(Duplicate Elimination) In Chapter 12, we explore the high-speed binary search tree data structure. One feature of a binary search tree is that duplicate values are discarded when insertions are made into the tree. This is referred to as duplicate elimination. Write a
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- narmts Save Answer Write a Java program that uses ArrayList and Iterator. It should input from user the names and ages of your few friends in a loop and add into ArrayList. Finally, it should use Iterator to display the data in a proper format. (Hint- Lecture 02: Slide 8) Sample output: List of my Friends Enter name and age [friend# oj Khalid Al-shamri 22.5 Do you want to add another friend (y/n)? y Enter name and age [friend# 1] Rahsed Al-anazi 21.1 Do you want to add another friend (y/n)? y Enter name and age [friend# 2] Salem Al-mutairi 23.7 Do you want to add another friend (y/n)? n Here is the data you entered: 0. Khalid Al-shamri, 22.5 1. Rahsed Al-anazi, 21.1 2. Salem Al-mutairi, 23.7arrow_forward(Maximum element in an array) Implement the following method that returns the maximum element in an array . public static > E max (E[] list) Write a test program that prompts the user to enter 10 integers, invokes this method to find the max.arrow_forward1.""Implementation of the Misra-Gries algorithm.Given a list of items and a value k, it returns the every item in the listthat appears at least n/k times, where n is the length of the array By default, k is set to 2, solving the majority problem. For the majority problem, this algorithm only guarantees that if there isan element that appears more than n/2 times, it will be outputed. If thereis no such element, any arbitrary element is returned by the algorithm.Therefore, we need to iterate through again at the end. But since we have filtredout the suspects, the memory complexity is significantly lower thanit would be to create counter for every element in the list. For example:Input misras_gries([1,4,4,4,5,4,4])Output {'4':5}Input misras_gries([0,0,0,1,1,1,1])Output {'1':4}Input misras_gries([0,0,0,0,1,1,1,2,2],3)Output {'0':4,'1':3}Input misras_gries([0,0,0,1,1,1]Output None""".expl.arrow_forward
- (Algebra: perfect square ) Write a program that prompts the user to enter an integer m and find the smallest integer n such that m * n is a perfect square. (Hint: Store all smallest factors of m into an array list. n is the product of the factors that appear an odd number of times in the array list. For example, consider m = 90, store the factors 2, 3, 3, 5 in an array list. 2 and 5 appear an odd number of times in the array list. So, n is 10.) Sample Run 1 Enter an integer m: 1500 The smallest number n for m x n to be a perfect square is 15 m x n is 22500 Sample Run 2 Enter an integer m: 63 The smallest number n for m x n to be a perfect square is 7 m x n is 441 Class Name: Exercise11_17 Answer is : import java.util.Scanner; public class Squares { public static void main(String[] args) { Scanner scan = new Scanner(System.in); //instantiation of Scanner that will take inputs from the keyboard //the try catch block below is for trapping error with the input try {…arrow_forwarddont give the same solution again .10 min left fast Array Indexing: Knowing the basics of array indexing is important for analysing and manipulating the array object. NumPy offers many ways to do array indexing. O slicing: Just like lists in python, NumPy arrays can be sliced. As arrays can be multidimensional, you need to specify a slice for each dimension of the array. O Integer array indexing: In this method, lists are passed for indexing for each dimension. One to one mapping of corresponding elements is done to construct a new arbitrary array. O Boolean array indexing: This method is used when we want to pick elements from array which satisfy some conditionarrow_forward/** numUnique returns the number of unique values in an array of doubles. * The array may be empty and it may contain duplicate values. * Unlike the previous questions, you can assume the array is sorted. * * Your solution should contain at most one loop. You may not use recursion. * Your solution must not call any other functions. * Here are some examples (using "==" informally): * * * * * Ⓒ == numUnique (new double[] { }) 1 == numUnique (new double[] {11}) 1 == numUnique (new double[] { 11, 11, 11, 11 }) 8 == numUnique (new double[] { 11, 11, 11, 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88, 88 }) 8 == numUnique (new double[] { 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88 }) * */ public static int numUnique (double[] list) { return StdRandom.uniform (100); //TODO: fix thisarrow_forward
