pressure decreases with altitude as per relation h = 19200 log10 (1.013), where P is in bar. State any assumptions made. t = ts P 0.0065harrow_forward
- 36 2) Use the method of MEMBERS to determine the true magnitude and direction of the forces in members1 and 2 of the frame shown below in Fig 3.2. 300lbs/ft member-1 member-2 30° Fig 3.2. https://brightspace.cuny.edu/d21/le/content/433117/viewContent/29873977/Viewarrow_forwardCan you solve this for me?arrow_forward5670 mm The apartment in the ground floor of three floors building in Fig. in Baghdad city. The details of walls, roof, windows and door are shown. The window is a double glazing and air space thickness is 1.3cm Poorly Fitted-with Storm Sash with wood strip and storm window of 0.6 cm glass thickness. The thickness of door is 2.5 cm. The door is Poor Installation. There are two peoples in each room. The height of room is 280 cm. assume the indoor design conditions are 25°C DBT and 50 RH, and moisture content of 8 gw/kga. The moisture content of outdoor is 10.5 gw/kga. Calculate heat gain for living room : الشقة في الطابق الأرضي من مبنى ثلاثة طوابق في مدينة بغداد يظهر في مخطط الشقة تفاصيل الجدران والسقف والنوافذ والباب. النافذة عبارة عن زجاج مزدوج وسمك الفراغ الهوائي 1.3 سم ضعيف الاحكام مع ساتر حماية مع إطار خشبي والنافذة بسماكة زجاج 0.6 سم سماكة الباب 2.5 سم. الباب هو تركيب ضعيف هناك شخصان في كل غرفة. ارتفاع الغرفة 280 سم. افترض أن ظروف التصميم الداخلي هي DBT25 و R50 ، ومحتوى الرطوبة 8…arrow_forward
- How do i solve this problem?arrow_forwardQ4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of 250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction between the belt and the small pulley is 0.3, and between the belt and the large pulley is 0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³. (a) What is the power capacity of the drive and (b) If the small pulley replaced by V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of friction between belt and grooved pulley is 0.35. What will be the power capacity in this case, assuming that the diameter of the large pulley remain the same of 1500 mm.arrow_forwardYou are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure. The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application: Specifications: Motor Power: The electric motor provides 10 kW of power at 1,500 RPM. Output Speed: The output shaft should rotate at 150 rpm. Design Decisions: Transmission ratio: Determine the necessary drive ratio for the system. Shaft Diameter: Design the shafts for both the motor and the conveyor end. Material Selection: Choose appropriate materials for the gears, shafts. Bearings: Select suitable rolling element bearings. Constraints: Space Limitation: The available space for the gear drive system is limited to a 1-meter-long section. Attribute 4 of CEP Depth of knowledge required Fundamentals-based, first principles analytical approach…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
8.01x - Lect 27 - Fluid Mechanics, Hydrostatics, Pascal's Principle, Atmosph. Pressure; Author: Lectures by Walter Lewin. They will make you ♥ Physics.;https://www.youtube.com/watch?v=O_HQklhIlwQ;License: Standard YouTube License, CC-BY
Dynamics of Fluid Flow - Introduction; Author: Tutorials Point (India) Ltd.;https://www.youtube.com/watch?v=djx9jlkYAt4;License: Standard Youtube License