Chapter 5.1, Problem 62E

To determine

To find:the range of degrees through which the composite flywheel can travel in a minute.

Answer to Problem 62E

  $\text{minimum }1.8\times {10}^6\text{ maximum }6.0\times {10}^6\text{ degrees traveled per minute}$

Explanation of Solution

Given information: Flywheels: A high-performance composite flywheel rotor can spin anywhere between 30,000 and 100,000 revolutions per minute.

Calculation:

Quadrants angles are multiples of ${90}^{\circ }$ so

  $\frac{30,000\text{ revolutions}}{\text{minute}}\times \frac{{60}^{\circ }}{\text{revolution}}=1,800,{000}^{\circ }$

This is the minimum

  $\frac{100,000\text{ revolutions}}{\text{minute}}\times \frac{{60}^{\circ }}{\text{revolution}}=6,000,{000}^{\circ }$

This is the maximum

Now change to scientific notation

  $\begin{array}{l}\text{minimum 1}\text{.8}\times {\text{10}}^6\\ \text{maximum 6}\text{.0}\times {\text{10}}^6\end{array}$

Thus,

  $\text{minimum }1.8\times {10}^6\text{ maximum }6.0\times {10}^6\text{ degrees traveled per minute}$