- 9. Implement an array with values 1, 5, 14, 23, 45, 52, 58, 81, 82 91. a) Create a getindex( function which does a linear search upon the array for a specific value n. Return the index of n, or -1 ifn does not exist, b) Print the array. c) Search the array for the values 23, 58, 11, rint the reaults. Qutpur Examnle 15 14 23 45 52 58 71 82 91 Number 23 is located at index Number 58 As located at index C Number 11 i looated at index -1arrow_forwardComplete my C++ program: Instructions: You have to continue on implementing your Array List namely the following functions: Example ArrayList: [10, 30, 40, 50] void addAt(int num, int pos) This method will add the integer num to the posth position of the list. Performing addAt(20, 2) in the example list will add 20 at the 2nd position and the array will now look like this: [10, 20, 30, 40, 50] When the value of pos is greater than the size + 1 or less than one, output "Position value invalid" void removeAt(int pos) Removes the number in the posth position of the list. Performing removeAt(3) in the example list will remove the 3rd element of the list and the updated array will be: [10, 30, 50] When the value of pos is greater than the size or less than one, output "Position value invalid" void removeAll(int num) Removes all instances of num in the array list. In this array [10, 10, 20, 30, 10], performing removeAll(10) will remove all 10's and the list will look like this: [20,…arrow_forwardplease code in python Forbidden concepts: arrays/lists (data structures), recursion, custom classes Watch this video on the Fibonacci sequence. The first two numbers of the sequence are 1 and 1. The subsequent numbers are the sum of the previous two numbers. Create a loop that calculates the Fibonacci sequence of the first 25 numbers and prints each one.Lastly, state the 25th and 24th sequence in a sentence, and explain how the golden ratio is conducted from it, including what it is.Note: you don’t know what the 24th and 25th numbers are, get the program to find out and calculate itself what the ratio is.arrow_forward
- [] [] partite_sets In the cell below, you are to write a function "partite_sets (graph)" that takes in a BIPARTITE graph as its input, and then returns a single list whose two entries are the partite sets of the graph as lists (the order of the sets outputed does not matter). After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (partite_sets({"A" : ["B", "C"], "B" : partite_sets({"A" : ["B", "C"], "B" : ["A"], "C" : ["A"]}), ["A", "D"], "C" : ["A", "D"], "D" : ["B", "C"]})) This should return [["B","C"], ["A"]] [["A","D"], ["B","C"]] (the order in which the entries appear does not matter) Python Pythonarrow_forward12) Fun With Mergesort. Given the recursive mergesort function below. Modify the msort function such that, msort calls msort for sub arrays with more than 1024 elements, and msort calls bsort for sub arrays with 1024 or less elements. Assume both functions operate on the same global array. int data[4294967296]; // REALLY BIG array void bsort (int f, int 1); // forward declaration void msort (int f, int 1) int m; if (f<1) { m - (f+1)/2; msort (f, m): msort (m+1,1): merge (f,m, 1);arrow_forward4. CodeW X For func X C Solved b Answer x+ https://codeworkou... ... [+) CodeWorkout X271: Recursion Programming Exercises: Minimum of array For function recursiveMin, write the missing part of the recursive call. This function should return the minimum element in an array of integers. You should assume that recursiveMin is initially called with startIndex = 0. Examples: recursiveMin({2, 4, 8}, 0) -> 2 Your Answer: 1 public int recursiveMin(int numbers[], int startIndex) { numbers.length - 1) { if (startIndex 2. return numbers[startIndex]; } else { return Math. min(numbers[startIndex], >); 5. { 1:11 AM 50°F Clear 12/4/2021arrow_forward
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