Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter 6, Problem 20E

a)

To determine

To find the mean and standard deviation.

a)

Expert Solution
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Answer to Problem 20E

New mean is 3.84 mph and standard deviation is 3.56 mph.

Explanation of Solution

Given:

  μ = 23.48

  σ = 3.56

All the values decreased by 20 mph. Therefore, the mean is also decreased by 20 mph.

Then the new mean is,

  μ=μold20=23.8420=3.84mph

There will be no impact on standard deviation because the spread of the data values will not change by adding subtracting any value.

Therefore, σ=σold=3.56mph

b)

To determine

To find the mean and standard deviation.

b)

Expert Solution
Check Mark

Answer to Problem 20E

New mean is 38.3586 km/h and standard deviation is 5.72804 km/h.

Explanation of Solution

Given:

  μ = 23.48

  σ = 3.56

All the values multiplied by 1.609.

Then the new mean is,

  μ=1.609×μold=1.609×23.84=38.35856km/h

Therefore, σ=1.609×σold=1.609×3.56=5.72804km/h

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