Basics Of Engineering Economy
2nd Edition
ISBN: 9780073376356
Author: Leland Blank, Anthony Tarquin
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Question
Chapter 5, Problem 15P
a:
To determine
Selection of the project.
b:
To determine
Calculate the present worth.
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An environmental engineer wants to evaluate three different methods for disposing of nonhazardous chemical waste: land application,
fluidized-bed incineration, and private disposal contract. Use the estimates below to help her determine which has the least cost at /=
13% per year on the basis of an annual worth evaluation.
First Cost
AOC per Year
Salvage Value
Life
Land
$-145.000
$-91,000
$23,000
4 years
Incineration
$-910,000
$-50,000
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6 years
The environmental engineer selects a✔(Click to select)
private disposal contract
land application
fluidized-bed incineration
Contract.
0
$-132,000
0
2 years
A chemical processing corporation is considering
three methods to dispose of a nonhazardous
chemical sludge: land application, fluidized-bed
incineration, and private disposal contract. The
estimates for each method are shown.
Determine which has the least cost on the basis of a
present worth comparison at 10% per year
for the following scenarios (You may assume a
planning horizon of 6 years.):
(a) The estimates are as shown in the table above.
b) If land application and incineration costs are as
shown in the table, but the annual cost of the
contract award cost increase by 20% every time the
contract is renewed (every 2 years).
Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with low friction properties for creating custom bearings for 3-D printers.
The estimates associated with each alternative are shown below. Using a MARR of 16% per year, which alternative has the better present worth and what is that
value (select the closest value)?
Method
First Cost
AOC, per Year
Salvage Value
Life
DDM
$170,000
$65,000
$4,000
2 years
LS
$350,000
$40,000
$29,000
4 years
DDM with a PW--$473,000
LS with a PW --$445,900
LS with a PW --$222,055
DDM with a PW--$109,300
Chapter 5 Solutions
Basics Of Engineering Economy
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Two machines with the following cost estimates are...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Estimates have been presented to Holly Farms,...Ch. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - A major repair on the suspension system of Janes...Ch. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32APQCh. 5 - Prob. 33APQCh. 5 - Prob. 34APQCh. 5 - Prob. 35APQCh. 5 - Prob. 36APQCh. 5 - The AW values of three revenue alternatives are ...Ch. 5 - Prob. 38APQCh. 5 - Prob. 39APQCh. 5 - Use an interest rate of 10% per year. The...Ch. 5 - Prob. 41APQCh. 5 - Prob. 42APQ
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- Consider two air-conditioning systems with the estimates below. (a) Use AW analysis to determine the sensitivity of the economic decision to MARR values of 4%, 6%, and 8% per year. (b) Develop the spreadsheet functions that will display the six AW values. System 1 2 First cost, $ −10,000 −17,000 AOC, $ per year −600 −150 Salvage value, $ −100 −300 New compressor and motor cost at midlife, $ −1,750 −3,000 Life, years 8 12arrow_forwardEvaluate a combined cycle power plant on the basis of the PW method when the MARR is 12% per year. Pertinent cost data are as follows : Power Plant (thousands of $) Investment cost $13,000 Useful life 15 years Market value (EOY 15) $3,000 Annual operating expenses $1,000 Overhaul cost—end of 5th year $200 Overhaul cost—end of 10th year $550 USING FUTURE WORTH (FW)arrow_forwardFor the cash flows shown, determine the incremental cash flow between machines B and A (a) in year 0, (b) in year 3, and (c) in year 6. Machine A B First cost, $ −15,000 −25,000 AOC, $ per year −1,600 −400 Salvage value, $ 3,000 6,000 Life, years 3 6arrow_forward
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