Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 42, Problem 35P
To determine
The ratio of forward current to reverse current for the diode.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
If the diode for the given circuit below is a Silicon
diode, how much is the maximum positive
voltage (taken at the series connection of the
diode and the battery)?
R1
1
V1
1kQ
D1
7.5V
Vout
1kHz
4
0°
V2
I 3.6V
Answer:
A pn junction diode and a Schottky diode have equal cross-sectional areas and have forward-bias currents of 0.5 mA. The reverse-saturation current of the Schottky diode is The difference in forward-bias voltages between the two diodes is 0.30 V. Determine the reverse-saturation current of the pn junction diode.
A silicon diode has a current of 2.5 mA at a forward voltage of 0.6 V at room
temperature (300 K). At this current, the diode has the ideality factor of ŋ = 1.
Calculate the diode reverse saturation current.
Chapter 42 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 42.1 - For each of the following atoms or molecules,...Ch. 42.2 - Prob. 42.2QQCh. 42.2 - Prob. 42.3QQCh. 42 - Prob. 1PCh. 42 - Prob. 2PCh. 42 - Prob. 3PCh. 42 - Prob. 4PCh. 42 - Prob. 5PCh. 42 - The photon frequency that would be absorbed by the...Ch. 42 - Prob. 8P
Ch. 42 - Prob. 9PCh. 42 - Prob. 10PCh. 42 - (a) In an HCl molecule, take the Cl atom to be the...Ch. 42 - Prob. 12PCh. 42 - Prob. 13PCh. 42 - Prob. 14PCh. 42 - Prob. 15PCh. 42 - Prob. 16PCh. 42 - Prob. 17PCh. 42 - Prob. 19PCh. 42 - Prob. 21PCh. 42 - Prob. 22PCh. 42 - Prob. 23PCh. 42 - Prob. 24PCh. 42 - Prob. 25PCh. 42 - Prob. 26PCh. 42 - Prob. 27PCh. 42 - Prob. 28PCh. 42 - Prob. 29PCh. 42 - Prob. 30PCh. 42 - Prob. 32PCh. 42 - Prob. 33PCh. 42 - Prob. 35PCh. 42 - Prob. 36APCh. 42 - Prob. 37APCh. 42 - Prob. 39APCh. 42 - Prob. 40APCh. 42 - As an alternative to Equation 42.1, another useful...
Knowledge Booster
Similar questions
- An abrupt silicon pn junction at zero bias has dopant concentrations of Nd = 5 X 1017 cm 3 and N₂ = 1 X 1017 cm-3 at T = a 300K. Determine the peak electric field for this junction for a reverse voltage of 5 V. Emax = O Emax O Emax 3.88 X 105 V/cm Emax 3.21 X 105 V/cm Emax = 1.70 X 105 V/cm 1.35 X 105 V/cm =arrow_forwardA germanium diode is operated at a junction temperature of 27 °C. For a forward current of 10 mA, V is found to be 0.3 V. (a) If V = 0.4 V, find the forward current. (b) Find the reverse saturation current.arrow_forwardTwo diodes are connected in parallel as shown below: p(0.c.) = 0.15 p (s.c.) = 0.25 A diode may fail in one of the two ways: by short-circuiting or by open-circuiting. What is the probability that the two-diode arrangement will work as a diode?arrow_forward
- The sensitivity of a diode thermometer depends on how much the voltage changes for a given temperature change, with the current remaining constant. What is the sensitivity for this diode thermometer, operated at 100 mA, for a temperature change from 25°C to 150°C? (a) +0.2 mV/°C; (b) +2.0 mV/°C; (c) -0.2 mV/°C; (d) -2.0 mV/°C.arrow_forwardDiodes are essentially one-way valves. They carry current in one direction, but block current in the other. In addition, in the forward conduction mode, the voltage must go above a threshold before significant conduction occurs. A 12.0V stabilized power supply is required to be produced from a 24V DC power supply input source. The maximum power rating Pz of the Zener diode is 4w V. + 'd R. With the loop equation, Vs = Vd + Vr = Vd + I*R Using the Zener regulator circuit calculate: a) The maximum DC current flowing through the Zener diode b) The minimum value of the resistor. c) If the whole process took 15seconds to complete what would be the energy released in the circuit? d) What would happen if the supply voltage is turned off in the circuit?arrow_forwardQ/ A Germanium p-n junction diode has a reverse saturation current of 3.97 x 10-19A at room temperature. The diode is forward-biased with a voltage source of 1 V. Calculate the dynamic resistance of the Ge diode at room temperature.arrow_forward
- 1.0 Biased PN Junctions Consider two PN diodes, A and B as depicted below. Suppose the junction area for each diode is 1.0 x10-8 cm² (1 square-micron) P-doped N-doped N = 1016 1/ cm3 Ng = 1017 1/cm³ X, *po Vo в P-doped Na = 1018 1/cm3 N-doped Ng = 1017 1/cm3 Х ро Xno V. a) At VD =0 Volts, which diode has the wider total depletion region width (value (in microns) and what is it? b) At Vp =0 Volts, in which diode the magnitude of the maximum electric field in the depletion region is the largest and what is its value (in V/cm)? c) Under a reverse bias Vp <0, which diode will breakdown first (i.e. at a smaller magnitude of the negative bias).arrow_forwardConsider a palladium Schottky diode at T = = 300 K formed on n-type silicon doped at N₁ = 5 X 1018 cm-³. Determine the Nd electric field at the metal junction for VR = 2 V. Emax = 2.18 X 106 V/cm O Emax = 1.74 X 106 V/cm Emax = 3.11 X 106 V/cm Emax = 6.00 X 106 V/cmarrow_forwardWhen the forward bias voltage of a diode is changed form 0.6V to 0.7V, the current changes form 5 mA to 15 mA. Then its forward bias resistance is A. 0.01 N B 10 0 Qo.1Aarrow_forward
- In a p-n junction diode, the current I can be expressed as eV 1= 1, exp ( 2k„T where I, is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, køis the Boltzmann constant (8.6x10- eV/K) and T is the absolute temperature. If for a given diode I, = 5 x 10-12 A and T = 300 K, then (a) What will be the forward current at a forward voltage of 0.6 V?arrow_forwardIn a Si semiconductor sample of 200 am length at 600 K the hole concentration as a' function of the sample length follows a quadratic relation of the form p (x) = 1 x1015x, at equilibrium the value of the electric field at 160 jum will be: O 1.935 V/cm O 3.250 V/cm O 5805 V/cm O 55.56 V/cm O 6.450 V/cmarrow_forward= Consider a silicon pn junction diode at T 300K. The reverse saturation current is ls 10-14 A and the ideality factor n = 1. Determine the diode current for a diode voltage of VD = 0.685 V and use that to determine the DC and AC resistance of the diode. RDC = 307 Q2 = rac =7Ω RDC = 224 22 rac 8 Ω RDC = 115 Q2 = rac = 40 RDC = 36 Q rac = 10arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning