Engineering Electromagnetics
Engineering Electromagnetics
9th Edition
ISBN: 9780078028151
Author: Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher: Mcgraw-hill Education,
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Chapter 6, Problem 6.25P

A capacitor is formed from concentric spherical conductors having radii a and b, where b > a. The inner conductor is raised to potential V0; the outer conductor is grounded. Under these conditions, derive Eq. (39) using Laplace’s equation.

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Derive the capacitance formula for the coaxial capacitor starting with Laplace’s equation. The voltage at the inner conductor is Vo and the outer conductor is 0 V. The formula obtained will match equation 6.28 in the book.
(a) Two parallel plates of area A separated by distance d form a capacitor. The first plate is grounded and the second one has a potential V2. Solving Laplace's equation determine: (i) (ii) (iii) (iv) The potential between the plates The electric field between the plates The total charge on conductor 2 The capacitance.
The parallel plate capacitor in the figure below has a plate area A and plate separation d. The capacitor is charged to a voltage Vo, and then isolated. A student then inserts a dielectric slab (dielectric constant K) with thickness t and area A between the plates and parallel to them as shown below (the dielectric does not touch the plates at any time). Once the slab is in place, the student measures the potential difference between the plates. What potential difference will the student measure? You can assume the following numerical values: A=115.0 cm2, d=1.240 cm, Vo=65.00 V, t=0.7800 cm and K=2.610. O24.90 V 39.78 V 65.00 V None of these The answer will depend on the distance of the dielectric from the positive plate, which is not provided in the problem V

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Demos: Dielectric breakdown; Author: Caltech's Feynman Lecture Hall;https://www.youtube.com/watch?v=2YrHh1ikefI;License: Standard Youtube License