Chapter 5, Problem 47A

Interpretation Introduction

Interpretation:

Frequency and type of electromagnetic radiation with a wavelength of $3.33\times {10}^{-8}m$ needs to be determined.

Concept introduction:

Frequency is the number of waves passed through a point in one second. It is denoted by the symbol $\nu$

$\left(nu\right)$ with unit per second or $hertz\left(Hz\right).$

Answer to Problem 47A

Frequency $=9\times {10}^{15}$

$cycle/s$ or $Hz$. It belongs to ultraviolet region.

Explanation of Solution

Given information:

The given wavelength $\left(\lambda \right)=$ $3.33\times {10}^{-8}m$.

The frequency can be calculated as follows:

$\nu =\frac{c}{\lambda }$

Where,

$\nu =$ frequency

$c=$ velocity of light $\left(3\times {10}^{8}m/s\right)$

$\lambda =$ wave length

Putting the values,

$\nu =\frac{3\times {10}^{8}m/s}{3.33\times {10}^{-8}m}$

$\nu =9\times {10}^{15}$

$cycle/s$

Wave with frequency $9\times {10}^{15}$

$cycle/s$.

The frequency range for ultraviolet rays is   $8\times {10}^{14} to3\times {10}^{16}$ cycles per second, or hertz (Hz). Thus, the calculate frequency falls in ultraviolet region.

Conclusion

Frequency of radiation $=9\times {10}^{15}$

$cycle/sorHz$. It belongs to ultraviolet region.