Engineering Electromagnetics
9th Edition
ISBN: 9780078028151
Author: Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher: Mcgraw-hill Education,
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Question
Chapter 6, Problem 6.32P
To determine
(a)
The potential at all point.
To determine
(b)
The electrical field intensity
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This problem is complete the question with proper dimension of rectangular plate. can u assumtion please
Please solve max in 20-25 please the subparts A,B,C Im very needed a solution and send thank u
A plate plate in a vacuum, has a rectangular area whose sides are 20 cm long. The distance between the two plates is 5 mm. So,
A. Make a summary and calculate the value of the capacitance!
B. If there is a dielectric material with dielectric constant k = 2 having dimensions of 20 cm x 10 cm x 5 mm is placed between the two plates, then sketch the trainer and calculate the current capacitance value?
C. If there is a dielectric material with dielectric constant k = 4 , having dimensions of 20 cm x 10 cm x 2 mm is added to the condition of problem B) and is placed in the blank between the two plates, so that it sticks to one of the plates. So make a sketch of the sport and determine its current capacitance value?
(al:Determine E caused by the spherical cloud of electrons with a volume charge density of -
1.68 x 10 -18 for 0 10mm. Clearly
mention the surfaces, there differential components and write the equation properly by
doing all the steps.
(b): For the dielectric composition shown in the figure find out its total capacitance.
QUESTION 1
a) Two conducting plates are separated by three dielectric materials as shown in
Figure Q.1(a) The relative permittivity, &, of the materials filled in the two
conducting plates are tabulated in Table Q.1. Find the total capacitance, C of
the parallel plates in terms of d₁, d2, A₁, and A₂ by neglecting the fringing effects.
The symbols of di, d2, A₁, and A2 are the material thickness and material areas,
respectively.
A₁
A₂
di
d₂
1
3
2
Figure Q. 1(a)
Table Q.1
Material
Relative permittivity, &r
1
2.2
2
2.8
3
4.2
Hint:
The general capacitance formula of two conducting plates is given as:
d
where E, A, and d are the permittivity of free space, area of the two conducting
plates, and distance between the two conducting plates, respectively.
1
Chapter 6 Solutions
Engineering Electromagnetics
Ch. 6 - Prob. 6.1PCh. 6 - Let S = 100 mm2. d= 3 mm, and er = 12 for a...Ch. 6 - Capacitors tend to be more expensive as their...Ch. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - A parallel-plane capacitor is made using two...Ch. 6 - For the capacitor of Problem 6.6, consider the...Ch. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - A coaxial cable has conductor dimensions of a =...
Ch. 6 - Prob. 6.11PCh. 6 - (a) Determine the capacitance of an isolated...Ch. 6 - With reference to Figure 6.5, let b=6m, h=15m, and...Ch. 6 - Two=16 copper conductor (1.29 mm diameter) are...Ch. 6 - Prob. 6.15PCh. 6 - Prob. 6.16PCh. 6 - Construct a curvilinear-square map for a coaxial...Ch. 6 - Prob. 6.18PCh. 6 - Construct a curvilinear- square map of the...Ch. 6 - Prob. 6.20PCh. 6 - The inner conductor of the transmission line shown...Ch. 6 - Prob. 6.22PCh. 6 - Prob. 6.23PCh. 6 - A potential field in free space is given in...Ch. 6 - A capacitor is formed from concentric spherical...Ch. 6 - Given the spherical symmetric field in free space,...Ch. 6 - Let V=z(x,y)=4e2xf(x)3y2 in a region of free space...Ch. 6 - Show that in a homogeneous medium of conductivity...Ch. 6 - What total charge must be located within a unit...Ch. 6 - Prob. 6.30PCh. 6 - For the parallel-plate capacitor shown in Figure...Ch. 6 - Prob. 6.32PCh. 6 - The functions V1 (p, , z) and V2(p, , z) both...Ch. 6 - Prob. 6.34PCh. 6 - Prob. 6.35PCh. 6 - Prob. 6.36PCh. 6 - Prob. 6.37PCh. 6 - Prob. 6.38PCh. 6 - Prob. 6.39PCh. 6 - Prob. 6.40PCh. 6 - Prob. 6.41PCh. 6 - Prob. 6.42PCh. 6 - Prob. 6.43PCh. 6 - Prob. 6.44PCh. 6 - Prob. 6.45PCh. 6 - By appropriate solution of Laplaces and Poissons...
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