Consider the following force vectors: A =-3î + ĵ + 2k (N) B = 2î – ĵ – k (N) 1. Vectors Á, B , and C maintain a body in equilibrium. What is vector C (in unit vector form)? Answer 1: 2. Evaluate: Bx A - (B. A)

1 2 B → ✰ S 1 4 https://mapleton.instructure.com/courses/16703/assignments/300550 1 point A 1kg flower is pushed by a force of 1N. How fast (in m/s2)does it accelerate? Type your answer... A Submit For these questions, assume that the acceleration due to gravity (g) on Earth is 10 m/s². Also assume that there is no friction or air resistance acting on any of these systems. E 1 point A 23kg statue sits on a table. What is the statue's weight in Newtons? Type your answer... 2 1 point A speeding car is pulled over by a police cruiser. If the car started at 60 m/s and stopped in 20 seconds. If the car has a mass of 1,800Kg, how much force (in Newtons) was exerted by the car's breaks? Type your answer... 3 1 point A moose pushes a 10kg rock, accelerating it from rest to 10m/s in 1 second (This is an acceleration of 10m/s2). What was the applied force in Newtons? Type your answer... Return 4

Two forces act on a 2.55 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (4.05î – 3.30j) m. Write th second force in unit vector notation. (Enter your answer in kg • m/s?. Assume the gravitational force acts in the -j direction.)

A force is specified by the vector F = (130i + 100j - 200k) N. Calculate the angles made by F with the positive x-, y-, and z-axes. Answers: 0x = Oy= 0 || 0₂ = D i i

A car of mass m = 1100 kg is traveling down a θ = 14 degree incline. When the car's speed is v0 = 13 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45. Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end

ΣF-a W = Fd parallel KE =-mv² v =v, +at v² – v? = 2a(x-x,) Fr = H,FN w = mg E, +W = E, GPE = mgh EPE = - kx? A C D B 11. A small block, with a mass of 4 kg, starts from rest at the top of the apparatus shown above. It then slides without friction down the incline, across the first level section, around the loop and then onto the final level section on the right. It then collides with a spring and compresses it, which momentarily brings the block to a stop. The maximum height of the incline is 5 m, the radius of the loop is 1.0 m and the spring constant is 120 N/m.

In space v = (-5) ux + (-3) uy + (4) uz [m / s] speed moving q = 4 [C] load,E = (5) ux + (10) uy + (7) uz and,B= (8) ux+ (9) uy+ (4) uzwhat is the x component of the total force acting on this load [N]?

A courier is delivering a 5 kg package to an office high in a tall building. (a)  What upwards force does the courier apply to the pack- age when carrying it horizontally at a constant velocity of 2 m s−1 into the building? (b)  The courier uses the elevator to reach the office. While the elevator (containing the courier who is holding the package) is accelerating upwards at 0.11 m s−2 what upwards force is the courier applying to the package? (c)  When the elevator is traveling upwards at a constant speed of 6 m s−1 what upwards force does the courier apply to the package? (d)  In order to stop at the correct floor the elevator accelerates downwards (decelerates) at a rate of 0.20 m s−2. What is the upwards force the courier applies to the package during the deceleration?

Let's consider the system given in Figure 2. The end of a flexible spring with spring constant k is attached to the wall and the other end to a block of mass m. There is no friction between the block and the inclined plane. When the spring is at its natural length, the block is first decelerated. The angle of inclination of the inclined plane is given as ß. a) What is the acceleration of the blog when the spring is extended by x?