
(a)
To find: TheGraphing device to graph the function.
(a)

Answer to Problem 56RE
The function has Domain=(−∞,∞) and Range=[1.5, 3] .
Explanation of Solution
Given: y=1+2cosx
Concept used:
Cosx is even function over all equation change to even .
Its Domain=(−∞,∞) and Range=[1.5, 3] .
Amplitude is A=(3−1.5)=1.5
Calculation:
Thee graph of the y=1+2cosx .
Graphing device use here is Desmos graphing calculator. from the graph modulus symbolize the positivity of the function which is shown in the graph.
Through graph range and domain can Measured which is
Domain=(−∞,∞) and Range=[1.5, 3] .
Hence the function has Domain=(−∞,∞) and Range=[1.5, 3] .
(b)
To find:whether the Function is periodic if then described it.
(b)

Answer to Problem 56RE
The period here is 2π .
Explanation of Solution
Given: y=1+2cosx
Concept used:
Period is measured as distance it takes for the entire graph to repeat.
Since the period of the Cosine function is π .
Calculation:
y=1+2cosx
Form the graph its clearly verified the periods as:
Periods=π−(−π)=2π.
Hence the period here is 2π .
(c)
To find: The graph whether the function is even or odd.
(c)

Answer to Problem 56RE
The given function is even.
Explanation of Solution
Given: y=1+2cosx
Concept used:
f(-x)=f(x) the function is an even function.
f(-x)=-f(x) the function is and odd function
Calculation:
y=1+2cosx
Since Cosx even functions and overall becomes even function so, the function is even function.
f(-x)=1+2cos(-x)=1+2cosx=f(x)∀x.
It looks like infinitely many arches of length π and of height 1 in the upper half plane touching the x-axis and symmetrical about y-axis. Therefore, the function takes the same value at points on the x-axis which are equidistant form the y-axis.
Hence the given function is even.
Chapter 5 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
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