21st Century Astronomy
21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 5, Problem 44QP
To determine

The average temperature of Eris when it is farthest from the Sun.

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Saturn is even further at 1434X109m from the sun.  Calculate the approximate strength of the greenhouse effect on Jupiter.  The observed surface temperature is 133K, the albedo is 0.47, the solar constant is 15W/m2.
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The fraction of the energy flux received which is reflected into space is the albedo of Venus, av, which is about 0.76.  The fraction of the energy flux which is absorbed is then (1-av) = 1. - 0.76 = 0.24.  So the amount of energy actually absorbed by Venus in each second is Lv = (1-av)Ev. Lv = (1-av)Ev = ___________________ ergs/s And next calculate the effective temperature of Venus: Tv4 = (Lv/(4pdv2))/s   =    Lv/(4spdv2)  = __________________ K4 and taking the square root of Tv4 twice in succession we get the effective Temperature Tv: Tv  = [Lv/(4spdv2)]0.25  =  _________________ K Calculate Venus' emittance assuming that the Venus' actual temperature, Tvr, is 472o C  =  745 K:  ev = Lv/(4pdv2s Tvr4)   =  __________________ .
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