Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 5, Problem 20P
Interpretation Introduction
Interpretation:
The given result of amplifying a segment of DNA by PCR with the help of the primers is to be explained.
Concept introduction:
The reaction that is used to make the duplicates of a particular DNA segment is known polymerase chain reaction (PCR).
A small single strand of DNA or RNA containing approximately
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Students have asked these similar questions
Clone number in this case is number 196 as shown in the images. What is the exact length of the segment of human DNA that has been inserted into the plasmid?
*report the entire length of the insert, not just the sequences matching the ends and labels of wells isn't needed for answer*
Help Please
Supercoiled DNA migrates through an
agorose gel faster than similarly sized linear
DNA? True or False?
Using the plasmid map, indicate where (bp region on plasmid) these enzymes cut on
the plasmid.
EcoR1
1. 1
Hindlll
2. 637
Bpu101
3. 14
BamHI
4. 256
To sequence a DNA plasmid, you need 1 µg of DNA.
If your DNA concentration was 0.45 µg/µL. How many µl of your DNA 0.45 µg/µL
is required to get 1 µg final? Answer in µl using 2 decimal places.
Your Answer:
Answer
units
>
Kpnl
4. Plasmid Z has a size of 7 kb, and the map shows Kpnl (K) and
Pstl (P) cut sites relative to each other.
This plasmid was digested with three different restriction enzymes
2000 bp
3500 bp
Kpnl (K), Pstl (P) and Bgll (B) either alone or in combination and the
samples run on an agarose gel as shown below.
Where does Bgll (B) cut this plasmid ? Does the plasmid have one
recognition site or two for Bg|l?
Describe the Bgll cut site in this plasmid relative to the Kpnl cut
Plasmid Z -7 kb
Pstl
site. How many bases to the left or right of the Kpnl cut site would
you observe the Bgll cut site. Explain briefly.
1500 bp
Pstl
Ladder
Kpni
Psti
K/P
Bgl
K/B
KPB
7000 bp
7000 bp
5600 bp
5500 bp
4900 bp
3500 bp
2000 bp
1500 bp
1500 bp
1500 bp
1400 bp
600 bp
%3D
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- Section Name MAPPING PRACTICE #4 Plasmid pBR 607 is a 2.6 Kb plasmid containing Ampicillin and Tetracycline resistance markers, an origin of replication, and unique restriction sites for the restriction enzymes EcoRI, BamHI, and Pstl. Given the restriction map for pBR 607 for the enzymes EcoRI, BamHI, and Pstl, show on the gel diagram, where the approximate positions of the restriction fragments generated from the restriction digests would be located after carrying out electrophoresis. BamHI 0.2 Kb pBR 607 ECORI 1.94 Kb 0.46 Kb Pstl Size EcoRI EcoRI EcoRI + Standards BamHI + Pstl BamHI Pstl 4.0 Kb 2.2 Kb 2.0 Kb 0.5 Kbarrow_forwardRestriction mapping sample question You have a 5.3 kb PstI fragment cloned into the PstI site of the vector pUC19, which is 2.7 kb in size. This vector has unique sites for the following enzymes in a multiple cloning site: PstI, HincII, Xbal, BamHI, SmaI, EcoRI A restriction map of the 5.3 kb insert is prepared. The recombinant plasmid is digested with the enzymes listed above in single digests, and then several combinations of enzymes are tested in double digests. The following bands are observed when the digests are run on a gel: Enzyme(s) used PstI ECORI HincII Band sizes observed (kb) 5.3, 2.7 5.4, 2.6 4.5, 3.5 6.7, 1.3 | 4.0 (high intensity band) 3.9, 3.7, 0.4 4.0, 3.5, 0.5 3.5, 2.6, 1.9 3.7, 3.6, 0.4, 0.3 3.7, 2.2, 1.7, 0.4 3.7, 3.0, 0.9, 0.4 3.9, 3.5, 0.4, 0.2 Smal Xbal ВатHI HinclI + Xbal HincII + ECORI XbaI + BamHI ECORI + BamHI Smal + BamHI HincII + BamHI Use the data above to construct a map of the cloned insert. Note that fragments smaller than 100 bp will not usually be…arrow_forwardIn Figure 10-14, why does DNA migrate to the anode(+ pole)?arrow_forward
- Hi, I need help filling in the table.arrow_forwardpls help very urgent, no explaantion required, pls help asaparrow_forwardAgarose gel Can someone help me to understand how to estimate the size of my plasmid cut (pla cut) and insert (PCR cut) that shows in the picture? thank you (its from an cloning experiment)arrow_forward
- Relative to this image of the steps in gene cloning, identify the steps involved and the protein/enzyme requirements of each.arrow_forwarddetail explaination asaparrow_forwardHindlII ECORI ECORV BamHI 379 Sall Pstl. tet amp Plasmid PBR322 1000 4361 bp ori Ndel If you were going to use this vector to clone a foreign fragment of DNA, what two restriction enzymes would you use to cut the vector, so you could make a recombinant plasmid that has AmpR and KanR (Kanamycin resistance), but No TetR. Assume the insert DNA does NOT have a Tet resistance gene but does have a Kanamycin resistance gene. O EcoR1 and Hindll O Pst1 and Sal1 O Pst1 and Nde1 O EcoR1 and Nde1 f6arrow_forward
- Identify and explain steps ‘A’, ‘B’ and ‘C’ in the PCR diagram given below. Please elaborately explain the answer properly and kindly relate to the NCERT Bio XII chapter 11.arrow_forwardEntire sequence below needs to beamplified by PCR and subcloned into a plasmid vector. Which of the primersequences listed underneath is the correct reverse primer (6 marks)? Copy correctsequence into your answer. Why primer e) is not the right answer (4 marks)? 5'ATCTCTATTTAATATTTATGTCTATTTAAGCCTCATATTTAAAGACAGGGAAGAGCAGAACGGAGCCCCAGGCCTCTGTGTCCTTCCCTGCATTTCTGAGTTTCATTCTCCTGCCTGTAGCAGTGAGAAAAAGCTCCTGTCCTCCCATCCCCTGGACTGGGAGGTAGATAGGTAAATACCAAGTATTTATTACTATGACTGCTCCCCAGCCCTGGCTCTGCAATGGGCACTGGGATGAGCCGCTGTGAGCCCCTGGTCCTGAGGGTCCCCACCTGGGACCCTTGAGAGTATCAGGTCTCCCACGTGGGAGACAAGAAATCCCTGTTTAATATTTAAACAGCAGTGTTCCCCATCTGGGTCCTTGCACCCCTCACTCTGGCCTCAGCCGACTGCACAGCGGCCCCTGCATCCCCTTGGCTGTGAGGCCCCTGGACAAGCAGAGGTGGCCAGAGCTGGGAGGCATGGCCCTGGGGTCCCACGAATTTGCTGGGGAATCTCGTTTTTCTTCTTAAGACTTTTGGGACATGGTTTGACTCCCGAACATCACCGACGCGTCTCCTGCTG 3'a) 5' TTCCGGAAGAAGCTTATACGG 3'b) 5' CTGTGTTCACCTAATATTCCT 3'c) 5' CAGCAGGAGACGCGTCGGTGA 3'd) 5' AGGAATATTAGTATAATCCAC 3'e) 5' GACGCGTCGGTGATGTTCGGG 3’f) 5'…arrow_forwardPretty sure I did it wrongarrow_forward
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