High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
15th Edition
ISBN: 9780133281149
Author: Prentice Hall
Publisher: Prentice Hall
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Chapter 5.5, Problem 5LC
To determine

To find:the equation of gift card purchased and spent is written in standard form and also find the three combinations of gift cards purchased.

Expert Solution & Answer
Check Mark

Answer to Problem 5LC

The relationship equation of gift card purchased and spent is 10x+25y=285

The three combinations of gift card purchased is given as (0,12) , (29,0) , and (6,9)

Explanation of Solution

Given info:

The price of the gift card is either $10 or $25.

Consider the number of $10 gift card is x

Consider the number of $25 gift card is y

The amount spent for buying gift card is $285.

Formula used:

Show the standard form of equation as follows:

  Ax+By=C

Here, A,B,C are constants

Calculation:

Find the relationship equation of gift card purchased and spent as follows:

  Ax+By=C10x+25y=285

Hence, the equation in standard form is 10x+25y=285

Find the x  and y intercept and also find the three combination of gift card purchased.

Consider the number of $10 card purchasedis x=0 .

  10x+25y=28510(0)+25y=28525y=285y=28525y=11.4 ≃12

Hence, the first combination is (0,12) also y=12 is the y-intercept.

Consider the number of $20 card purchased is y=0 .

  10x+25y=28510x+25(0)=28510x=285x=28510x=28.5 ≃29

Hence, the second combination is (29,0) also x=29 is the x-intercept.

Consider any value of x and y to get 285 on right side of the equation. Take x=6 and y=9 to form the third combination of card purchased.

  10x+25y=28510(6)+25(9)=28560+225=285285=285

Hence, the third combination is (6,9) .

Conclusion:

Thus, the relationship equation of gift card purchased and spent is 10x+25y=285

Thus, the three combinations of gift card purchased is given as (0,12) , (29,0) , and (6,9)

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Chapter 5.5, Problem 4LC
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Chapter 5.5, Problem 6LC

Chapter 5 Solutions

High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9

Ch. 5.1 - Prob. 1PCh. 5.1 - Prob. 2PCh. 5.1 - Prob. 3PCh. 5.1 - Prob. 4PCh. 5.1 - Prob. 1LCCh. 5.1 - Prob. 2LCCh. 5.1 - Prob. 3LCCh. 5.1 - Prob. 4LCCh. 5.1 - Prob. 5LCCh. 5.1 - Prob. 6LC
Ch. 5.1 - Prob. 7LCCh. 5.1 - Prob. 8PPECh. 5.1 - Prob. 9PPECh. 5.1 - Prob. 10PPECh. 5.1 - Prob. 11PPECh. 5.1 - Prob. 12PPECh. 5.1 - Prob. 13PPECh. 5.1 - Prob. 14PPECh. 5.1 - Prob. 15PPECh. 5.1 - Prob. 16PPECh. 5.1 - Prob. 17PPECh. 5.1 - Prob. 18PPECh. 5.1 - Prob. 19PPECh. 5.1 - Prob. 20PPECh. 5.1 - Prob. 21PPECh. 5.1 - Prob. 22PPECh. 5.1 - Prob. 23PPECh. 5.1 - Prob. 24PPECh. 5.1 - Prob. 25PPECh. 5.1 - Prob. 26PPECh. 5.1 - Prob. 27PPECh. 5.1 - Prob. 28PPECh. 5.1 - Prob. 29PPECh. 5.1 - Prob. 30PPECh. 5.1 - Prob. 31PPECh. 5.1 - Prob. 32PPECh. 5.1 - Prob. 33PPECh. 5.1 - Prob. 34PPECh. 5.1 - Prob. 35PPECh. 5.1 - Prob. 36PPECh. 5.1 - Prob. 37PPECh. 5.1 - Prob. 38PPECh. 5.1 - Prob. 39PPECh. 5.1 - Prob. 40PPECh. 5.1 - Prob. 41PPECh. 5.1 - Prob. 42PPECh. 5.1 - Prob. 43PPECh. 5.1 - Prob. 44PPECh. 5.1 - Prob. 45PPECh. 5.1 - Prob. 46PPECh. 5.1 - Prob. 47PPECh. 5.1 - Prob. 48PPECh. 5.1 - Prob. 49PPECh. 5.1 - Prob. 50PPECh. 5.1 - Prob. 51PPECh. 5.1 - Prob. 52PPECh. 5.1 - Prob. 53PPECh. 5.1 - Prob. 54PPECh. 5.1 - 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Prob. 72MRCh. 5.5 - Prob. 73MRCh. 5.5 - Prob. 74MRCh. 5.5 - Prob. 75MRCh. 5.5 - Prob. 76MRCh. 5.5 - Prob. 77MRCh. 5.5 - Prob. 1CBCh. 5.5 - Prob. 2CBCh. 5.5 - Prob. 3CBCh. 5.5 - Prob. 4CBCh. 5.5 - Prob. 5CBCh. 5.5 - Prob. 6CBCh. 5.5 - Prob. 7CBCh. 5.5 - Prob. 8CBCh. 5.5 - Prob. 9CBCh. 5.5 - Prob. 10CBCh. 5.5 - Prob. 11CBCh. 5.5 - Prob. 12CBCh. 5.5 - Prob. 13CBCh. 5.5 - Prob. 14CBCh. 5.5 - Prob. 15CBCh. 5.5 - Prob. 16CBCh. 5.5 - Prob. 17CBCh. 5.5 - Prob. 18CBCh. 5.5 - Prob. 19CBCh. 5.6 - Prob. 1PCh. 5.6 - Prob. 2PCh. 5.6 - Prob. 3PCh. 5.6 - Prob. 4PCh. 5.6 - Prob. 1LCCh. 5.6 - Prob. 2LCCh. 5.6 - Prob. 3LCCh. 5.6 - Prob. 4LCCh. 5.6 - Prob. 5LCCh. 5.6 - Prob. 6LCCh. 5.6 - Prob. 7PPECh. 5.6 - Prob. 8PPECh. 5.6 - Prob. 9PPECh. 5.6 - Prob. 10PPECh. 5.6 - Prob. 11PPECh. 5.6 - Prob. 12PPECh. 5.6 - Prob. 13PPECh. 5.6 - Prob. 14PPECh. 5.6 - Prob. 15PPECh. 5.6 - Prob. 16PPECh. 5.6 - Prob. 17PPECh. 5.6 - Prob. 18PPECh. 5.6 - Prob. 19PPECh. 5.6 - Prob. 20PPECh. 5.6 - Prob. 21PPECh. 5.6 - Prob. 22PPECh. 5.6 - 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