Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 43, Problem 4P
(a)
To determine
The de Broglie wavelength of the alpha particle and its comparison with distance of closest approach
(b)
To determine
The reason behind treating alpha particle as a particle.
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Chapter 43 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 43.1 - Prob. 43.1QQCh. 43.5 - Prob. 43.3QQCh. 43.5 - Which of the following is the correct daughter...Ch. 43.8 - When a nucleus undergoes fission, the two daughter...Ch. 43.8 - Prob. 43.6QQCh. 43.10 - Prob. 43.7QQCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4P
Ch. 43 - Prob. 5PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 13PCh. 43 - Prob. 15PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Enter the correct nuclide symbol in each open tan...Ch. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 35PCh. 43 - Prob. 37PCh. 43 - Prob. 39PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 44PCh. 43 - Prob. 45APCh. 43 - Prob. 46APCh. 43 - Prob. 47APCh. 43 - Prob. 48APCh. 43 - Prob. 49APCh. 43 - Prob. 50APCh. 43 - Prob. 51APCh. 43 - Prob. 52APCh. 43 - As part of his discovery of the neutron in 1932,...Ch. 43 - Prob. 55APCh. 43 - Prob. 56APCh. 43 - Prob. 58APCh. 43 - Prob. 59APCh. 43 - Prob. 60APCh. 43 - Prob. 62APCh. 43 - Prob. 63APCh. 43 - Prob. 64APCh. 43 - Prob. 65APCh. 43 - Prob. 66CP
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- Alpha particles of energy 8.4 MeV are incident on a silver foil of thickness 6.5 x 10-6 m. For a certain value of the impact parameter, the alpha particles lose exactly half their incident kinetic energy when they reach their minimum separation from the nucleus. Find the minimum separation, the impact parameter, and the scattering angle.arrow_forwardWhen a nucleus decays, the daughter nucleus can be in an excited state. The 93/43Tc nucleus (molar mass 92.910 2 g/mol) in the ground state decays by electron capture and e+ emission to energy levels of the daughter (molar mass 92.906 8 g/mol in the ground state) at 2.44 MeV, 2.03 MeV, 1.48 MeV, and 1.35 MeV. (a) Identify the daughter nuclide. (b) To which of the listed levels of the daughter are electron capture and e+ decay of 93/43Tc allowed?arrow_forwardWhat is the ratio of the velocity of a 5.00-MeV β ray to that of an α particle with the same kinetic energy? This should confirm that β s travel much faster than α s even when relativity is taken into consideration.arrow_forward
- In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 80, when an α-particle of 8 MeV energy impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubled?arrow_forwardWhat fraction of 5-MeV alpha particles will be scattered through an angle greater than 8° from a gold foil (Z=79, density = 19.3 g/cm^3) of thickness of 10^-8m?arrow_forwardOutside the nucleus, the neutron itself is radioactive and decays into a proton, an electron, and an antineutrino. The half-life of a neutron (mass = 1.675 × 10-27 kg) outside the nucleus is 10.4 min. On average, over what distance x would a beam of 3.14-eV neutrons travel before the number of neutrons decreased to 75.0% of its initial value? Ignore relativistic effects. X =arrow_forward
- A 5 MeV α particle approach a gold nucleus with an impact parameter of 2.6 ×10−13 meter. Through what angle will it be scattered.arrow_forwardA sample of Co (atomic mass= 59.933820u) undergoes ß decay emitting electrons with maximum kinetic energy 0.31 MeV. If the ground state mass of the Ni atom is 59.930788u, then calculate the excitation energy of the state to which the decay occurs.arrow_forwardQ# 4 (a) A beam of 8.3 MeV alpha particles is directed at an aluminum foil. It is found that the Rutherford scattering formula ceases to be obeyed at scattering angles exceeding about 60°. If the alpha-particle radius is assumed small enough to neglect here, find the radius of the aluminum nucleus.arrow_forward
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