High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
15th Edition
ISBN: 9780133281149
Author: Prentice Hall
Publisher: Prentice Hall
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Chapter 5.5, Problem 38PPE
To determine

To find: The equation that represents the given situation and also to graph it. Also to find three combinations of T-shirts and sweatshirts, someone can buy for $120.

Expert Solution & Answer
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Answer to Problem 38PPE

Linear equation representing the given situation is

  12x+15y=120 and its related graph is shown below.

  High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9, Chapter 5.5, Problem 38PPE , additional homework tip  1

Three combination of T shirts and sweatshirts are,

(iii) 10 T-shirts only (ii) 8 sweatshirts only (iii) T-shirts and 4 sweatshirts

Explanation of Solution

Given information: M has to spend $120 on T-shirts and Sweatshirts. The price of one T-shirt is $12 and of one sweatshirt is $15.

Concept/Formula used: Set the equation using following statement of equality.

  Total buying cost = Price of one T-shirt ×cost of one shirt +Price of one sweatshirt ×cost of one sweatshirt 

Calculation: Let M buys x T shirts and y sweatshirts. So, required equation representing the situation is set using above formula as;

  12x+15y=120

Three points in ordered pair form (x,y) are calculated in below table:

    x12x+15y=120(x,y)
    512(5)+15y=12015y=12060=60y=6015=4(5,4)
    012(0)+15y=12015y=120y=12015=8(0,8)
    1012(10)+15y=12015y=120120=0y=015=0(10,0)

Plot these points in XY coordinate plane to get related graph as:

  High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9, Chapter 5.5, Problem 38PPE , additional homework tip  2

Conclusion: By above table, three combination of purchasing are,

(i) 10 T-shirts only (ii) 8 sweatshirts only (iii) T-shirts and 4 sweatshirts

Chapter 5 Solutions

High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9

Ch. 5.1 - Prob. 7LCCh. 5.1 - Prob. 8PPECh. 5.1 - Prob. 9PPECh. 5.1 - Prob. 10PPECh. 5.1 - Prob. 11PPECh. 5.1 - Prob. 12PPECh. 5.1 - Prob. 13PPECh. 5.1 - Prob. 14PPECh. 5.1 - Prob. 15PPECh. 5.1 - Prob. 16PPECh. 5.1 - Prob. 17PPECh. 5.1 - Prob. 18PPECh. 5.1 - Prob. 19PPECh. 5.1 - Prob. 20PPECh. 5.1 - Prob. 21PPECh. 5.1 - Prob. 22PPECh. 5.1 - Prob. 23PPECh. 5.1 - Prob. 24PPECh. 5.1 - Prob. 25PPECh. 5.1 - Prob. 26PPECh. 5.1 - Prob. 27PPECh. 5.1 - Prob. 28PPECh. 5.1 - Prob. 29PPECh. 5.1 - Prob. 30PPECh. 5.1 - Prob. 31PPECh. 5.1 - Prob. 32PPECh. 5.1 - Prob. 33PPECh. 5.1 - Prob. 34PPECh. 5.1 - Prob. 35PPECh. 5.1 - Prob. 36PPECh. 5.1 - Prob. 37PPECh. 5.1 - Prob. 38PPECh. 5.1 - Prob. 39PPECh. 5.1 - Prob. 40PPECh. 5.1 - Prob. 41PPECh. 5.1 - Prob. 42PPECh. 5.1 - Prob. 43PPECh. 5.1 - Prob. 44PPECh. 5.1 - Prob. 45PPECh. 5.1 - Prob. 46PPECh. 5.1 - Prob. 47PPECh. 5.1 - Prob. 48PPECh. 5.1 - Prob. 49PPECh. 5.1 - Prob. 50PPECh. 5.1 - Prob. 51PPECh. 5.1 - Prob. 52PPECh. 5.1 - Prob. 53PPECh. 5.1 - Prob. 54PPECh. 5.1 - 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Prob. 72MRCh. 5.5 - Prob. 73MRCh. 5.5 - Prob. 74MRCh. 5.5 - Prob. 75MRCh. 5.5 - Prob. 76MRCh. 5.5 - Prob. 77MRCh. 5.5 - Prob. 1CBCh. 5.5 - Prob. 2CBCh. 5.5 - Prob. 3CBCh. 5.5 - Prob. 4CBCh. 5.5 - Prob. 5CBCh. 5.5 - Prob. 6CBCh. 5.5 - Prob. 7CBCh. 5.5 - Prob. 8CBCh. 5.5 - Prob. 9CBCh. 5.5 - Prob. 10CBCh. 5.5 - Prob. 11CBCh. 5.5 - Prob. 12CBCh. 5.5 - Prob. 13CBCh. 5.5 - Prob. 14CBCh. 5.5 - Prob. 15CBCh. 5.5 - Prob. 16CBCh. 5.5 - Prob. 17CBCh. 5.5 - Prob. 18CBCh. 5.5 - Prob. 19CBCh. 5.6 - Prob. 1PCh. 5.6 - Prob. 2PCh. 5.6 - Prob. 3PCh. 5.6 - Prob. 4PCh. 5.6 - Prob. 1LCCh. 5.6 - Prob. 2LCCh. 5.6 - Prob. 3LCCh. 5.6 - Prob. 4LCCh. 5.6 - Prob. 5LCCh. 5.6 - Prob. 6LCCh. 5.6 - Prob. 7PPECh. 5.6 - Prob. 8PPECh. 5.6 - Prob. 9PPECh. 5.6 - Prob. 10PPECh. 5.6 - Prob. 11PPECh. 5.6 - Prob. 12PPECh. 5.6 - Prob. 13PPECh. 5.6 - Prob. 14PPECh. 5.6 - Prob. 15PPECh. 5.6 - Prob. 16PPECh. 5.6 - Prob. 17PPECh. 5.6 - Prob. 18PPECh. 5.6 - Prob. 19PPECh. 5.6 - Prob. 20PPECh. 5.6 - Prob. 21PPECh. 5.6 - Prob. 22PPECh. 5.6 - 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